D3.js | d3.timeTuesdays() Function
The d3.timeTuesdays() function in D3.js is used to return all the dates based on Tuesday in the given range of start and end date.
Syntax:
d3.timeTuesdays(start, end, step);
Parameters: This function accept three parameters which are given below:
- Start: This is the given start date.
- end: This is the given end date.
- step: This is the optional value used to skip dates.
Return Value: This function returns all the dates based on Tuesday.
Below programs illustrate the d3.timeTuesdays() function in D3.js:
Example 1:
<!DOCTYPE html> <html> <head> <title> D3.js | d3.timeTuesdays() Function </title> <script src= </script> </head> <body> <script> // Initialising start and end date var start = new Date(2015, 07, 01); var end = new Date(2015, 07, 30); // Calling the timeTuesdays() function // without step value var a = d3.timeTuesdays(start, end); // Getting the Tuesday dates console.log(a); </script> </body> </html> |
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Output:
[“2015-08-03T18:30:00.000Z”, “2015-08-10T18:30:00.000Z”, “2015-08-17T18:30:00.000Z”, “2015-08-24T18:30:00.000Z”]
Example 2:
<!DOCTYPE html> <html> <head> <title> D3.js | d3.timeTuesdays() Function </title> <script src= </script> </head> <body> <script> // Initialising start and end date var start = new Date(2015, 07, 01); var end = new Date(2015, 07, 30); // Calling the timeTuesdays() function // with step value var a = d3.timeTuesdays(start, end, 2); // Getting the Tuesday dates console.log(a); </script> </body> </html> |
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Output:
["2015-08-03T18:30:00.000Z", "2015-08-17T18:30:00.000Z"]
