D3.js | d3.timeYear Function
Last Updated :
25 Jul, 2019
The d3.timeYear function in D3.js is used to return all the years with date in the given range of start and end date.
Syntax:
d3.timeYear.range(start, end, step);
Parameters: This function accept three parameters which are given below:
- Start: This parameter holds the given start date.
- end: This parameter holds the given end date.
- step: It is the optional parameter which holds the value used to skip years.
Return Value: This function returns all the possible years in the given range.
Below programs illustrate the d3.timeYear function in D3.js:
Example 1:
<!DOCTYPE html>
<html>
<head>
<title>
D3.js | d3.timeYear Function
</title>
<script src =
</script>
</head>
<body>
<script>
var start = new Date(2015, 01, 01);
var end = new Date(2020, 01, 01);
var a = d3.timeYear.range(start, end);
console.log(a);
</script>
</body>
</html>
|
Output:
["2015-12-31T18:30:00.000Z","2016-12-31T18:30:00.000Z",
"2017-12-31T18:30:00.000Z","2018-12-31T18:30:00.000Z",
"2019-12-31T18:30:00.000Z"]
Example 2:
<!DOCTYPE html>
<html>
<head>
<title>
D3.js | d3.timeYear Function
</title>
<script src =
</script>
</head>
<body>
<script>
var start = new Date(2015, 01, 01);
var end = new Date(2020, 01, 01);
var a = d3.timeYear.range(start, end, 2);
console.log(a);
</script>
</body>
</html>
|
Output:
["2015-12-31T18:30:00.000Z","2017-12-31T18:30:00.000Z",
"2019-12-31T18:30:00.000Z"]
Reference: https://devdocs.io/d3~5/d3-time#timeYear
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