Predict the output of following C programs.

`// PROGRAM 1` `#include <stdio.h>` `int` `main(` `void` `)` `{` ` ` `int` `arr[] = {10, 20};` ` ` `int` `*p = arr;` ` ` `++*p;` ` ` `printf` `(` `"arr[0] = %d, arr[1] = %d, *p = %d"` `,` ` ` `arr[0], arr[1], *p);` ` ` `return` `0;` `}` |

`// PROGRAM 2` `#include <stdio.h>` `int` `main(` `void` `)` `{` ` ` `int` `arr[] = {10, 20};` ` ` `int` `*p = arr;` ` ` `*p++;` ` ` `printf` `(` `"arr[0] = %d, arr[1] = %d, *p = %d"` `,` ` ` `arr[0], arr[1], *p);` ` ` `return` `0;` `}` |

`// PROGRAM 3` `#include <stdio.h>` `int` `main(` `void` `)` `{` ` ` `int` `arr[] = {10, 20};` ` ` `int` `*p = arr;` ` ` `*++p;` ` ` `printf` `(` `"arr[0] = %d, arr[1] = %d, *p = %d"` `, ` ` ` `arr[0], arr[1], *p);` ` ` `return` `0;` `}` |

The output of above programs and all such programs can be easily guessed by remembering following simple rules about postfix ++, prefix ++ and * (dereference) operators**1)** Precedence of prefix ++ and * is same. Associativity of both is right to left.**2)** Precedence of postfix ++ is higher than both * and prefix ++. Associativity of postfix ++ is left to right.

(Refer: Precedence Table)

The expression **++*p** has two operators of same precedence, so compiler looks for assoiativity. Associativity of operators is right to left. Therefore the expression is treated as * ++(*p)*. Therefore the output of first program is “

*arr[0] = 11, arr[1] = 20, *p = 11*“.

The expression ***p++** is treated as* *(p++) *as the precedence of postfix ++ is higher than *. Therefore the output of second program is “

*arr[0] = 10, arr[1] = 20, *p = 20*“.

The expression ***++p** has two operators of same precedence, so compiler looks for assoiativity. Associativity of operators is right to left. Therefore the expression is treated as * *(++p)*. Therefore the output of third program is “

*arr[0] = 10, arr[1] = 20, *p = 20*“.

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