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D3.js | d3.timeTuesdays() Function
  • Last Updated : 23 Jul, 2019

The d3.timeTuesdays() function in D3.js is used to return all the dates based on Tuesday in the given range of start and end date.

Syntax:

d3.timeTuesdays(start, end, step);

Parameters: This function accept three parameters which are given below:

  • Start: This is the given start date.
  • end: This is the given end date.
  • step: This is the optional value used to skip dates.

Return Value: This function returns all the dates based on Tuesday.

Below programs illustrate the d3.timeTuesdays() function in D3.js:



Example 1:

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<!DOCTYPE html>
<html>
  
<head>
    <title>
        D3.js | d3.timeTuesdays() Function
    </title>
      
    <script src=
        "https://d3js.org/d3.v4.min.js">
    </script>
</head>
  
<body>
    <script>
      
        // Initialising start and end date
        var start = new Date(2015, 07, 01);
        var end = new Date(2015, 07, 30);
  
        // Calling the timeTuesdays() function
        // without step value
        var a = d3.timeTuesdays(start, end);
  
        // Getting the Tuesday dates
        console.log(a);
    </script>
</body>
  
</html>

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Output:

[“2015-08-03T18:30:00.000Z”, “2015-08-10T18:30:00.000Z”, “2015-08-17T18:30:00.000Z”, “2015-08-24T18:30:00.000Z”]

Example 2:

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<!DOCTYPE html>
<html>
  
<head>
    <title>
        D3.js | d3.timeTuesdays() Function
    </title>
      
    <script src=
        "https://d3js.org/d3.v4.min.js">
    </script>
</head>
  
<body>
    <script>
      
        // Initialising start and end date
        var start = new Date(2015, 07, 01);
        var end = new Date(2015, 07, 30);
   
        // Calling the timeTuesdays() function
        // with step value
        var a = d3.timeTuesdays(start, end, 2);
   
        // Getting the Tuesday dates
        console.log(a);
    </script>
</body>
  
</html>

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Output:

["2015-08-03T18:30:00.000Z", "2015-08-17T18:30:00.000Z"]

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