Decimal.ToInt32() Method in C#
Last Updated :
30 Jan, 2019
This method is used to convert the value of the specified Decimal to the equivalent 32-bit signed integer. A user can also convert a Decimal value to a 32-bit integer by using the Explicit assignment operator.
Syntax: public static int ToInt32 (decimal value);
Here, the value is the decimal number which is to be converted.
Return Value: It returns a 32-bit signed integer equivalent to the specified value.
Exception: This method will give OverflowException if the specified value is less than MinValue or greater than MaxValue.
Below programs illustrate the use of the above-discussed method:
Example 1:
using System;
class GFG {
public static void Main()
{
try {
Decimal dec1 = 2147483647M;
Decimal dec2 = 21458565.2996m;
int val1 = Decimal.ToInt32(dec1);
int val2 = Decimal.ToInt32(dec2);
Console.WriteLine( "The Int32 value "
+ "is : {0}" , val1);
Console.WriteLine( "The Int32 value "
+ "is : {0}" , val2);
}
catch (OverflowException e)
{
Console.Write( "Exception Thrown: " );
Console.Write( "{0}" , e.GetType(), e.Message);
}
}
}
|
Output:
The Int32 value is : 2147483647
The Int32 value is : 21458565
Example 2: For OverflowException
using System;
class GFG {
public static void Main()
{
try {
Decimal dec1 = 2147483648M;
Decimal dec2 = Decimal.MaxValue;
int val1 = Decimal.ToInt32(dec1);
int val2 = Decimal.ToInt32(dec2);
Console.WriteLine( "The Int32 value "
+ "is : {0}" , val1);
Console.WriteLine( "The Int32 value "
+ "is : {0}" , val2);
}
catch (OverflowException e)
{
Console.Write( "Exception Thrown: " );
Console.Write( "{0}" , e.GetType(), e.Message);
}
}
}
|
Output:
Exception Thrown: System.OverflowException
Reference:
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