Given a stack with n elements, the task is to remove all the elements of the stack without affecting the order of elements.
Input : s = 16 <- 15 <- 29 <- 24 <- 19 (TOP)
Output: 19 29 15
19 29 15 is the order of odd elements in which
they will be popped from the given stack.
Input : s = 1 <- 2 <- 3 <- 4 <- 5 (TOP)
Output: 5 3 1
- Create a temporary stack temp and start popping the elements of the given stack s.
- For every popped element say val, if val % 2 == 1 then push it to temp.
- At the end of step 2, temp will contain all the odd elements from s but in reverse order.
- Now, to get the original order, pop every element from temp and push it to s.
Below is the implementation of the above approach:
19 29 15
- Delete middle element of a stack
- Print Stack Elements from Bottom to Top
- Check if the elements of stack are pairwise sorted
- Check if stack elements are pairwise consecutive
- Design a stack to retrieve original elements and return the minimum element in O(1) time and O(1) space
- Delete array elements which are smaller than next or become smaller
- Infix to Postfix using different Precedence Values for In-Stack and Out-Stack
- Stack Permutations (Check if an array is stack permutation of other)
- Find maximum in stack in O(1) without using additional stack
- Sort a stack using a temporary stack
- Stack | Set 3 (Reverse a string using stack)
- Delete consecutive same words in a sequence
- Delete all the even nodes from a Doubly Linked List
- Delete all odd or even positioned nodes from Circular Linked List
- Delete all the nodes from the doubly linked list that are greater than a given value
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