Difference between sizeof(int *) and sizeof(int) in C/C++
sizeof() is commonly used operator in the C or C++. It is a compile-time unary operator that can be used to compute the size of its operand. The result of sizeof() is of unsigned integral type which is usually denoted by size_t. This operator can be applied to any data-type, including primitive types such as integer and floating-point types, pointer types, or compound datatypes such as structure, union etc.
int means a variable whose datatype is integer.
sizeof(int) returns the number of bytes used to store an integer.Take a step-up from those "Hello World" programs. Learn to implement data structures like Heap, Stacks, Linked List and many more! Check out our Data Structures in C course to start learning today.
int* means a pointer to a variable whose datatype is integer.
sizeof(int*) returns the number of bytes used to store a pointer.
Since the sizeof operator returns the size of the datatype or the parameter we pass to it. So, the value it should return after passing a variable of (int *) to it:
- Since int* points to an address location as it is a pointer to a variable, So, the sizeof(int*) simply implies the value of the memory location on the machine, and, memory Locations themselves are 4-byte to 8-byte integer values.
- On a 32-bit Machine, sizeof(int*) will return a value 4 because the address value of memory location on a 32-bit machine is 4-byte integers.
- Similarly, on a 64-bit machine it will return a value of 8 as on a 64-bit machine the address of a memory location are 8-byte integers.
Now, the value it should return after passing a variable of (int) to it:
- Since int in an integer type variable. So, the sizeof(int) simply implies the value of size of an integer.
- Whether it is a 32-bit Machine or 64-bit machine, sizeof(int) will always return a value 4 as the size of an integer.
Below is the illustration of sizeof operator on 64-bit machine:
Size of (int) = 4 bytes Size of (int*) = 8 bytes