Given a numerator and denominator, we have to find their quotient and remainder without using the modulo or division operator. div() function allows us to do the same task easily and efficiently.**div() function : **Returns the integral quotient and remainder of the division of numer by denom ( numer/denom ) as a structure of type div_t, ldiv_t or lldiv_t, which has two members: quot and rem. **Syntax: **

div_t div(int numerator, int denominator); ldiv_t div(long numerator, long denominator); lldiv_t div(long long numerator, long long denominator);

When we use div() function, it returns a structure which contains the quotient and remainder of the parameters. The first parameter passed in a div() function is taken as numerator and the 2nd parameter is taken as denominator.

For int values, the structure returned is div_t. This structure looks like this:

## C++

`typedef` `struct` ` ` `{` ` ` `int` `quot; ` `/* Quotient. */` ` ` `int` `rem; ` `/* Remainder. */` `} ` `div_t` `;` |

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Similarly, for long values, structure ldiv_t is returned and for long long values, structure lldiv_t is returned.

## C++

`ldiv_t` `:` `struct` `ldiv_t` `{` ` ` `long` `quot;` ` ` `long` `rem;` `};` `lldiv_t:` `struct` `lldiv_t {` ` ` `long` `long` `quot;` ` ` `long` `long` `rem;` `};` |

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**Where is it useful ?**

The question is, since we have both % and / operators, why should we use div() function?. Well, in a program where we require both – quotient and remainder, using div() function would be the best choice as it calculates both the values for you at once, moreover, it requires less time as compared to using % and / functions one by one.

While using div() function, *both %operator and using div() will return the same value of remainder, i.e if we’re getting negative value of remainder by using %operator then we will get negative value of remainder using div() function too. Eg, div(-40,3) will give remainder of ‘-1’. *. So, div() function can be efficiently used according to one’s requirement. **What happens when the denominator is 0?**

If any one of the part of this function, i.e. the remainder or the quotient cannot be represented or cannot find a result, then the whole structure shows an **undefined behaviour** . **NOTE :** While using div() function, remember to include cstdlib.h library in your program.

Examples:

Input : div(40, 5) Output :quot = 8 rem = 0 Input :div(53, 8) Output :quot = 6 rem = 5 Input : div(-40,3) Output : quot = -13 , rem = -1

**Implementation:**

## CPP

`// CPP program to illustrate` `// div() function` `#include <iostream>` `#include <cstdlib>` `using` `namespace` `std;` `int` `main()` `{` ` ` `div_t` `result1 = ` `div` `(100, 6);` ` ` `cout << ` `"Quotient of 100/6 = "` `<< ` ` ` `result1.quot << endl;` ` ` `cout << ` `"Remainder of 100/6 = "` `<< ` ` ` `result1.rem << endl;` ` ` `ldiv_t` `result2 = ` `div` `(19237012L,251L);` ` ` `cout << ` `"Quotient of 19237012L/251L = "` `<< ` ` ` `result2.quot << endl;` ` ` `cout << ` `"Remainder of 19237012L/251L = "` `<< ` ` ` `result2.rem << endl;` ` ` `return` `0;` `}` |

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**Output: **

Quotient of 100/6 = 16 Remainder of 100/6 = 4 Quotient of 19237012L/251L = 76641 Remainder of 19237012L/251L = 121

This article is contributed by **Ayush Saxena**. If you like GeeksforGeeks and would like to contribute, you can also write an article using contribute.geeksforgeeks.org or mail your article to contribute@geeksforgeeks.org. See your article appearing on the GeeksforGeeks main page and help other Geeks.

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