Delete consecutive same words in a sequence

Given a sequence of n strings, the task is to check if any two similar words come together then they destroy each other then print the number of words left in the sequence after this pairwise destruction.

Examples:

Input : ab aa aa bcd ab
Output : 3
As aa, aa destroys each other so, ab bcd ab is the
new sequence.

Input :  tom jerry jerry tom
Output : 0
As first both jerry will destroy each other.
Then sequence will be tom, tom they will also destroy
each other. So, the final sequence doesn't contain any
word.

Method 1:

1- Start traversing the sequence by storing it in vector.
  a) Check if the current string is equal to next string
     if yes, erase both from the vector.
  b) And check the same till last.
2- Return vector size.

C++

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// C++ program to remove consecutive same words
#include<bits/stdc++.h>
using namespace std;
  
// Function to find the size of manipulated sequence
int removeConsecutiveSame(vector <string > v)
{
    int n = v.size();
  
    // Start traversing the sequence
    for (int i=0; i<n-1; )
    {
        // Compare the current string with next one
        // Erase both if equal
        if (v[i].compare(v[i+1]) == 0)
        {
            // Erase function delete the element and
            // also shifts other element that's why
            // i is not updated
            v.erase(v.begin()+i);
            v.erase(v.begin()+i);
  
            // Update i, as to check from previous
            // element again
            if (i > 0)
                i--;
  
            // Reduce sequence size
            n = n-2;
        }
  
        // Increment i, if not equal
        else
            i++;
    }
  
    // Return modified size
    return v.size();
}
  
// Driver code
int main()
{
    vector<string> v = { "tom", "jerry", "jerry", "tom"};
    cout << removeConsecutiveSame(v);
    return 0;
}

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Java

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// Java program to remove consecutive same words
  
import java.util.Vector;
  
class Test
{
    // Method to find the size of manipulated sequence
    static int removeConsecutiveSame(Vector <String > v)
    {
        int n = v.size();
       
        // Start traversing the sequence
        for (int i=0; i<n-1; )
        {
            // Compare the current string with next one
            // Erase both if equal
            if (v.get(i).equals(v.get(i+1)))
            {
                // Erase function delete the element and
                // also shifts other element that's why
                // i is not updated
                v.remove(i);
                v.remove(i);
       
                // Update i, as to check from previous
                // element again
                if (i > 0)
                    i--;
       
                // Reduce sequence size
                n = n-2;
            }
       
            // Increment i, if not equal
            else
                i++;
        }
       
        // Return modified size
        return v.size();
    }
      
    // Driver method
    public static void main(String[] args) 
    {
        Vector<String> v = new Vector<>();
  
        v.addElement("tom"); v.addElement("jerry");
        v.addElement("jerry");v.addElement("tom");
  
        System.out.println(removeConsecutiveSame(v));
    }
}

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Python3

# Python3 program to remove consecutive
# same words

# Function to find the size of
# manipulated sequence
def removeConsecutiveSame(v):

n = len(v)

# Start traversing the sequence
i = 0
while(i < n - 1): # Compare the current string with # next one Erase both if equal if ((i + 1) < len(v)) and (v[i] == v[i + 1]): # Erase function delete the element and # also shifts other element that's why # i is not updated v = v[:i] v = v[:i] # Update i, as to check from previous # element again if (i > 0):
i -= 1

# Reduce sequence size
n = n – 2

# Increment i, if not equal
else:
i += 1

# Return modified size
return len(v[:i – 1])

# Driver Code
if __name__ == ‘__main__’:
v = [“tom”, “jerry”, “jerry”, “tom”]
print(removeConsecutiveSame(v))

# This code is contributed by SHUBHAMSINGH10

C#

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// C# program to remove consecutive same words 
using System;
using System.Collections.Generic;
  
class GFG
{
// Method to find the size of 
// manipulated sequence 
public static int removeConsecutiveSame(List<string> v)
{
    int n = v.Count;
  
    // Start traversing the sequence 
    for (int i = 0; i < n - 1;)
    {
        // Compare the current string with 
        // next one Erase both if equal 
        if (v[i].Equals(v[i + 1]))
        {
            // Erase function delete the element and 
            // also shifts other element that's why 
            // i is not updated 
            v.RemoveAt(i);
            v.RemoveAt(i);
  
            // Update i, as to check from 
            // previous element again 
            if (i > 0)
            {
                i--;
            }
  
            // Reduce sequence size 
            n = n - 2;
        }
  
        // Increment i, if not equal 
        else
        {
            i++;
        }
    }
  
    // Return modified size 
    return v.Count;
}
  
// Driver Code 
public static void Main(string[] args)
{
    List<string> v = new List<string>();
  
    v.Add("tom");
    v.Add("jerry");
    v.Add("jerry");
    v.Add("tom");
  
    Console.WriteLine(removeConsecutiveSame(v));
}
}
  
// This code is contributed by Shrikant13

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Output:

0

 

Method 2:(Using Stack)

1- Start traversing the strings and push into stack.
    a) Check if the current string is same as the string
       at the top of the stack
        i) If yes, pop the string from top.
        ii) Else push the current string.
2- Return stack size if the whole sequence is traversed.

C++

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//  C++ implementation of above method
#include<bits/stdc++.h>
using namespace std;
  
// Function to find the size of manipulated sequence
int removeConsecutiveSame(vector <string> v)
{
    stack<string> st;
  
    // Start traversing the sequence
    for (int i=0; i<v.size(); i++)
    {
        // Push the current string if the stack
        // is empty
        if (st.empty())
            st.push(v[i]);
        else
        {
            string str = st.top();
  
            // compare the current string with stack top
            // if equal, pop the top
            if (str.compare(v[i]) == 0)
                st.pop();
  
            // Otherwise push the current string
            else
                st.push(v[i]);
        }
    }
  
    // Return stack size
    return st.size();
}
  
// Driver code
int main()
{
    vector<string> V = { "ab", "aa", "aa", "bcd", "ab"};
    cout << removeConsecutiveSame(V);
    return 0;
}

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Java

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//  Java implementation of above method
  
import java.util.Stack;
import java.util.Vector;
  
class Test
{
    // Method to find the size of manipulated sequence
    static int removeConsecutiveSame(Vector <String> v)
    {
        Stack<String> st = new Stack<>();
       
        // Start traversing the sequence
        for (int i=0; i<v.size(); i++)
        {
            // Push the current string if the stack
            // is empty
            if (st.empty())
                st.push(v.get(i));
            else
            {
                String str = st.peek();
       
                // compare the current string with stack top
                // if equal, pop the top
                if (str.equals(v.get(i)))    
                    st.pop();
       
                // Otherwise push the current string
                else
                    st.push(v.get(i));
            }
        }
       
        // Return stack size
        return st.size();
    }
      
    // Driver method
    public static void main(String[] args) 
    {
        Vector<String> v = new Vector<>();
          
        v.addElement("ab"); v.addElement("aa");
        v.addElement("aa");v.addElement("bcd");
        v.addElement("ab");
          
        System.out.println(removeConsecutiveSame(v));
    }
}

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Python3

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# Python implementation of above method 
  
# Function to find the size of manipulated sequence 
def removeConsecutiveSame(v):
    st = []
  
    # Start traversing the sequence
    for i in range(len(v)):
          
        # Push the current string if the stack 
        # is empty 
        if (len(st) == 0): 
            st.append(v[i]) 
        else:
            Str = st[-1
  
            # compare the current string with stack top 
            # if equal, pop the top 
            if (Str == v[i]): 
                st.pop() 
  
            # Otherwise push the current string 
            else:
                st.append(v[i])
  
    # Return stack size 
    return len(st)
  
# Driver code 
if __name__ == '__main__':
    V = [ "ab", "aa", "aa", "bcd", "ab"
    print(removeConsecutiveSame(V))
  
# This code is contributed by PranchalK.

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C#

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// C# implementation of above method 
using System;
using System.Collections.Generic;
  
class GFG
{
// Method to find the size of 
// manipulated sequence 
public static int removeConsecutiveSame(List<string> v)
{
    Stack<string> st = new Stack<string>();
  
    // Start traversing the sequence 
    for (int i = 0; i < v.Count; i++)
    {
        // Push the current string if 
        // the stack is empty 
        if (st.Count == 0)
        {
            st.Push(v[i]);
        }
        else
        {
            string str = st.Peek();
  
            // compare the current string with  
            // stack top if equal, pop the top 
            if (str.Equals(v[i]))
            {
                st.Pop();
            }
  
            // Otherwise push the current 
            // string 
            else
            {
                st.Push(v[i]);
            }
        }
    }
  
    // Return stack size 
    return st.Count;
}
  
// Driver Code 
public static void Main(string[] args)
{
    List<string> v = new List<string>();
  
    v.Add("ab");
    v.Add("aa");
    v.Add("aa");
    v.Add("bcd");
    v.Add("ab");
  
    Console.WriteLine(removeConsecutiveSame(v));
}
}
  
// This code is contributed by Shrikant13

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Output:

3

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