# Divide every element of one array by other array elements

Given two arrays and the operation to be performed is that the every element of a[] should be divided by all the element of b[] and their floor value has to be calculated.

Examples :

Input : a[] = {5, 100, 8}, b[] = {2, 3}
Output : 0 16 1
Explanation :
Size of a[] is 3.
Size of b[] is 2.
Now 5 has to be divided by the elements of array b[]
i.e. 5 is divided by 2, then the quotient obtained
is divided by 3 and the floor value of this is
calculated. The same process is repeated for the other
array elements.

## Recommended: Please try your approach on {IDE} first, before moving on to the solution.

First Approach : This solution is of complexity O(n * m) where size of a[] is n and size of array b[] is m. In this solution we fix the elements of array a[] and iterate it with the elements of array b[].

Second Approach : In this method we have used simple maths. We first find product of array B and then divide it by each array element of a[]
The complexity of this solution is O(n).

## C++

 // CPP program to find quotient of array // elements #include using namespace std;    // Function to calculate the quotient // of every element of the array void calculate(int a[], int b[], int n, int m) {     int mul = 1;        // Calculate the product of all elements     for (int i = 0 ; i < m ; i++)         if (b[i] != 0)             mul = mul * b[i];        // To calculate the quotient of every     // array element     for (int i = 0 ; i < n ; i++)     {         int x = floor(a[i] / mul);         cout << x << " ";     } }    // Driver code int main() {     int a[] = {5 , 100 , 8};     int b[] = {2 , 3};     int n = sizeof(a)/sizeof(a[0]);     int m = sizeof(b)/sizeof(b[0]);     calculate(a, b, n, m);     return 0; }

## Java

 // Java program to find quotient of array // elements    import java.io.*;    class GFG {        // Function to calculate the quotient     // of every element of the array     static void calculate(int a[], int b[],                                  int n, int m)     {                    int mul = 1;            // Calculate the product of all          // elements         for (int i = 0; i < m; i++)             if (b[i] != 0)                 mul = mul * b[i];            // To calculate the quotient of every         // array element         for (int i = 0; i < n; i++) {             int x = (int)Math.floor(a[i] / mul);             System.out.print(x + " ");         }     }        public static void main(String[] args)     {         int a[] = { 5, 100, 8 };         int b[] = { 2, 3 };         int n = a.length;         int m = b.length;                    calculate(a, b, n, m);     } }    // This code is contributed by Ajit.

## Python3

 # Python3 program to find  # quotient of arrayelements import math    # Function to calculate the quotient # of every element of the array def calculate(a, b, n, m):                mul = 1        # Calculate the product      # of all elements     for i in range(m):         if (b[i] != 0):             mul = mul * b[i]        # To calculate the quotient      # of every array element     for i in range(n):         x = math.floor(a[i] / mul)         print(x, end = " ")               # Driver code a = [ 5, 100, 8 ] b = [ 2, 3 ] n = len(a) m = len(b)            calculate(a, b, n, m)    # This code is contributed by Anant Agarwal.

## C#

 // C# program to find quotient  // of array elements using System;    class GFG {         // Function to calculate the quotient     // of every element of the array     static void calculate(int []a, int []b,                                int n, int m)     {         int mul = 1;             // Calculate the product of all          // elements         for (int i = 0; i < m; i++)             if (b[i] != 0)                 mul = mul * b[i];             // To calculate the quotient of every         // array element         for (int i = 0; i < n; i++) {             int x = (int)Math.Floor((double)(a[i] / mul));             Console.Write(x + " ");         }     }            // Driver code     public static void Main()     {         int []a = { 5, 100, 8 };         int []b = { 2, 3 };         int n = a.Length;         int m = b.Length;                     calculate(a, b, n, m);     } }     // This code is contributed by Anant Agarwal.

## PHP



Output :

0 16 1

My Personal Notes arrow_drop_up

Check out this Author's contributed articles.

If you like GeeksforGeeks and would like to contribute, you can also write an article using contribute.geeksforgeeks.org or mail your article to contribute@geeksforgeeks.org. See your article appearing on the GeeksforGeeks main page and help other Geeks.

Please Improve this article if you find anything incorrect by clicking on the "Improve Article" button below.

Improved By : vt_m