Given a graph, the task is to detect a cycle in the graph using degrees of the nodes in the graph and print all the nodes that are involved in any of the cycles. If there is no cycle in the graph then print -1.
Output: 0 1 2
Approach: Recursively remove all vertices of degree 1. This can be done efficiently by storing a map of vertices to their degrees.
Initially, traverse the map and store all the vertices with degree = 1 in a queue. Traverse the queue as long as it is not empty. For each node in the queue, mark it as visited, and iterate through all the nodes that are connected to it (using the adjacency list), and decrement the degree of each of those nodes by one in the map. Add all nodes whose degree becomes equal to one to the queue. At the end of this algorithm, all the nodes that are unvisited are part of the cycle.
Below is the implementation of the above approach:
0 1 2
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- Disjoint Set (Or Union-Find) | Set 1 (Detect Cycle in an Undirected Graph)
- Difference Between sum of degrees of odd and even degree nodes in an Undirected Graph
- Finding in and out degrees of all vertices in a graph
- Construct a graph from given degrees of all vertices
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- Check if there is a cycle with odd weight sum in an undirected graph
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Improved By : sanjeev2552