D3.js symbol.type() Method

Last Updated : 18 Sep, 2020

The symbol.type() method takes a symbol type, sets the generators symbol that it will generate. The default symbol type, if not set, is d3.symbolCircle.

Syntax:

symbol.type([type])

Parameters: This function accepts a single parameter as mentioned above and described below:

type: This is the type of symbol to be set.

Return Value: This method has no return value.

Example 1:

HTML

<!DOCTYPE html> 
<html> 
<head> 
    <meta charset="utf-8"> 
  
    <script src= 
        "https://d3js.org/d3.v5.min.js"> 
    </script> 
</head> 
  
<body> 
  
    <h1 style="text-align:center; color:green;"> 
        GeeksforGeeks 
    </h1> 
  
    <h3 style="text-align: center;"> 
        D3.js | symbol.type() Method 
    </h3> 
  
    <center> 
    <svg id="gfg" width="100" height="100"></svg> 
    </center> 
  
    <script> 
        var sym = d3.symbol() 
            .type(d3.symbolSquare).size(500); 
        d3.select("#gfg") 
            .append("path") 
            .attr("d", sym) 
            .attr("fill", "green") 
            .attr("transform", "translate(50,50)"); 
  
    </script> 
</body> 
  
</html>

Output:

Example 2:

HTML

<!DOCTYPE html> 
<html> 
<head> 
    <meta charset="utf-8"> 
  
    <script src= 
        "https://d3js.org/d3.v5.min.js"> 
    </script> 
</head> 
  
<body> 
    <h1 style="text-align:center; color:green;"> 
        GeeksforGeeks 
    </h1> 
  
    <h3 style="text-align: center;"> 
        D3.js | symbol.type() Method 
    </h3> 
  
    <center> 
    <svg id="gfg" width="100" height="100"></svg> 
    </center> 
  
    <script> 
        var sym = d3.symbol() 
            .type(d3.symbolCircle).size(500); 
        d3.select("#gfg") 
            .append("path") 
            .attr("d", sym) 
            .attr("fill", "green") 
            .attr("transform", "translate(50,50)"); 
    </script> 
</body> 
  
</html>