Decimal to Binary using recursion and without using power operator

Given an integer N, the task is convert and print the binary equaiva;ent of N.
Examples:

Input: N = 13 
Output: 1101
Input: N = 15 
Output: 1111 

Approach Write a recursive function that takes an argument N and recursively calls itself with the value N / 2 as the new argument and prints N % 2 after the call. The base condition will be when N = 0, simply print 0 and return out of the function in that case.
Below is the implementation of the above approach: 

C++

// C++ implementation of the approach
#include <bits/stdc++.h>
using namespace std;

// Recursive function to convert n
// to its binary equivalent
void decimalToBinary(int n)
{
    // Base case
    if (n == 0) {
        cout << "0";
        return;
    }

    // Recursive call
    decimalToBinary(n / 2);
    cout << n % 2;
}

// Driver code
int main()
{
    int n = 13;

    decimalToBinary(n);

    return 0;
}

Java

// Java implementation of the approach
import java.io.*;

class GFG
{


// Recursive function to convert n
// to its binary equivalent
static void decimalToBinary(int n)
{
    // Base case
    if (n == 0)
    {
        System.out.print("0");
        return;
    }

    // Recursive call
    decimalToBinary(n / 2);
    System.out.print( n % 2);
}

// Driver code
public static void main (String[] args)
{
    int n = 13;

    decimalToBinary(n);
}
}

// This code is contributed by anuj_67..

Python3

# Python3 implementation of the approach

# Recursive function to convert n
# to its binary equivalent
def decimalToBinary(n) :

    # Base case
    if (n == 0) :
        print("0",end="");
        return;

    # Recursive call
    decimalToBinary(n // 2);
    print(n % 2,end="");


# Driver code
if __name__ == "__main__" :

    n = 13;
    decimalToBinary(n);

# This code is contributed by AnkitRai01

C#

// C# implementation of the approach
using System;

class GFG
{

    // Recursive function to convert n
    // to its binary equivalent
    static void decimalToBinary(int n)
    {

        // Base case
        if (n == 0)
        {
            Console.Write("0");
            return;
        }

        // Recursive call
        decimalToBinary(n / 2);
        Console.Write(n % 2);
    }

    // Driver code
    public static void Main(String[] args)
    {
        int n = 13;

        decimalToBinary(n);
    }
}

// This code is contributed by 29AjayKumar

Javascript

<script>
// javascript implementation of the approach

    // Recursive function to convert n
    // to its binary equivalent
    function decimalToBinary(n) {
        // Base case
        if (n == 0) {
            document.write("0");
            return;
        }

        // Recursive call
        decimalToBinary(parseInt(n / 2));
        document.write(n % 2);
    }

    // Driver code

        var n = 13;

        decimalToBinary(n);

// This code contributed by gauravrajput1
</script>

Output:

01101

Time Complexity: O(logN)
Auxiliary Space: O(logN)