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Divide large number represented as string

  • Difficulty Level : Medium
  • Last Updated : 29 Apr, 2021

Given a large number (represented as a string) which has to divide by another number (represented as int data type). The large number can be very large which does not even fit in long long in C++. The task is to find the division of these numbers.
Examples: 
 

Input : number  = 1260257
        divisor = 37
Output : 34061
(See below diagram)

Input : number  = 12313413534672234
        divisor = 754
Output : 16330787181262

Input : number  = 1248163264128256512
        divisor = 125
Output : 9985306113026052

 

We have already discussed Multiply Large Numbers represented as Strings.
We use basic school mathematics as shown in below example.
 

division

As the dividend and result can be very large we store them in string. We first take digits which are divisible by number. After this take each digit and store result in string. 
 



C++




// C++ program to implement division with large
// number
#include <bits/stdc++.h>
using namespace std;
 
// A function to perform division of large numbers
string longDivision(string number, int divisor)
{
    // As result can be very large store it in string
    string ans;
 
    // Find prefix of number that is larger
    // than divisor.
    int idx = 0;
    int temp = number[idx] - '0';
    while (temp < divisor)
        temp = temp * 10 + (number[++idx] - '0');
 
    // Repeatedly divide divisor with temp. After
    // every division, update temp to include one
    // more digit.
    while (number.size() > idx) {
        // Store result in answer i.e. temp / divisor
        ans += (temp / divisor) + '0';
 
        // Take next digit of number
        temp = (temp % divisor) * 10 + number[++idx] - '0';
    }
 
    // If divisor is greater than number
    if (ans.length() == 0)
        return "0";
 
    // else return ans
    return ans;
}
 
// Driver program to test longDivison()
int main()
{
    string number = "1248163264128256512";
    int divisor = 125;
    cout << longDivision(number, divisor);
    return 0;
}

Java




// Java program to implement division
// with large number
class GFG {
    public static String longDivision(
        String number,
        int divisor)
    {
 
        // As result can be very
        // large store it in string
        // but since we need to modify
        // it very often so using
        // string builder
        StringBuilder result
            = new StringBuilder();
 
        // We will be iterating
        // the dividend so converting
        // it to char array
        char[] dividend
            = number.toCharArray();
 
        // Initially the carry
        // would be zero
        int carry = 0;
 
        // Iterate the dividend
        for (
            int i = 0;
            i < dividend.length; i++) {
            // Prepare the number to
            // be divided
            int x
                = carry * 10
                  + Character.getNumericValue(
                        dividend[i]);
 
            // Append the result with
            // partial quotient
            result.append(x / divisor);
 
            // Prepare the carry for
            // the next Iteration
            carry = x % divisor;
        }
 
        // Remove any leading zeros
        for (
            int i = 0;
            i < result.length(); i++) {
            if (
                result.charAt(i) != '0') {
                // Return the result
                return result.substring(i);
            }
        }
        // Return empty string
        // if number is empty
        return "";
    }
 
    // Driver code
    public static void main(
        String[] args)
    {
        String number
            = "1248163264128256512";
        int divisor = 125;
        System.out.println(
            longDivision(
                number, divisor));
    }
}
 
// This code is contributed by Saurabh321Gupta.

Python3




# Python3 program to implement division
# with large number
import math
 
# A function to perform division of
# large numbers
def longDivision(number, divisor):
 
    # As result can be very large
    # store it in string
    ans = "";
     
    # Find prefix of number that
    # is larger than divisor.
    idx = 0;
    temp = ord(number[idx]) - ord('0');
    while (temp < divisor):
        temp = (temp * 10 + ord(number[idx + 1]) -
                            ord('0'));
        idx += 1;
     
    idx += 1;
 
    # Repeatedly divide divisor with temp.
    # After every division, update temp to
    # include one more digit.
    while ((len(number)) > idx):
         
        # Store result in answer i.e. temp / divisor
        ans += chr(math.floor(temp // divisor) + ord('0'));
         
        # Take next digit of number
        temp = ((temp % divisor) * 10 + ord(number[idx]) -
                                        ord('0'));
        idx += 1;
 
    ans += chr(math.floor(temp // divisor) + ord('0'));
     
    # If divisor is greater than number
    if (len(ans) == 0):
        return "0";
     
    # else return ans
    return ans;
 
# Driver Code
number = "1248163264128256512";
divisor = 125;
print(longDivision(number, divisor));
     
# This code is contributed by mits

C#




// C# program to implement division
// with large number
using System;
 
class GFG {
 
    // A function to perform division of large numbers
    static string longDivision(string number, int divisor)
    {
        // As result can be very large store it in string
        string ans = "";
 
        // Find prefix of number that is larger
        // than divisor.
        int idx = 0;
        int temp = (int)(number[idx] - '0');
        while (temp < divisor) {
            temp = temp * 10 + (int)(number[idx + 1] - '0');
            idx++;
        }
        ++idx;
 
        // Repeatedly divide divisor with temp. After
        // every division, update temp to include one
        // more digit.
        while (number.Length > idx) {
            // Store result in answer i.e. temp / divisor
            ans += (char)(temp / divisor + '0');
 
            // Take next digit of number
            temp = (temp % divisor) * 10 + (int)(number[idx] - '0');
            idx++;
        }
        ans += (char)(temp / divisor + '0');
 
        // If divisor is greater than number
        if (ans.Length == 0)
            return "0";
 
        // else return ans
        return ans;
    }
 
    // Driver code
    static void Main()
    {
        string number = "1248163264128256512";
        int divisor = 125;
        Console.WriteLine(longDivision(number, divisor));
    }
}
 
// This code is contributed by mits

PHP




<?php
// PHP program to implement division
// with large number
 
// A function to perform division of
// large numbers
function longDivision($number, $divisor)
{
    // As result can be very large
    // store it in string
    $ans = "";
     
    // Find prefix of number that is
    // larger than divisor.
    $idx = 0;
    $temp = ord($number[$idx]) - 48;
    while ($temp < $divisor)
        $temp = $temp * 10 +
            ord($number[++$idx]) - 48;
     
    // Repeatedly divide divisor with temp.
    // After every division, update temp to
    // include one more digit.
    ++$idx;
    while (strlen($number) > $idx)
    {
        // Store result in answer i.e. temp / divisor
        $ans .= chr((int)($temp / $divisor) + 48);
         
        // Take next digit of number
        $temp = ($temp % $divisor) * 10 +
             ord($number[$idx]) - 48;
        ++$idx;
    }
    $ans .= chr((int)($temp / $divisor) + 48);
     
    // If divisor is greater than number
    if (strlen($ans) == 0)
        return "0";
     
    // else return ans
    return $ans;
}
 
// Driver Code
$number = "1248163264128256512";
$divisor = 125;
print(longDivision($number, $divisor));
 
// This code is contributed by mits
?>

Javascript




<script>
 
// Javascript program to implement division
// with large number
     
     
    function longDivision(number,divisor)
    {
        // As result can be very
        // large store it in string
        // but since we need to modify
        // it very often so using
        // string builder
        let ans="";
   
        // We will be iterating
        // the dividend so converting
        // it to char array
   
        // Initially the carry
        // would be zero
        let idx = 0;
          let temp=number[idx]-'0';
        while (temp < divisor)
        {
            temp = (temp * 10 +
            (number[idx + 1]).charCodeAt(0) -
                   ('0').charCodeAt(0));
            idx += 1;
        }
        idx += 1;
         
        while(number.length>idx)
        {
            // Store result in answer i.e. temp / divisor
            ans += String.fromCharCode
            (Math.floor(temp / divisor) +
            ('0').charCodeAt(0));
           
            // Take next digit of number
            temp = ((temp % divisor) * 10 +
            (number[idx]).charCodeAt(0) -
                  ('0').charCodeAt(0));
            idx += 1;
        }
         
        ans += String.fromCharCode
        (Math.floor(temp / divisor) +
        ('0').charCodeAt(0));
         
        //If divisor is greater than number
        if(ans.length==0)
            return "0";
        //else return ans
        return ans;
    }
     
    // Driver Code
    let number = "1248163264128256512";
    let divisor = 125;
    document.write(longDivision(
                number, divisor));
     
    // This code is contributed
    // by avanitrachhadiya2155
     
</script>

Output:

9985306113026052

This article is contributed by nuclode. If you like GeeksforGeeks and would like to contribute, you can also write an article using contribute.geeksforgeeks.org or mail your article to contribute@geeksforgeeks.org. See your article appearing on the GeeksforGeeks main page and help other Geeks.
Please write comments if you find anything incorrect, or you want to share more information about the topic discussed above.
 

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