Cyclic shifts of integer N by another integer m

Given an integer N represented as a binary representation of X = 16 bits. We are also given a number ‘m’ and a character c which is either L or R. The task is to determine a number M that is generated after cyclically shifting the binary representation of N by m positions either left if c = L or right if c = R.

Examples:

Input : N = 7881, m = 5, c = L
Output : 55587
Explanation:
N in binary is 0001 1110 1100 1001 and shifting it left by 5 positions, it becomes 1101 1001 0010 0011 which in the decimal system is 55587.

Input : N = 7881, m = 3, c = R
Output : 9177
Explanation:
N in binary is 0001 1110 1100 1001 and shifted 3 positions to right, it becomes 0010 0011 1101 1001 which in the decimal system is 9177.

Approach:



To solve the problem mentioned above we observe that we have to right shift the number by m if the char is R, else we will do a left shift by m if the char is L where left shifts is equivalent to multiplying a number by 2, right shifts is equivalent to dividing a number by 2.

Below is the implementation of the above approach:

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# Python implementation to make 
# Cyclic shifts of integer N by another integer m
  
def Count(N, count, turn):
    # Convert N into hexadecimal number and
    # remove the initial zeros in it
    N = hex(int(N)).split('x')[-1]
      
    # Convert hexadecimal term binary
    # string of length = 16 with padded 0s
    S = ( bin(int(N, 16))[2:] ).zfill(16)
      
     
    # rotate the string by a specific count
    if(turn == 'R'):
        S = (S[16 - int(count) : ] + S[0 : 16 - int(count)])
          
    else:
        S = (S[int(count) : ] + S[0 : int(count)])
          
    # Convert the rotated binary string
    # in decimal form, here 2 means in binary form.
    print(int(S, 2))
      
# driver code 
N = 7881
count = 5
turn = 'L'
  
Count(N, count, turn)

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Output:

55587

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