Given a Binary Tree, the task is to find the absolute difference between the sums of odd and even positioned nodes. A node is said to be odd and even positioned if its position in the current level is odd and even respectively. Note that the first element of each row is considered as odd positioned.
Input: 5 / \ 2 6 / \ \ 1 4 8 / / \ 3 7 9 Output: 11 Level oddPositionNodeSum evenPositionNodeSum 0 5 0 1 2 6 2 9 4 3 12 7 Difference = |(5 + 2 + 9 + 12) - (0 + 6 + 4 + 7)| = |28 - 17| = 11 Input: 5 / \ 2 3 Output: 4
Approach: To find the sum of nodes at even and odd positions level by level, use level order traversal. While traversing the tree level by level mark flag oddPosition as true for the first element of each row and switch it for each next element of the same row. And in case if oddPosition flag is true add the node data into oddPositionNodeSum else add node data to evenPositionNodeSum. After completion of tree traversal find the absolute value of their differences at the end of the tree traversal.
Below is the implementation of the above approach:
- Difference between sums of odd level and even level nodes of a Binary Tree
- Swap Nodes in Binary tree of every k'th level
- Print nodes between two given level numbers of a binary tree
- Count nodes with two children at level L in a Binary Tree
- Print all the nodes except the leftmost node in every level of the given binary tree
- Print odd positioned nodes of odd levels in level order of the given binary tree
- Print odd positioned nodes of even levels in level order of the given binary tree
- Print extreme nodes of each level of Binary Tree in alternate order
- Print even positioned nodes of odd levels in level order of the given binary tree
- Print even positioned nodes of even levels in level order of the given binary tree
- Queries to find the maximum Xor value between X and the nodes of a given level of a perfect binary tree
- Recursive Program to Print extreme nodes of each level of Binary Tree in alternate order
- Sum of nodes at k-th level in a tree represented as string
- Level with maximum number of nodes using DFS in a N-ary tree
- Count the number of nodes at given level in a tree using BFS.
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