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D3.js | d3.min() function

  • Last Updated : 28 Jun, 2019

The d3.min() function in D3.js is used to returns the minimum value in the given array using natural order. If an array is empty then it returns undefined as output.

Syntax:

d3.min(Array)

Parameters: This function accepts a parameters Array which is an array of elements whose minimum value is to be calculated. Here elements might be integers or any strings.

Return Value: It returns the minimum value.

Below programs illustrate the d3.min() function in D3.js.



Example 1:




<html>
  
<head>
    <title>Getting minimum value</title>
</head>
  
<body>
    <script src='https://d3js.org/d3.v4.min.js'>
  </script>
  
    <script>
        // initialising the array of elements
        var Array1 = [10, 20, 30, 40, 50, 60];
        var Array2 = [1, 2];
        var Array3 = [0, 1.5, 6.8];
        var Array4 = [.8, .08, .008];
  
        // Calling to d3.min() function
        A = d3.min(Array1);
        B = d3.min(Array2);
        C = d3.min(Array3);
        D = d3.min(Array4);
  
        // Getting minimum value
        document.write(A + "<br>");
        document.write(B + "<br>");
        document.write(C + "<br>");
        document.write(D + "<br>");
    </script>
</body>
  
</html>

Output:

10
1
0
0.008

Example 2:




<html>
  
<head>
    <title>Getting minimum value</title>
</head>
  
<body>
    <script src='https://d3js.org/d3.v4.min.js'>
  </script>
  
    <script>
        // initialising the array of elements
        var Array1 = [];
        var Array2 = ["a", "b", "c"];
        var Array3 = ["A", "B", "C"];
        var Array4 = ["Geek", "Geeks", "GeeksforGeeks"];
  
        // Calling to d3.min() function
        A = d3.min(Array1);
        B = d3.min(Array2);
        C = d3.min(Array3);
        D = d3.min(Array4);
  
        // Getting minimum value
        document.write(A + "<br>");
        document.write(B + "<br>");
        document.write(C + "<br>");
        document.write(D + "<br>");
    </script>
</body>
  
</html>

Output:

undefined
a
A
Geek



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