D3.js | d3.timeTuesdays() Function

The d3.timeTuesdays() function in D3.js is used to return all the dates based on Tuesday in the given range of start and end date.

Syntax:

d3.timeTuesdays(start, end, step);

Parameters: This function accept three parameters which are given below:

Start: This is the given start date.
end: This is the given end date.
step: This is the optional value used to skip dates.

Return Value: This function returns all the dates based on Tuesday.

Below programs illustrate the d3.timeTuesdays() function in D3.js:

Example 1:

<!DOCTYPE html> 
<html> 
  
<head> 
    <title> 
        D3.js | d3.timeTuesdays() Function 
    </title> 
      
    <script src= 
        "https://d3js.org/d3.v4.min.js"> 
    </script> 
</head> 
  
<body> 
    <script> 
      
        // Initialising start and end date 
        var start = new Date(2015, 07, 01); 
        var end = new Date(2015, 07, 30); 
  
        // Calling the timeTuesdays() function 
        // without step value 
        var a = d3.timeTuesdays(start, end); 
  
        // Getting the Tuesday dates 
        console.log(a); 
    </script> 
</body> 
  
</html> 

Output:

[“2015-08-03T18:30:00.000Z”, “2015-08-10T18:30:00.000Z”, “2015-08-17T18:30:00.000Z”, “2015-08-24T18:30:00.000Z”]

Example 2:

<!DOCTYPE html> 
<html> 
  
<head> 
    <title> 
        D3.js | d3.timeTuesdays() Function 
    </title> 
      
    <script src= 
        "https://d3js.org/d3.v4.min.js"> 
    </script> 
</head> 
  
<body> 
    <script> 
      
        // Initialising start and end date 
        var start = new Date(2015, 07, 01); 
        var end = new Date(2015, 07, 30); 
   
        // Calling the timeTuesdays() function 
        // with step value 
        var a = d3.timeTuesdays(start, end, 2); 
   
        // Getting the Tuesday dates 
        console.log(a); 
    </script> 
</body> 
  
</html> 

Output:

["2015-08-03T18:30:00.000Z", "2015-08-17T18:30:00.000Z"]

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