Diagonal of a Regular Decagon
Last Updated :
25 Jun, 2022
Given an integer a which is the side of a regular decagon, the task is to find and print the length of its diagonal.
Examples:
Input: a = 5
Output: 9.51
Input: a = 9
Output: 17.118
Approach: We know that the sum of interior angles of a polygon = (n – 2) * 180 where, n is the no. of sides in the polygon.
So, sum of interior angles of decagon = 8 * 180 = 1440 and each interior angle will be 144.
Now, we have to find BC = 2 * x. If we draw a perpendicular AO on BC, we will see that the perpendicular bisects BC in BO and OC, as triangles AOB and AOC are congruent to each other.
So, in triangle AOB, sin(72) = x / a i.e. x = 0.951 * a
Therefore, diagonal length will be 2 * x i.e. 1.902 * a.
Below is the implementation of the above approach:
C++
#include <bits/stdc++.h>
using namespace std;
float decdiagonal( float a)
{
if (a < 0)
return -1;
float d = 1.902 * a;
return d;
}
int main()
{
float a = 9;
cout << decdiagonal(a) << endl;
return 0;
}
|
Java
import java.util.*;
import java.lang.*;
import java.io.*;
public class GFG {
static double decdiagonal( double a)
{
if (a< 0 )
return - 1 ;
double d= 1.902 *a;
return d;
}
public static void main(String[] args)
{
int a = 9 ;
System.out.println(decdiagonal(a));
}
}
|
Python3
def decdiagonal(a) :
if (a < 0 ) :
return - 1
d = 1.902 * a
return d
if __name__ = = "__main__" :
a = 9
print (decdiagonal(a))
|
C#
using System;
public class GFG {
static double decdiagonal( double a)
{
if (a<0)
return -1;
double d=1.902*a;
return d;
}
public static void Main()
{
int a = 9;
Console.WriteLine(decdiagonal(a));
}
}
|
PHP
<?php
function decdiagonal( $a )
{
if ( $a < 0)
return -1;
$d = 1.902 * $a ;
return $d ;
}
$a = 9;
echo decdiagonal( $a );
?>
|
Javascript
<script>
function decdiagonal(a)
{
if (a < 0)
return -1;
var d = 1.902*a;
return d;
}
var a = 9;
document.write(decdiagonal(a));
</script>
|
Time Complexity: O(1)
Auxiliary Space: O(1)
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