Given N balls. For convenience, we denote the color of each ball as — lowercase letters. We have to distribute N balls among K people. They will be upset if they get two balls of the same color. We can give any number of balls to people and they won’t be upset even if they do not get any balls, but, we have to distribute all the balls, such that no one will be upset — print YES, if it is possible, and NO, otherwise.
Examples:
Input : 4 2 // value of N and K
aabb // colors of given balls
Output : YES
We can give 1st and 3rd ball to the first person,
and 2nd and 4th to the second.
Input : 6 3 // value of N and K
aacaab // colors of given balls
Output : NO
We need to give all balls of color a, but one
ball will stay, that's why answer is NO
The approach will be really simple. We will create a count array to keep the count of each color that occurs and then we will check if any color occurs more than the number of people we have. If it occurs, we will print NO else YES.
The implementation of the above idea is given below.
C++
#include <bits/stdc++.h>
using namespace std;
const int MAX_CHAR = 26;
bool distributingBalls( int k, int n, string str)
{
int a[MAX_CHAR] = {0};
for ( int i = 0; i < n; i++){
a[str[i] - 'a' ]++;
}
for ( int i = 0; i < MAX_CHAR; i++)
if (a[i] > k)
return false ;
return true ;
}
int main()
{
long long int n = 6, k = 3;
string str = "aacaab" ;
if (distributingBalls(k, n, str))
cout << "YES" ;
else
cout << "NO" ;
return 0;
}
|
Java
import java.io.*;
public class GFG {
static int MAX_CHAR = 26 ;
static boolean distributingBalls( long k,
long n, String str)
{
int []a = new int [MAX_CHAR];
for ( int i = 0 ; i < n; i++)
{
a[str.charAt(i) - 'a' ]++;
}
for ( int i = 0 ; i < MAX_CHAR; i++)
if (a[i] > k)
return false ;
return true ;
}
static public void main (String[] args)
{
long n = 6 , k = 3 ;
String str = "aacaab" ;
if (distributingBalls(k, n, str))
System.out.println( "YES" );
else
System.out.println( "NO" );
}
}
|
Python3
MAX_CHAR = 26
def distributingBalls(k, n, string) :
a = [ 0 ] * MAX_CHAR
for i in range (n) :
a[ ord (string[i]) - ord ( 'a' )] + = 1
for i in range (MAX_CHAR) :
if (a[i] > k) :
return False
return True
if __name__ = = "__main__" :
n, k = 6 , 3
string = "aacaab"
if (distributingBalls(k, n, string)) :
print ( "YES" )
else :
print ( "NO" )
|
C#
using System;
public class GFG {
static int MAX_CHAR = 26;
static bool distributingBalls( long k,
long n, string str)
{
int []a = new int [MAX_CHAR];
for ( int i = 0; i < n; i++)
{
a[str[i] - 'a' ]++;
}
for ( int i = 0; i < MAX_CHAR; i++)
if (a[i] > k)
return false ;
return true ;
}
static public void Main ()
{
long n = 6, k = 3;
string str = "aacaab" ;
if (distributingBalls(k, n, str))
Console.WriteLine( "YES" );
else
Console.WriteLine( "NO" );
}
}
|
Javascript
<script>
let MAX_CHAR = 26;
function distributingBalls(k, n, str)
{
let a = new Array(MAX_CHAR);
a.fill(0);
for (let i = 0; i < n; i++)
{
a[str[i].charCodeAt() - 'a' .charCodeAt()]++;
}
for (let i = 0; i < MAX_CHAR; i++)
if (a[i] > k)
return false ;
return true ;
}
let n = 6, k = 3;
let str = "aacaab" ;
if (distributingBalls(k, n, str))
document.write( "YES" );
else
document.write( "NO" );
</script>
|
Time complexity : O(n)
Auxiliary Space : O(1)
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Last Updated :
16 Feb, 2023
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