# Difference Between Bisection Method and Regula Falsi Method

The bisection method is used for finding the roots of equations of non-linear equations of the form f(x) = 0 is based on the repeated application of the intermediate value property. Let f(x) is continuous function in the closed interval [x1,x2], if f(x1), f(x2) are of opposite signs , then there is at least one root α in the interval (x1,x2), such that f(α) = 0.

**Formula**

X2= (X0 + X1) / 2

**Example**

**Problem: Find a root of an equation f(x)=x3-x-1 **

**Solution:**

Given equation f(x)=x3-x-1

let x = 0, 1, 2

**In 1st iteration :**

f(1)=-1<0 and f(2)=5>0

Root lies between these two points 1 and 2

x0=1+2/2 = 1.5

f(x0)=f(1.5)=0.875>0

**In 2nd iteration :**

f(1)=-1<0 and f(1.5)=0.875>0

Root lies between these two points 1 and 1.5

x1=1+1.5/2 =1.25

f(x1)=f(1.25)=-0.29688<0

**In** **3rd iteration :**

f(1.25)=-0.29688<0 and f(1.5)=0.875>0

Root lies between these two points 1.25 and 1.5

x2=1.25+1.5/2 = 1.375

f(x2)=f(1.375)=0.22461>0

**In 4th iteration :**

f(1.25)=-0.29688<0 and f(1.375)=0.22461>0

Root li

etween these two points 1.25 and 1.375x3=1.25+1.375/2=1.3125

f(x3)=f(1.3125)=-0.05151<0

**In** **5th iteration :**

f(1.3125)=-0.05151<0 and f(1.375)=0.22461>0

Root lies between these two points 1.3125 and 1.375

x4=1.3125+1.375/2=1.34375

f(x4)=f(1.34375)=0.08261>0

**In** **6th iteration :**

f(1.3125)=-0.05151<0 and f(1.34375)=0.08261>0

Root lies b

en these two points 1.3125 and 1.34375x5=1.3125+1.34375/2=1.32812

f(x5)=f(1.32812)=0.01458>0

**In 7th iteration :**

f(1.3125)=-0.05151<0 and f(1.32812)=0.01458>0

Root lies between these two points 1.3125 and 1.32812

x6=1.3125+1.32812/2 =1.32031

f(x6)=f(1.32031)=-0.01871<0

**In** **8th iteration :**

f(1.32031)=-0.01871<0 and f(1.32812)=0.01458>0

Root lies be

n these two points 1.32031 and 1.32812x7=1.32031+1.32812/2=1.32422

f(x7)=f(1.32422)=-0.00213<0

**In** **9th iteration :**

f(1.32422)=-0.00213<0 and f(1.32812)=0.01458>0

Root lies between these two points 1.32422 and 1.32812

x8=1.32422+1.32812/2=1.32617

f(x8)=f(1.32617)=0.00621>0

**In 10th iteration :**

f(1.32422)=-0.00213<0 and f(1.32617)=0.00621>0

Root lies be

n these two points 1.32422 and 1.32617x9=1.32422+1.32617/2=1.3252

f(x9)=f(1.3252)=0.00204>0

**In** **11th iteration :**

f(1.32422)=-0.00213<0 and f(1.3252)=0.00204>0

Root lies between these two points 1.32422 and 1.3252

x10=1.32422+1.3252/2=1.32471

f(x10)=f(1.32471)=-0.00005<0

**The approximate root of the equation x3-x-1=0 using the** **Bisection method is 1.32471**

### Regula Falsi Method:

Regula Falsi is one of the oldest methods to find the real root of an equation f(x) = 0 and closely resembles with Bisection method. It requires less computational effort as we need to evaluate only one function per iteration.

**Formula**

X3 = X1(fX2) - X2(fX1)/ f(X2) -f(X1)

**Example**

**Problem: Find a root**

**an equation f(x)=x3-x-1**

**Solution:**

**Given equation,** x3-x-1=0

let x = 0, 1, 2

**In 1st iteration :**

f(1)=-1<0 and f(2)=5>0

Root lies between these two points x0=1 and x1=2

x2=x0-f(x0)

= x1-x0

f(x1)-f(x0)

x2=1-(-1)⋅

= 2-1

= 5-(-1)

x2=1.16667

f(x2)=f(1.16667)=-0.5787<0

**In 2nd iteration :**

f(1.16667)=-0.5787<0 and f(2)=5>0

Root lies between these two points x0=1.16667 and x1=2

x

-f(x0)x1-x0

f(x1)-f(x0)

x3=1.16667-(-0.5787)

2-1.16667

5-(-0.5787)

x3=1.25311

f(x3)=f(1.25311)=-0.28536<0

**In 3rd iteration :**

f(1.25311)=-0.28536<0 and f(2)=5>0

Root lies between these two points x0=1.25311 and x1=2

x4=x0-f(x0)⋅

x1-x0

f(x1)-f(x0)

x4=1.25311-(-0.28536)⋅

2-1.25311

5-(-0.28536)

x4=1.29344

f(x4)=f(1.29344)=-0.12954<0

**In 4th iteration :**

f(1.29344)=-0.12954<0 and f(2)=5>0

Root lies between these two points

1.29344 and x1=2x5=x0-f(x0)⋅

x1-x0

f(x1)-f(x0)

x5=1.29344-(-0.12954)⋅

2-1.29344

5-(-0.12954)

x5=1.31128

f(x5)=f(1.31128)=-0.05659<0

**In 5th iteration :**

f(1.31128)=-0.05659<0 and f(2)=5>0

Root lies between these two points x0=1.31128 and x1=2

x6=x0-f(x0)⋅

x1-x0

f(x1)-f(x0)

x6=1.31128-(-0.05659)⋅

2-1.31128

5-(-0.05659)

x6=1.31899

f(x6)=f(1.31899)=-0.0243<0

**In 6th iteration :**

&nb

(1.31899)=-0.0243<0 and f(2)=5>0Root lies between these two points x0=1.31899 and x1=2

x7=x0-f(x0)⋅

x1-x0

f(x1)-f(x0)

x7=1.31899-(-0.0243)⋅

2-1.31899

5-(-0.0243)

x7=1.32228

f(x7)=f(1.32228)=-0.01036<0

**In 7th iteration :**

f(1.32228)=-0.01036<0 and f(2)=5>0

Root lies between these two points x0=1.32228 and x1=2

x8=x0-f(x0)⋅

x1-x0

f(x1)-f(x0)

x8=1.32228-(-0.01036)⋅

2-1.32228

5-(-0.01036)

x8=1.32368

**The approximate root of the equation x3-x-1=0 using the Regula Falsi method is 1.32368**

**Differences between Bisection Method and Regula False Method**

Basis | Bisection Method | Regula Falsi Method |
---|---|---|

Definition | In mathematics, the bisection method is a root-finding method that applies to continuous function for which knows two values with opposite signs. | In mathematics, the false position method is a very old method for solving equations with one unknown this method is modified form is still in use. |

Simplicity | it is simple to use and easy to implement. | Simple to use as compared to Bisection Method |

Computational Efforts | Less as compared to Regula Falsi Method | More as compared to Bisection Method |

Iteration required | In the bisection method, if one of the initial guesses is closer to the root, it will take a large number of iterations to reach the root. | Less as compared to Bisection Method. This method can be less precise than bisection – no strict precision is guaranteed. |

Convergence | The order of convergence of the bisection method is slow and linear. | This method faster order of convergence than the bisection method. |

General Iterative Formula | Formula is : X3 =( X1 + X2)/2 | Formula is : X3 = X1(fx2) – x2(fx1)/ f(x2) -f(x1) |

Other Names | It is also known as the Bolzano method, Binary chopping method, half Interval method. | It is also known as the False Position method. |