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Answer :

`C^(12)=7.68MeV` <BR> `N^(14)=7.68MeV` <br> `O^(16)=7.68MeV` <br> Stability is same. Solution :

`a. C^(12),` proton `=6`, neutron `=6` <br> `Delta_(m)=(6xx1.0078+6xx1.0087)-12` <br> `=(6.0468+6.0522)-12` <br> `=12.099-12=0.099m _(u)` <br> `BE` per nucleus <br> `=(0.099xx931)/(12)MeV=7.68MeV` <br> `b.` `N^(14), proton =7`, neutron `=7` <br> `Delta m=(7xx1.0078+7xx1.0087)-14` <br> `=(7.0546+7.0609)-14` <br> `=14.1155-14=0.1155m_(u)` <br> `BE` per nucleus <br> `=(0.1155xx931)/(14)MeV=7.68m_(u)` <br> `c.` `O^(16),` proton `=8` neutron `=8` <br> `Delta_(m)=(8xx1.0078+8xx1.0087)-16` <br> `=(8.0624+8.0696)-16` <br> `=0.132m_(u)` <br> `BE` per nucleus <br> `=(0.132xx931)/(16)MeV=7.68MeV`