E -Library Management System
In this article, we will discuss the approach to create an E-Library Management System where the user has the following options:
- Add book information.
- Display book information.
- To list all books of a given author.
- To list the count of books in the library.
Functionalities Required:
- If the user tries to add a book then the user must have to provide the below specific Information about the book as:
- Enter Book Name:
- Enter Author Name:
- Enter Pages:
- Enter Price:
- When the user tries to display all books of a particular author then the user must have to enter the name of the author:
- Enter the author name:
- The E-Library management System must be also capable of counting all the books available in the library.
Below is the program to implement the E-Library Management System:
C
// C program for the E-library // Management System #include <stdio.h> #include <stdlib.h> #include <string.h> // Create Structure of Library struct library { char book_name[20]; char author[20]; int pages; float price; }; // Driver Code int main() { // Create a instance struct library lib[100]; char ar_nm[30], bk_nm[30]; // Keep the track of the number of // of books available in the library int i, input, count; i = input = count = 0; // Iterate the loop while (input != 5) { printf ( "\n\n********######" "WELCOME TO E-LIBRARY " "#####********\n" ); printf ( "\n\n1. Add book infor" "mation\n2. Display " "book information\n" ); printf ( "3. List all books of " "given author\n" ); printf ( "4. List the count of book" "s in the library\n" ); printf ( "5. Exit" ); // Enter the book details printf ( "\n\nEnter one of " "the above: " ); scanf ( "%d" , &input); // Process the input switch (input) { // Add book case 1: printf ( "Enter book name = " ); scanf ( "%s" , lib[i].book_name); printf ( "Enter author name = " ); scanf ( "%s" , lib[i].author); printf ( "Enter pages = " ); scanf ( "%d" , &lib[i].pages); printf ( "Enter price = " ); scanf ( "%f" , &lib[i].price); count++; break ; // Print book information case 2: printf ( "you have entered" " the following " "information\n" ); for (i = 0; i < count; i++) { printf ( "book name = %s" , lib[i].book_name); printf ( "\t author name = %s" , lib[i].author); printf ( "\t pages = %d" , lib[i].pages); printf ( "\t price = %f" , lib[i].price); } break ; // Take the author name as input case 3: printf ( "Enter author name : " ); scanf ( "%s" , ar_nm); for (i = 0; i < count; i++) { if ( strcmp (ar_nm, lib[i].author) == 0) printf ( "%s %s %d %f" , lib[i].book_name, lib[i].author, lib[i].pages, lib[i].price); } break ; // Print total count case 4: printf ( "\n No of books in " "brary : %d" , count); break ; case 5: exit (0); } } return 0; } |
Output: