Divide a string in N equal parts

Difficulty Level: Rookie

Question:
Write a program to print N equal parts of a given string.

Solution:
1) Get the size of the string using string function strlen() (present in string.h)
2) Get size of a part.

  
     part_size = string_length/n

3) Loop through the input string. In loop, if index becomes multiple of part_size then put a part separator(“\n”)

Implementation:

C++

// C++ program to divide a string 
// in n equal parts 
#include<iostream> 
#include<string.h> 
  
using namespace std; 
  
class gfg 
{ 
  
// Function to print n equal parts of str 
public:  
void divideString(char str[], int n) 
{ 
      
    int str_size = strlen(str); 
    int i; 
    int part_size; 
  
    // Check if string can be divided in 
    // n equal parts 
    if (str_size % n != 0) 
    { 
        cout<<"Invalid Input: String size"; 
        cout<<" is not divisible by n"; 
        return; 
    } 
  
    // Calculate the size of parts to 
    // find the division points 
    part_size = str_size / n; 
    for (i = 0; i< str_size; i++) 
    { 
        if (i % part_size == 0) 
            cout<<endl;  
        cout<< str[i]; 
    } 
} 
}; 
  
// Driver code 
int main() 
{ 
    gfg g; 
      
    // length od string is 28 
    char str[] = "a_simple_divide_string_quest"; 
  
    // Print 4 equal parts of the string  
    g.divideString(str, 4); 
    return 0; 
} 
  
// This code is contributed by SoM15242 

C

// C program to divide a string 
// in n equal parts 
#include<stdio.h> 
#include<string.h> 
  
// Function to print n equal parts of str 
void divideString(char *str, int n) 
{ 
int str_size = strlen(str); 
int i; 
int part_size; 
  
// Check if string can be divided in 
// n equal parts 
if (str_size % n != 0) 
{ 
    printf("Invalid Input: String size"); 
    printf(" is not divisible by n"); 
    return; 
} 
  
// Calculate the size of parts to 
// find the division points 
part_size = str_size / n; 
for (i = 0; i< str_size; i++) 
{ 
    if (i % part_size == 0) 
        printf("\n");  
    printf("%c", str[i]); 
} 
} 
  
int main() 
{ 
    // length od string is 28 
    char *str = "a_simple_divide_string_quest"; 
  
    // Print 4 equal parts of the string  
    divideString(str, 4); 
  
    getchar(); 
    return 0; 
} 

Java

// Java program to divide a string  
// in n equal parts 
  
class GFG  
{ 
    // Method to print n equal parts of str 
    static void divideString(String str, int n) 
    { 
    int str_size = str.length(); 
    int part_size; 
      
    // Check if string can be divided in 
    // n equal parts  
    if (str_size % n != 0) 
    { 
        System.out.println("Invalid Input: String size" + 
                                "is not divisible by n"); 
        return; 
    } 
      
    // Calculate the size of parts to find  
    // the division points 
    part_size = str_size / n; 
          
    for (int i = 0; i< str_size; i++) 
    { 
        if(i % part_size == 0) 
            System.out.println();  
        System.out.print(str.charAt(i)); 
    } 
    } 
      
    // Driver Code 
    public static void main(String[] args) 
    { 
        // length od string is 28 
        String str = "a_simple_divide_string_quest"; 
      
        // Print 4 equal parts of the string 
        divideString(str, 4); 
    } 
} 

Python

# Python program to print n equal parts of string 
  
# Function to print n equal parts of string 
def divideString(string, n): 
    str_size = len(string) 
  
    # Check if string can be divided in n equal parts 
    if str_size % n != 0: 
        print "Invalid Input: String size is not divisible by n"
        return
  
    # Calculate the size of parts to find the division points 
    part_size = str_size/n 
    k = 0
    for i in string: 
        if k%part_size==0: 
            print "\n", 
        print i, 
        k += 1
  
# Driver program to test the above function 
# Length of string is 28 
string = "a_simple_divide_string_quest"
  
# Print 4 equal parts of the string 
divideString(string, 4) 
  
# This code is contributed by Bhavya Jain 

C#

// C# program to divide a string  
// in n equal parts 
using System; 
  
class GFG { 
      
// Method to print n  
// equal parts of str 
static void divideString(String str, 
                         int n) 
{ 
    int str_size = str.Length; 
    int part_size; 
      
    // Check if string  
    // can be divided in 
    // n equal parts  
    if (str_size % n != 0) 
    { 
        Console.Write("Invalid Input: String size" + 
                      "is not divisible by n"); 
        return; 
    } 
      
    // Calculate the size  
    // of parts to find  
    // the division points 
    part_size = str_size / n; 
          
    for (int i = 0; i< str_size; i++) 
    { 
        if(i % part_size == 0) 
            Console.WriteLine();  
        Console.Write(str[i]); 
    } 
    } 
      
    // Driver Code 
    static void Main()  
    { 
          
        // length od string is 28 
        String str = "a_simple_divide_string_quest"; 
      
        // Print 4 equal parts of the string 
        divideString(str, 4); 
    } 
} 
  
// This code is contributed by Anuj_67 

PHP

<?php 
// PHP program to divide a string 
// in n equal parts 
  
// Function to print n 
// equal parts of str 
function divideString($str, $n) 
{ 
    $str_size = strlen($str); 
    $i; 
    $part_size; 
  
// Check if string can be divided  
// in n equal parts 
if ($str_size % $n != 0) 
{ 
    echo "Invalid Input: String size"; 
    echo " is not divisible by n"; 
    return; 
} 
  
// Calculate the size of parts to 
// find the division point 
$part_size = $str_size / $n; 
for ($i = 0; $i< $str_size; $i++) 
{ 
    if ($i % $part_size == 0) 
        echo "\n";  
    echo $str[$i]; 
} 
} 
  
    // Driver Code 
    // length od string is 28 
    $str = "a_simple_divide_string_quest"; 
  
    // Print 4 equal parts of the string  
    divideString($str, 4); 
  
// This code is contributed by ajit. 
?> 

Output:

a_simpl
e_divid
e_strin
g_quest

In above solution, n equal parts of the string are only printed. If we want individual parts to be stored then we need to allocate part_size + 1 memory for all N parts (1 extra for string termination character ‘\0’), and store the addresses of the parts in an array of character pointers.

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