Delete all nodes from the doubly linked list which are divisible by K

Given a doubly-linked list containing N nodes, the task is to delete all nodes from the list which are divisible by K.

Examples:

Input: List = 15 <=> 16 <=> 6 <=> 7 <=> 17, K = 2 
Output: Final List = 15 <=> 7 <=> 17

Input: List = 5 <=> 3 <=> 4 <=> 2 <=> 9, K = 3 
Output: Final List = 5 <=> 4 <=> 2 

Approach: The idea is to traverse the nodes of the doubly linked list one by one and get the pointer of the nodes which are divisible by K. Delete those nodes by following the approach used in this post.

Below is the implementation of the above idea: 

C++

// C++ implementation to delete all
// from the doubly linked list which
// are divisible by K

#include <bits/stdc++.h>

using namespace std;

// Node of the doubly linked list
struct Node {
    int data;
    Node *prev, *next;
};

// function to insert a node at the beginning
// of the Doubly Linked List
void push(Node** head_ref, int new_data)
{
    // allocate node
    Node* new_node = (Node*)malloc(sizeof(struct Node));

    // put in the data
    new_node->data = new_data;

    // since we are adding at the beginning,
    // prev is always NULL
    new_node->prev = NULL;

    // link the old list of the new node
    new_node->next = (*head_ref);

    // change prev of head node to new node
    if ((*head_ref) != NULL)
        (*head_ref)->prev = new_node;

    // move the head to point to the new node
    (*head_ref) = new_node;
}

// function to delete a node in a Doubly Linked List.
// head_ref --> pointer to head node pointer.
// del --> pointer to node to be deleted
void deleteNode(Node** head_ref, Node* del)
{
    // base case
    if (*head_ref == NULL || del == NULL)
        return;

    // If node to be deleted is head node
    if (*head_ref == del)
        *head_ref = del->next;

    // Change next only if node to be
    // deleted is NOT the last node
    if (del->next != NULL)
        del->next->prev = del->prev;

    // Change prev only if node to be
    // deleted is NOT the first node
    if (del->prev != NULL)
        del->prev->next = del->next;

    // Finally, free the memory occupied by del
    free(del);

    return;
}

// function to delete all nodes from the
// doubly linked list divisible by K
void deleteDivisibleNodes(Node** head_ref, int K)
{
    Node* ptr = *head_ref;
    Node* next;

    while (ptr != NULL) {
        next = ptr->next;
        // if true, delete node 'ptr'
        if (ptr->data % K == 0)
            deleteNode(head_ref, ptr);
        ptr = next;
    }
}

// function to print nodes in a
// given doubly linked list
void printList(Node* head)
{
    while (head != NULL) {
        cout << head->data << " ";
        head = head->next;
    }
}

// Driver program
int main()
{
    // start with the empty list
    Node* head = NULL;

    // create the doubly linked list
    // 15 <-> 16 <-> 7 <-> 6 <-> 17
    push(&head, 17);
    push(&head, 6);
    push(&head, 7);
    push(&head, 16);
    push(&head, 15);

    int K = 2;

    cout << "Original List: ";
    printList(head);

    deleteDivisibleNodes(&head, K);

    cout << "\nModified List: ";
    printList(head);
}

Java

// Java implementation to delete all
// from the doubly linked list which
// are divisible by K
class GFG
{

// Node of the doubly linked list
static class Node
{
    int data;
    Node prev, next;
};

// function to insert a node at the beginning
// of the Doubly Linked List
static Node push(Node head_ref, int new_data)
{
    // allocate node
    Node new_node = new Node();

    // put in the data
    new_node.data = new_data;

    // since we are adding at the beginning,
    // prev is always null
    new_node.prev = null;

    // link the old list of the new node
    new_node.next = (head_ref);

    // change prev of head node to new node
    if ((head_ref) != null)
        (head_ref).prev = new_node;

    // move the head to point to the new node
    (head_ref) = new_node;
    return head_ref;
}

// function to delete a node in a Doubly Linked List.
// head_ref -. pointer to head node pointer.
// del -. pointer to node to be deleted
static Node deleteNode(Node head_ref, Node del)
{
    // base case
    if (head_ref == null || del == null)
        return null;

    // If node to be deleted is head node
    if (head_ref == del)
        head_ref = del.next;

    // Change next only if node to be
    // deleted is NOT the last node
    if (del.next != null)
        del.next.prev = del.prev;

    // Change prev only if node to be
    // deleted is NOT the first node
    if (del.prev != null)
        del.prev.next = del.next;

    return head_ref;
}

// function to delete all nodes from the
// doubly linked list divisible by K
static Node deleteDivisibleNodes(Node head_ref, int K)
{
    Node ptr = head_ref;
    Node next;

    while (ptr != null)
    {
        next = ptr.next;

        // if true, delete node 'ptr'
        if (ptr.data % K == 0)
            deleteNode(head_ref, ptr);
        ptr = next;
    }
    return head_ref;
}

// function to print nodes in a
// given doubly linked list
static void printList(Node head)
{
    while (head != null)
    {
        System.out.print( head.data + " ");
        head = head.next;
    }
}

// Driver code
public static void main(String args[])
{
    // start with the empty list
    Node head = null;

    // create the doubly linked list
    // 15 <. 16 <. 7 <. 6 <. 17
    head = push(head, 17);
    head = push(head, 6);
    head = push(head, 7);
    head = push(head, 16);
    head = push(head, 15);

    int K = 2;

    System.out.print( "Original List: ");
    printList(head);

    head=deleteDivisibleNodes(head, K);

    System.out.print( "\nModified List: ");
    printList(head);
}
}

// This code is contributed by Arnab Kundu

Python3

    # Python3 implementation to delete all
# from the doubly linked list which
# are divisible by K
import math

# Node of the doubly linked list
class Node:
    def __init__(self,data):
        self.data = data
        self.next = None

# function to insert a node at the
# beginning of the Doubly Linked List
def push(head_ref, new_data):

    # allocate node
    new_node = Node(new_data)

    # put in the data
    new_node.data = new_data

    # since we are adding at the beginning,
    # prev is always None
    new_node.prev = None

    # link the old list of the new node
    new_node.next = head_ref

    # change prev of head node to new node
    if (head_ref != None):
        head_ref.prev = new_node

    # move the head to point
    # to the new node
    head_ref = new_node
    return head_ref

# function to delete a node
# in a Doubly Linked List.
# head_ref --> pointer to head node pointer.
# del --> pointer to node to be deleted
def deleteNode(head_ref, delete):

    # base case
    if (head_ref == None or delete == None):
        return

    # If node to be deleted is head node
    if (head_ref == delete):
        head_ref = delete.next

    # Change next only if node to be
    # deleted is NOT the last node
    if (delete.next != None):
        delete.next.prev = delete.prev

    # Change prev only if node to be
    # deleted is NOT the first node
    if (delete.prev != None):
        delete.prev.next = delete.next

    # Finally, free the memory
    # occupied by del, free(del)
    return

# function to delete all nodes from the
# doubly linked list divisible by K
def deleteDivisibleNodes(head_ref, K):
    ptr = head_ref
    #next

    while (ptr != None) :
        next = ptr.next

        # if true, delete node 'ptr'
        if (ptr.data % K == 0):
            deleteNode(head_ref, ptr)
        ptr = next

# function to print nodes in a
# given doubly linked list
def printList(head):
    while (head != None):
        print(head.data, end = " ")
        head = head.next

# Driver Code
if __name__=='__main__':

    # start with the empty list
    head = None

    # create the doubly linked list
    # 15 <- 16 <- 7 <- 6 <- 17
    head = push(head, 17)
    head = push(head, 6)
    head = push(head, 7)
    head = push(head, 16)
    head = push(head, 15)

    K = 2

    print("Original List: ", end = "")
    printList(head)

    deleteDivisibleNodes(head, K)

    print("\nModified List: ", end = "")
    printList(head)

# This code is contributed by AbhiThakur

C#

// C# implementation to delete all
// from the doubly linked list which
// are divisible by K
using System;

class GFG
{

// Node of the doubly linked list
public class Node
{
    public int data;
    public Node prev, next;
};

// function to insert a node at the beginning
// of the Doubly Linked List
static Node push(Node head_ref, int new_data)
{
    // allocate node
    Node new_node = new Node();

    // put in the data
    new_node.data = new_data;

    // since we are adding at the beginning,
    // prev is always null
    new_node.prev = null;

    // link the old list of the new node
    new_node.next = (head_ref);

    // change prev of head node to new node
    if ((head_ref) != null)
        (head_ref).prev = new_node;

    // move the head to point to the new node
    (head_ref) = new_node;
    return head_ref;
}

// function to delete a node in a Doubly Linked List.
// head_ref -. pointer to head node pointer.
// del -. pointer to node to be deleted
static Node deleteNode(Node head_ref, Node del)
{
    // base case
    if (head_ref == null || del == null)
        return null;

    // If node to be deleted is head node
    if (head_ref == del)
        head_ref = del.next;

    // Change next only if node to be
    // deleted is NOT the last node
    if (del.next != null)
        del.next.prev = del.prev;

    // Change prev only if node to be
    // deleted is NOT the first node
    if (del.prev != null)
        del.prev.next = del.next;

    return head_ref;
}

// function to delete all nodes from the
// doubly linked list divisible by K
static Node deleteDivisibleNodes(Node head_ref, int K)
{
    Node ptr = head_ref;
    Node next;

    while (ptr != null)
    {
        next = ptr.next;

        // if true, delete node 'ptr'
        if (ptr.data % K == 0)
            deleteNode(head_ref, ptr);
        ptr = next;
    }
    return head_ref;
}

// function to print nodes in a
// given doubly linked list
static void printList(Node head)
{
    while (head != null)
    {
        Console.Write( head.data + " ");
        head = head.next;
    }
}

// Driver code
public static void Main(String []args)
{
    // start with the empty list
    Node head = null;

    // create the doubly linked list
    // 15 <. 16 <. 7 <. 6 <. 17
    head = push(head, 17);
    head = push(head, 6);
    head = push(head, 7);
    head = push(head, 16);
    head = push(head, 15);

    int K = 2;

    Console.Write( "Original List: ");
    printList(head);

    head = deleteDivisibleNodes(head, K);

    Console.Write( "\nModified List: ");
    printList(head);
}
}

// This code contributed by Rajput-Ji

Javascript

<script>
// javascript implementation to delete all
// from the doubly linked list which
// are divisible by K     // Node of the doubly linked list
     class Node {
        constructor(val) {
            this.data = val;
            this.prev = null;
            this.next = null;
        }
    }

    // function to insert a node at the beginning
    // of the Doubly Linked List
    function push(head_ref , new_data) {
        // allocate node
var new_node = new Node();

        // put in the data
        new_node.data = new_data;

        // since we are adding at the beginning,
        // prev is always null
        new_node.prev = null;

        // link the old list of the new node
        new_node.next = (head_ref);

        // change prev of head node to new node
        if ((head_ref) != null)
            (head_ref).prev = new_node;

        // move the head to point to the new node
        (head_ref) = new_node;
        return head_ref;
    }

    // function to delete a node in a Doubly Linked List.
    // head_ref -. pointer to head node pointer.
    // del -. pointer to node to be deleted
    function deleteNode(head_ref,  del) {
        // base case
        if (head_ref == null || del == null)
            return null;

        // If node to be deleted is head node
        if (head_ref == del)
            head_ref = del.next;

        // Change next only if node to be
        // deleted is NOT the last node
        if (del.next != null)
            del.next.prev = del.prev;

        // Change prev only if node to be
        // deleted is NOT the first node
        if (del.prev != null)
            del.prev.next = del.next;

        return head_ref;
    }

    // function to delete all nodes from the
    // doubly linked list divisible by K
    function deleteDivisibleNodes(head_ref , K) {
var ptr = head_ref;
var next;

        while (ptr != null) {
            next = ptr.next;

            // if true, delete node 'ptr'
            if (ptr.data % K == 0)
                deleteNode(head_ref, ptr);
            ptr = next;
        }
        return head_ref;
    }

    // function to print nodes in a
    // given doubly linked list
    function printList(head) {
        while (head != null) {
            document.write(head.data + " ");
            head = head.next;
        }
    }

    // Driver code

        // start with the empty list
var head = null;

        // create the doubly linked list
        // 15 <. 16 <. 7 <. 6 <. 17
        head = push(head, 17);
        head = push(head, 6);
        head = push(head, 7);
        head = push(head, 16);
        head = push(head, 15);

        var K = 2;

        document.write("Original List: ");
        printList(head);

        head = deleteDivisibleNodes(head, K);

        document.write("<br/>Modified List: ");
        printList(head);

// This code is contributed by todaysgaurav
</script>

Output

Original List: 15 16 7 6 17 
Modified List: 15 7 17 

Complexity Analysis:

• Time Complexity: O(N), where N is the total number of nodes.
• Space Complexity: O(1) since using constant variables