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# Distributing all balls without repetition

Given N balls. For convenience, we denote the color of each ball as — lowercase letters. We have to distribute N balls among K people. They will be upset if they get two balls of the same color. We can give any number of balls to people and they won’t be upset even if they do not get any balls, but, we have to distribute all the balls, such that no one will be upset — print YES, if it is possible, and NO, otherwise.

Examples:

```Input : 4 2 // value of N and K
aabb // colors of given balls
Output : YES
We can give 1st and 3rd ball to the first person,
and 2nd and 4th to the second.

Input : 6 3 // value of N and K
aacaab // colors of given balls
Output : NO
We need to give all balls of color a, but one
ball will stay, that's why answer is NO ```

The approach will be really simple. We will create a count array to keep the count of each color that occurs and then we will check if any color occurs more than the number of people we have. If it occurs, we will print NO else YES.

The implementation of the above idea is given below.

## C++

 `// CPP program to find if its possible to``// distribute balls without repetition``#include ``using` `namespace` `std;`` ` `const` `int` `MAX_CHAR = 26;`` ` `// function to find if its possible to``// distribute balls or not``bool` `distributingBalls(``int` `k, ``int` `n, string str)``{   ``    ``// count array to count how many times``    ``// each color has occurred``    ``int` `a[MAX_CHAR] = {0};``    ``for` `(``int` `i = 0; i < n; i++){``         ` `        ``// increasing count of each color``        ``// every time it appears``        ``a[str[i] - ``'a'``]++;  ``    ``}``     ` `    ``for` `(``int` `i = 0; i < MAX_CHAR; i++)   `` ` `        ``// to check if any color appears ``        ``// more than K times if it does ``        ``// we will print NO``        ``if` `(a[i] > k) ``          ``return` `false``;`` ` `    ``return` `true``;``}`` ` `// Driver code``int` `main()``{``    ``long` `long` `int` `n = 6, k = 3;``    ``string str = ``"aacaab"``;`` ` `    ``if` `(distributingBalls(k, n, str))``        ``cout << ``"YES"``;``    ``else``        ``cout << ``"NO"``;``    ``return` `0;``}`

## Java

 `// Java program to find if its possible``// to distribute balls without repetition``import` `java.io.*;`` ` `public` `class` `GFG {`` ` `    ``static` `int` `MAX_CHAR = ``26``;``     ` `    ``// function to find if its possible``    ``// to distribute balls or not``    ``static` `boolean` `distributingBalls(``long` `k,``                         ``long` `n, String str)``    ``{ ``         ` `        ``// count array to count how many``        ``// times each color has occurred``        ``int` `[]a = ``new` `int``[MAX_CHAR];``         ` `        ``for` `(``int` `i = ``0``; i < n; i++)``        ``{``             ` `            ``// increasing count of each``            ``// color every time it appears``            ``a[str.charAt(i) - ``'a'``]++; ``        ``}``         ` `        ``for` `(``int` `i = ``0``; i < MAX_CHAR; i++) ``     ` `            ``// to check if any color appears ``            ``// more than K times if it does ``            ``// we will print NO``            ``if` `(a[i] > k) ``                ``return` `false``;``     ` `        ``return` `true``;``    ``}``     ` `    ``// Driver code``    ``static` `public` `void` `main (String[] args)``    ``{``        ``long` `n = ``6``, k = ``3``;``        ``String str = ``"aacaab"``;``     ` `        ``if` `(distributingBalls(k, n, str))``            ``System.out.println(``"YES"``);``        ``else``            ``System.out.println(``"NO"``);``    ``}``}`` ` `// This code is contributed by vt_m.`

## Python3

 `# Python3 program to find if its possible to ``# distribute balls without repetition`` ` ` ` `MAX_CHAR ``=` `26`` ` `# function to find if its possible to ``# distribute balls or not ``def` `distributingBalls(k, n, string) :`` ` `    ``# count array to count how many times ``    ``# each color has occurred ``    ``a ``=` `[``0``] ``*` `MAX_CHAR``     ` `    ``for` `i ``in` `range``(n) : ``        ``# increasing count of each color``        ``# every time it appears``        ``a[``ord``(string[i]) ``-` `ord``(``'a'``)] ``+``=` `1``     ` `    ``for` `i ``in` `range``(MAX_CHAR) :``        ``# to check if any color appears``        ``# more than K times if it does``        ``# we will print NO``        ``if` `(a[i] > k) :``            ``return` `False` `     ` `    ``return` `True` ` ` ` ` `# Driver code ``if` `__name__ ``=``=` `"__main__"` `:``  ` `    ``n, k ``=` `6``, ``3``    ``string ``=` `"aacaab"` ` ` `    ``if` `(distributingBalls(k, n, string)) :``        ``print``(``"YES"``) ``    ``else` `:``        ``print``(``"NO"``) `` ` `# This code is contributed by Ryuga`

## C#

 `// C# program to find if its possible to``// distribute balls without repetition``using` `System;`` ` `public` `class` `GFG {`` ` `    ``static` `int` `MAX_CHAR = 26;``     ` `    ``// function to find if its possible``    ``// to distribute balls or not``    ``static` `bool` `distributingBalls(``long` `k,``                       ``long` `n, ``string` `str)``    ``{ ``         ` `        ``// count array to count how many``        ``// times each color has occurred``        ``int` `[]a = ``new` `int``[MAX_CHAR];``         ` `        ``for` `(``int` `i = 0; i < n; i++)``        ``{``             ` `            ``// increasing count of each``            ``// color every time it appears``            ``a[str[i] - ``'a'``]++; ``        ``}``         ` `        ``for` `(``int` `i = 0; i < MAX_CHAR; i++) ``     ` `            ``// to check if any color``            ``// appears more than K``            ``// times if it does we``            ``// will print NO``            ``if` `(a[i] > k) ``                ``return` `false``;``     ` `        ``return` `true``;``    ``}``     ` `    ``// Driver code``    ``static` `public` `void` `Main ()``    ``{``        ``long` `n = 6, k = 3;``        ``string` `str = ``"aacaab"``;``     ` `        ``if` `(distributingBalls(k, n, str))``            ``Console.WriteLine(``"YES"``);``        ``else``            ``Console.WriteLine(``"NO"``);``    ``}``}`` ` `// This code is contributed by vt_m.`

## Javascript

 ``

Output

`NO`

Time complexity : O(n)
Auxiliary Space : O(1)

This article is contributed by Sarthak Kohli. If you like GeeksforGeeks and would like to contribute, you can also write an article using write.geeksforgeeks.org or mail your article to review-team@geeksforgeeks.org. See your article appearing on the GeeksforGeeks main page and help other Geeks.