Divide a string in N equal parts

Difficulty Level: Rookie

Question:
Write a program to print N equal parts of a given string.

Solution:
1) Get the size of the string using string function strlen() (present in string.h)
2) Get size of a part.

  
     part_size = string_length/n

3) Loop through the input string. In loop, if index becomes multiple of part_size then put a part separator(“\n”)

Implementation:

C++

// C++ program to divide a string 
// in n equal parts 
#include<iostream> 
#include<string.h> 
  
using namespace std; 
  
class gfg 
{ 
  
// Function to print n equal parts of str 
public:  
void divideString(char str[], int n) 
{ 
      
    int str_size = strlen(str); 
    int i; 
    int part_size; 
  
    // Check if string can be divided in 
    // n equal parts 
    if (str_size % n != 0) 
    { 
        cout<<"Invalid Input: String size"; 
        cout<<" is not divisible by n"; 
        return; 
    } 
  
    // Calculate the size of parts to 
    // find the division points 
    part_size = str_size / n; 
    for (i = 0; i< str_size; i++) 
    { 
        if (i % part_size == 0) 
            cout<<endl;  
        cout<< str[i]; 
    } 
} 
}; 
  
// Driver code 
int main() 
{ 
    gfg g; 
      
    // length od string is 28 
    char str[] = "a_simple_divide_string_quest"; 
  
    // Print 4 equal parts of the string  
    g.divideString(str, 4); 
    return 0; 
} 
  
// This code is contributed by SoM15242 

C

// C program to divide a string 
// in n equal parts 
#include<stdio.h> 
#include<string.h> 
  
// Function to print n equal parts of str 
void divideString(char *str, int n) 
{ 
int str_size = strlen(str); 
int i; 
int part_size; 
  
// Check if string can be divided in 
// n equal parts 
if (str_size % n != 0) 
{ 
    printf("Invalid Input: String size"); 
    printf(" is not divisible by n"); 
    return; 
} 
  
// Calculate the size of parts to 
// find the division points 
part_size = str_size / n; 
for (i = 0; i< str_size; i++) 
{ 
    if (i % part_size == 0) 
        printf("\n");  
    printf("%c", str[i]); 
} 
} 
  
int main() 
{ 
    // length od string is 28 
    char *str = "a_simple_divide_string_quest"; 
  
    // Print 4 equal parts of the string  
    divideString(str, 4); 
  
    getchar(); 
    return 0; 
} 

Java

// Java program to divide a string  
// in n equal parts 
  
class GFG  
{ 
    // Method to print n equal parts of str 
    static void divideString(String str, int n) 
    { 
    int str_size = str.length(); 
    int part_size; 
      
    // Check if string can be divided in 
    // n equal parts  
    if (str_size % n != 0) 
    { 
        System.out.println("Invalid Input: String size" + 
                                "is not divisible by n"); 
        return; 
    } 
      
    // Calculate the size of parts to find  
    // the division points 
    part_size = str_size / n; 
          
    for (int i = 0; i< str_size; i++) 
    { 
        if(i % part_size == 0) 
            System.out.println();  
        System.out.print(str.charAt(i)); 
    } 
    } 
      
    // Driver Code 
    public static void main(String[] args) 
    { 
        // length od string is 28 
        String str = "a_simple_divide_string_quest"; 
      
        // Print 4 equal parts of the string 
        divideString(str, 4); 
    } 
} 

Python

# Python program to print n equal parts of string 
  
# Function to print n equal parts of string 
def divideString(string, n): 
    str_size = len(string) 
  
    # Check if string can be divided in n equal parts 
    if str_size % n != 0: 
        print "Invalid Input: String size is not divisible by n"
        return
  
    # Calculate the size of parts to find the division points 
    part_size = str_size/n 
    k = 0
    for i in string: 
        if k%part_size==0: 
            print "\n", 
        print i, 
        k += 1
  
# Driver program to test the above function 
# Length of string is 28 
string = "a_simple_divide_string_quest"
  
# Print 4 equal parts of the string 
divideString(string, 4) 
  
# This code is contributed by Bhavya Jain 

C#

// C# program to divide a string  
// in n equal parts 
using System; 
  
class GFG { 
      
// Method to print n  
// equal parts of str 
static void divideString(String str, 
                         int n) 
{ 
    int str_size = str.Length; 
    int part_size; 
      
    // Check if string  
    // can be divided in 
    // n equal parts  
    if (str_size % n != 0) 
    { 
        Console.Write("Invalid Input: String size" + 
                      "is not divisible by n"); 
        return; 
    } 
      
    // Calculate the size  
    // of parts to find  
    // the division points 
    part_size = str_size / n; 
          
    for (int i = 0; i< str_size; i++) 
    { 
        if(i % part_size == 0) 
            Console.WriteLine();  
        Console.Write(str[i]); 
    } 
    } 
      
    // Driver Code 
    static void Main()  
    { 
          
        // length od string is 28 
        String str = "a_simple_divide_string_quest"; 
      
        // Print 4 equal parts of the string 
        divideString(str, 4); 
    } 
} 
  
// This code is contributed by Anuj_67 

PHP

<?php 
// PHP program to divide a string 
// in n equal parts 
  
// Function to print n 
// equal parts of str 
function divideString($str, $n) 
{ 
    $str_size = strlen($str); 
    $i; 
    $part_size; 
  
// Check if string can be divided  
// in n equal parts 
if ($str_size % $n != 0) 
{ 
    echo "Invalid Input: String size"; 
    echo " is not divisible by n"; 
    return; 
} 
  
// Calculate the size of parts to 
// find the division point 
$part_size = $str_size / $n; 
for ($i = 0; $i< $str_size; $i++) 
{ 
    if ($i % $part_size == 0) 
        echo "\n";  
    echo $str[$i]; 
} 
} 
  
    // Driver Code 
    // length od string is 28 
    $str = "a_simple_divide_string_quest"; 
  
    // Print 4 equal parts of the string  
    divideString($str, 4); 
  
// This code is contributed by ajit. 
?> 

Output:

a_simpl
e_divid
e_strin
g_quest

In above solution, n equal parts of the string are only printed. If we want individual parts to be stored then we need to allocate part_size + 1 memory for all N parts (1 extra for string termination character ‘\0’), and store the addresses of the parts in an array of character pointers.

Please write comments if you find anything incorrect, or you want to share more information about the topic discussed above.

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C++

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