Question No. 1
Directions: Answer the questions based on the information given below.
The given table shows the total number of boilers (Taap and Bhaap), average quantity of water boiled per boiler, percentage of the quantity of water boiled in Taap out of total quantity of water boiled in both the boilers together, average quantity of water boiled per Bhaap, in four different factories.
For Anu, find the ratio of the average quantity of water boiled in each Taap and in each Bhaap.
A – 3:4
B – 2:5
C – 1:3
D – 5:7
E- None of these
Solution
For Anu:
Sum of quantities of water boiled in given two type of boilers = 80 x 300 = 24000 litres
Quantity of water boiled in Taap = 0.25 x 24000 = 6000 litres
Quantity of water boiled in Bhaap = 24000 – 6000 = 18000 litres
Total number of Bhaap = 18000/120 = 150
Total number of Taap = 300 – 150 = 150
Average quantity of water boiled per Taap = 6000/150=40 litres
Similarly,
Average of quantity of water boiled in each Taap = 6000/150 = 40 litres
Average of quantity of water boiled in each Bhaap = 120 litres
Required ratio = 40:120 = 1:3
Hence, option C.
Question No. 2
Directions: Answer the questions based on the information given below.
The given table shows the total number of boilers (Taap and Bhaap), average quantity of water boiled per boiler, percentage of quantity of water boiled in Taap out of total quantity of water boiled in both the boilers together, average quantity of water boiled per Bhaap, in four different factories.
Number of Bhaap in Ushma is how much percent more/less then number of Taap in it?
A- 75%
B- 60%
C- 80%
D- 45%
E- None of these
Solution
For Anu:
Sum of quantities of water boiled in given two type of boilers = 80 x 300 = 24000 litres
Quantity of water boiled in Taap = 0.25 x 24000 = 6000 litres
Quantity of water boiled in Bhaap = 24000 – 6000 = 18000 litres
Total number of Bhaap = 18000/120 = 150
Total number of Taap = 300 – 150 = 150
Average quantity of water boiled per Taap = 6000/150=40 litres
Similarly,
Required percentage = {(200 – 50)/200} x 100 = 75%
Hence, option A
Question No. 3
Directions: Answer the questions based on the information given below.
The given table shows the total number of boilers (Taap and Bhaap), average quantity of water boiled per boiler, percentage of quantity of water boiled in Taap out of total quantity of water boiled in both the boilers together, average quantity of water boiled per Bhaap, in four different factories.
On a certain day in Vaasp, 25% of number of Taap and 1/3rd of the number of Bhaap were not working. If the average quantity of water boiled in each Taap and each Bhaap on that day was 60 litres and 50 litres, respectively then find the total quantity of water boiled in boilers in Vaasp.
A – 6200 litres
B – 4800 litres
C- 6000 litres
D – 5400 litres
E – None of these
Solution
For Anu:
Sum of quantities of water boiled in given two type of boilers = 80 x 300 = 24000 litres
Quantity of water boiled in Taap = 0.25 x 24000 = 6000 litres
Quantity of water boiled in Bhaap = 24000 – 6000 = 18000 litres
Total number of Bhaap = 18000/120 = 150
Total number of Taap = 300 – 150 = 150
Average quantity of water boiled per Taap = 6000/150=40 litres
Similarly,
Number of Taap working in Vaasp = 0.75 x 40 = 30
Quantity of water boiled in Taap = 30 x 60 = 1800 litres
Number of Bhaap working in Vaasp = (2/3) x 120 = 80
Quantity of water boiled in Bhaap = 80 x 50 = 4000 litres
Required quantity of water boiled = 4000 + 1800 = 5800 litres
Hence, option E.
Question No. 4
Directions: Answer the questions based on the information given below.
The given table shows the total number of boilers (Taap and Bhaap), average quantity of water boiled per boiler, percentage of quantity of water boiled in Taap out of the total quantity of water boiled in both the boilers together, average quantity of water boiled per Bhaap, in four different factories.
In Dravya, 20 more number of Taap and 25% more number of Bhaap, were installed. Find the difference between new number of Taap and Bhaap in Dravya.
A – 20
B – 50
C-40
D-60
E – None of these
Solution
For Anu:
Sum of quantities of water boiled in given two type of boilers = 80 x 300 = 24000 litres
Quantity of water boiled in Taap = 0.25 x 24000 = 6000 litres
Quantity of water boiled in Bhaap = 24000 – 6000 = 18000 litres
Total number of Bhaap = 18000/120 = 150
Total number of Taap = 300 – 150 = 150
Average quantity of water boiled per Taap = 6000/150=40 litres
Similarly,
New number of Taap = 80 + 20 = 100
New number of Bhaap = 1.25 x 120 = 150
Required difference = 150 – 100 = 50
Hence, option B
Question No. 5
Directions: Answer the questions based on the information given below.
The given table shows the total number of boilers (Taap and Bhaap), average quantity of water boiled per boiler, percentage of quantity of water boiled in Taap out of total quantity of water boiled in both the boilers together, average quantity of water boiled per Bhaap, in four different factories.
Find the sum of average quantity of water boiled per Taap in Ushma and Dravya.
A – 420 litres
B – 360 litres
C- 280 litres
D – 390 litres
E. None of these
Solution
For Anu:
Sum of quantities of water boiled in given two type of boilers = 80 x 300 = 24000 litres
Quantity of water boiled in Taap = 0.25 x 24000 = 6000 litres
Quantity of water boiled in Bhaap = 24000 – 6000 = 18000 litres
Total number of Bhaap = 18000/120 = 150
Total number of Taap = 300 – 150 = 150
Average quantity of water boiled per Taap = 6000/150=40 litres
Similarly,
Required sum = 90 + 300 = 390 litres
Hence, option D.
Question No. 6
Directions: Answer the questions based on the information given below.
The given table shows the data regarding the number of air conditioners and air coolers sold by a shop in 5 different months and also percentage of those installed.
If total number of air conditioners installed in all the months together is 1540 units, then find out the number of air coolers installed in the month of June.
A – 120
B – 170
C – 140
D – 210
E – 150
Solution
In March, Number of air conditioners installed = 2x * 0.8 = 1.6x
Number of air coolers installed = (3x + 90) * 1/3 = x + 30
Similarly, we can find out the number of air conditioners and air coolers installed in the given 5 months.
Total number of air conditioners installed in all the months together
= (1.6x) + (2x + 400) + (x + 300) + 2x + (0.9x + 90)
= 7.5x + 790
According to the question,
7.5x + 790 = 1540
Or, 7.5x = 750
Or, x = 100
Number of air coolers installed in the month of June = 1.5 x 100 = 150
Hence, option E.
Question No. 7
Directions: Answer the questions based on the information given below.
The given table shows the data regarding the number of air conditioners and air coolers sold by a shop in 5 different months and also percentage of those installed.
If number of air conditioners installed in April and May together is 150 more than the number of air coolers sold in June and July together, then find out the total number of air conditioners sold in March, April and July together.
A – 1200
B – 1700
C – 2000
D – 2100
E – 1500
Solution
In March, Number of air conditioners installed = 2x * 0.8 = 1.6x
Number of air coolers installed = (3x + 90) * 1/3 = x + 30
Similarly, we can find out the number of air conditioners and air coolers installed in the given 5 months.
Number of air conditioners installed in April and May together = (2x + 400) + (x + 300) = 3x + 700
Number of air coolers sold in June and July together = (1.5x) + (2x + 400) = 3.5x + 400
According to the question,
(3x + 700) – (3.5x + 400) = 150
Or, -0.5x + 300 = 150
Or, 0.5x = 150
Or, x = 300
Total air conditioners sold in March, April and July together
= (2x) + (2x + 400) + (x + 100)
= 5x + 500
= 2000
Hence, option C.
Question No. 8
Directions: Answer the questions based on the information given below.
The given table shows the data regarding the number of air conditioners and air coolers sold by a shop in 5 different months and also percentage of those installed
Find the difference between number of air conditioners installed in April and June together and the number of air coolers installed in March and May together.
A – Can’t be determined
B – 970
C- 870
D – 210
E – 530
Solution
In March, Number of air conditioners installed = 2x * 0.8 = 1.6x
Number of air coolers installed = (3x + 90) * 1/3 = x + 30
Similarly, we can find out the number of air conditioners and air coolers installed in the given 5 months.
Number of air conditioners installed in April and June together = (2x + 400) + 2x = 4x + 400
Number of air coolers installed in March and May together = (x + 30) + (3x – 600) = 4x – 570
Required difference = (4x + 400) – (4x – 570) = 970
Hence, option B.
Question No. 9
Directions: Answer the questions based on the information given below.
The given table shows the data regarding the number of air conditioners and air coolers sold by a shop in 5 different months and also percentage of those installed.
If the ratio between number of air conditioners installed in July to the air coolers installed in March is 3:2, then find out the total number of air conditioners and air coolers together sold in the month of July.
A – 725
B – 975
C- 775
D- 750
E – 580
Solution
In March, Number of air conditioners installed = 2x * 0.8 = 1.6x
Number of air coolers installed = (3x + 90) * 1/3 = x + 30
Similarly, we can find out the number of air conditioners and air coolers installed in the given 5 months.
According to the question,
(0.9x + 90):(x + 30) = 3:2
Or, 3x + 90 = 1.8x + 180
Or, 1.2x = 90
Or, x = 75
The total number of units sold in the month of July
= (x + 100) + (2x + 400)
= 3x + 500
= 3 × 75 + 500
= 725
Hence, option A.
Question No. 10
Directions: Answer the questions based on the information given below.
The given table shows the data regarding the number of air conditioners and air coolers sold by a shop in 5 different months and also percentage of those installed.
If average number of air conditioners sold in the months of April and May is 600, then what is the average of the number of air coolers sold in the months of June and July?
A – 289.5
B – 235.5
C – 287.5
D- 275.5
E – 290.5
Solution
In March, Number of air conditioners installed = 2x * 0.8 = 1.6x
Number of air coolers installed = (3x + 90) * 1/3 = x + 30
Similarly, we can find out the number of air conditioners and air coolers installed in the given 5 months
Average number of air conditioners sold in the months of April and May = {(2x + 400) + (2x + 600)}/2 = 2x + 500
According to the question,
2x + 500 = 600
Or, 2x = 100
Or, x = 50
Now, average of the number of air coolers sold in the months of June and July
= {(1.5x) + (2x + 400)}/2
= (3.5x + 400)/2
= (3.5 x 50 + 400)/2
= 575/2
= 287.5
Hence, option C
Question No. 11
Direction: Answer the questions based on the information given below:
The given table shows the number of cooler sold ad ratio of number of coolers sold to the number of ACs sold, in five different cities.
Note: Total product sold = Number of (coolers + ACs) sold
Find the ratio of total product sold in Delhi to number of ACs sold in Agra
A – 4:5
B – 3:2
C – 1:1
D – 2:1
E – 5:3
Solution
Required ratio = 1750:1750 = 1:1
Hence, option C
Question No. 12
Direction: Answer the questions based on the information given below:
The given table shows the number of cooler sold ad ratio of number of coolers sold to the number of ACs sold, in five different cities.
Note: Total product sold = Number of (coolers + ACs) sold
Total number of product sold in Ranchi is how much percent more/less than that in Patna?
A – 27.48%
B – 24.56%
C – 29.12%
D – 23.48%
E – None of these
Solution
Required percentage = {(5000 – 3626)/5000} x 100 = 27.48%
Hence, option A
Question No. 13
Direction: Answer the questions based on the information given below:
The given table shows the number of cooler sold ad ratio of number of coolers sold to the number of ACs sold, in five different cities.
Note: Total product sold = Number of (coolers + ACs) sold
Find the average number of ACs sold in Delhi and Agra
A – 1125
B – 1245
C – 1315
D – 1095
E – 975
Solution
Required average = (500 + 1750)/2 = 1125
Hence, option A
Question No. 14
Direction: Answer the questions based on the information given below:
The given table shows the number of cooler sold ad ratio of number of coolers sold to the number of ACs sold, in five different cities.
Note: Total product sold = Number of (coolers + ACs) sold
Out of total products in Agra, 40% were of LG and rest of Haier. If 2/3rd of coolers sold in Agra were of Haier, then find the number of ACs of Haier sold in Agra.
A – 750
B – 1050
C – 540
D – 950
E – 1000
Solution
Total products of Haier sold in Agra = 0.6 x 2500 = 1500
Number of coolers of Haier sold in Agra = (2/3) x 750 = 500
Therefore, number of ACs of Haier sold in Agra = 1500 – 500 = 1000
Hence, option E
Question No. 15
Direction: Answer the questions based on the information given below:
The given table shows the number of cooler sold ad ratio of number of coolers sold to the number of ACs sold, in five different cities.
Note: Total product sold = Number of (coolers + ACs) sold
If the ratio of the number of ACs sold in Patna and Ambala is 9:5, respectively, then find the number of coolers sold in Ambala which is 200 less than that the number of ACs sold in the same city.
A – 750
B – 800
C – 1200
D – 600
E – None of theses
Solution
Number of ACs sold in Ambala = 1800 x (5/9) = 1000
Number of coolers sold in Ambala = 1000 – 200 = 800
Hence, option B
Question No. 16
Directions: Answer the questions based on the information given below.
Different number of articles (bracelets, boxes and pens) was sold in five different months. The given table shows the total number of articles sold, number of bracelets sold and ratio of number of boxes to pens sold, in given five months.
Out of total number of pens sold in May and June together 40% were red pens and rest were black pens. If the cost of each red pens and each black pens sold in given two months are Rs. 5 and Rs. 3 respectively then find the difference between amount earned by selling red and black pens in given two months together.
A – Rs. 180
B – Rs. 240
C – Rs. 200
D – Rs. 160
E – None of these
Solution
Number of black pens sold in May and June together = 0.6 × (600 + 300) = 540
Number of red pens sold in May and June together = 0.4 × (600 + 300) = 360
Required difference = 360 × 5 – 540 × 3 = 1800 – 1620 = Rs. 180
Hence, option A
Question No. 17
Directions: Answer the questions based on the information given below.
Different number of articles (bracelets, boxes and pens) was sold in five different months. The given table shows the total number of articles sold, number of bracelets sold and ratio of number of boxes to pens sold, in given five months.
In July, 1/15th of number of bracelets, 50% of number of boxes and 60% of number of pens were sold to males and rest to females. How much percent of articles were sold to females in July?
A – 50%
B – 20%
C – 40%
D – 60%
E – None of these
Solution
In July,
Number of articles sold to males = (750/15) + (700/2) + (0.6 × 900) = 50 + 350 + 540 = 940
Required percentage = {(2350 – 940)/2350} × 100 = 60%
Hence, option D
Question No. 18
Directions: Answer the questions based on the information given below.
Different number of articles (bracelets, boxes and pens) was sold in five different months. The given table shows the total number of articles sold, number of bracelets sold and ratio of number of boxes to pens sold, in given five months.
In April, May and July each bracelet was sold for Rs. 8, Rs. 10 and Rs. 5 respectively. If the total amount earned by selling bracelets in given three months is equal to the amount earned by selling boxes in July and August together then find the average cost of each box sold in July and August together.
A – Rs. 9.065
B – Rs. 8.035
C – Rs. 6.125
D – Rs. 7.240
E – None of these
Solution
‘Amount earned by selling bracelets in April, May and July = (840 × 8) + (560 × 10) + (750 × 5) = 6720 + 5600 + 3750 = Rs. 16070
Therefore, average cost of each box sold in July and August together = {16070/1300 + 700)} = Rs. 8.035
Hence, option B
Question No. 19
Directions: Answer the questions based on the information given below.
The different number of articles (bracelets, boxes and pens) were sold in five different months. The given table shows the total number of articles sold, the number of bracelets sold and the ratio of the number of boxes to pens sold, in the five given months.
In each box sold in April and June, 25 fruits and 15 fruits can be packed, respectively. If the difference between the numbers of fruits which can be put in the boxes sold in April and June is 12 times the number of pencils sold in June then find the sum of the number of pencils and bracelets sold in June.
A – 1540
B – 1650
C – 1200
D – 1800
E – None of these
Solution
Difference between number of fruits which can be put in the boxes sold in April and June = (960 × 25) – (800 × 15) = 24000 – 12000 = 12000
Number of pencils sold in June = 12000/12 = 1000
Required sum = 1000 + 800 = 1800
Hence, option D
Question No. 20
Directions: Answer the questions based on the information given below.
Different number of articles (bracelets, boxes and pens) was sold in five different months. The given table shows the total number of articles sold, number of bracelets sold and ratio of number of boxes to pens sold, in given five months.
The ratio of the number of pens sold in April, June and August is:
A – 3:3:4
B – 1:2:5
C – 2:2:3
D – 1:1:5
E – None of these.
Solution
Required ratio = 600:600:800 = 3:3:4
Hence, option A
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