D3.js | d3.extent() function
Last Updated :
26 Jun, 2019
The d3.extent() function in D3.js is used to returns the minimum and maximum value in an array from the given array using natural order. If an array is empty then it returns undefined, undefined as output.
Syntax:
d3.extent(Array)
Parameters: This function accepts a parameters Array which is an array of elements whose minimum and maximum value in an array are to be calculated. Here elements might be integers or any strings.
Return Value: It returns the minimum and maximum value in an array from the given array.
Below programs illustrate the d3.extent() function in D3.js.
Example 1:
<html>
<head>
<title>
Getting minimum and
maximum value in an array
</title>
</head>
<body>
</script>
<script>
var Array1 = [10, 20, 30, 40, 50, 60];
var Array2 = [1, 2];
var Array3 = [0, 1.5, 6.8];
var Array4 = [.8, .08, .008];
A = d3.extent(Array1);
B = d3.extent(Array2);
C = d3.extent(Array3);
D = d3.extent(Array4);
document.write(A + "<br>");
document.write(B + "<br>");
document.write(C + "<br>");
document.write(D + "<br>");
</script>
</body>
</html>
|
Output:
10, 60
1, 2
0, 6.8
0.008, 0.8
Example 2:
<html>
<head>
<title>
Getting minimum
and maximum value
</title>
</head>
<body>
</script>
<script>
var Array1 = [];
var Array2 = ["a", "b", "c"];
var Array3 = ["A", "B", "C"];
var Array4 = ["Geek", "Geeks", "GeeksforGeeks"];
A = d3.extent(Array1);
B = d3.extent(Array2);
C = d3.extent(Array3);
D = d3.extent(Array4);
document.write(A + "<br>");
document.write(B + "<br>");
document.write(C + "<br>");
document.write(D + "<br>");
</script>
</body>
</html>
|
Output:
undefined, undefined
a, c
A, C
Geek, GeeksforGeeks
Note: In the above output, first element is minimum value and second element is maximum value.
Ref: https://devdocs.io/d3~4/d3-array#extent
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