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D3.js symbol.type() Method

  • Last Updated : 18 Sep, 2020

The symbol.type() method takes a symbol type, sets the generators symbol that it will generate. The default symbol type, if not set, is d3.symbolCircle.

Syntax:

symbol.type([type])

Parameters: This function accepts a single parameter as mentioned above and described below:

  • type: This is the type of symbol to be set.

Return Value: This method has no return value.

Example 1:



HTML




<!DOCTYPE html>
<html>
<head>
    <meta charset="utf-8">
  
    <script src=
    </script>
</head>
  
<body>
  
    <h1 style="text-align:center; color:green;">
        GeeksforGeeks
    </h1>
  
    <h3 style="text-align: center;">
        D3.js | symbol.type() Method
    </h3>
  
    <center>
    <svg id="gfg" width="100" height="100"></svg>
    </center>
  
    <script>
        var sym = d3.symbol()
            .type(d3.symbolSquare).size(500);
        d3.select("#gfg")
            .append("path")
            .attr("d", sym)
            .attr("fill", "green")
            .attr("transform", "translate(50,50)");
  
    </script>
</body>
  
</html>

Output:

Example 2:

HTML




<!DOCTYPE html>
<html>
<head>
    <meta charset="utf-8">
  
    <script src=
    </script>
</head>
  
<body>
    <h1 style="text-align:center; color:green;">
        GeeksforGeeks
    </h1>
  
    <h3 style="text-align: center;">
        D3.js | symbol.type() Method
    </h3>
  
    <center>
    <svg id="gfg" width="100" height="100"></svg>
    </center>
  
    <script>
        var sym = d3.symbol()
            .type(d3.symbolCircle).size(500);
        d3.select("#gfg")
            .append("path")
            .attr("d", sym)
            .attr("fill", "green")
            .attr("transform", "translate(50,50)");
    </script>
</body>
  
</html>

Output:




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