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# C# Program to Count trailing zeroes in factorial of a number

• Last Updated : 02 Jan, 2019

Given an integer n, write a function that returns count of trailing zeroes in n!.

Examples :

```Input: n = 5
Output: 1
Factorial of 5 is 120 which has one trailing 0.

Input: n = 20
Output: 4
Factorial of 20 is 2432902008176640000 which has
4 trailing zeroes.

Input: n = 100
Output: 24
```
```Trailing 0s in n! = Count of 5s in prime factors of n!
= floor(n/5) + floor(n/25) + floor(n/125) + ....
```

## C#

 `// C# program to count``// trailing 0s in n!``using` `System;`` ` `class` `GFG {`` ` `    ``// Function to return trailing``    ``// 0s in factorial of n``    ``static` `int` `findTrailingZeros(``int` `n)``    ``{``        ``// Initialize result``        ``int` `count = 0;`` ` `        ``// Keep dividing n by powers``        ``// of 5 and update count``        ``for` `(``int` `i = 5; n / i >= 1; i *= 5)``            ``count += n / i;`` ` `        ``return` `count;``    ``}`` ` `    ``// Driver Code``    ``public` `static` `void` `Main()``    ``{``        ``int` `n = 100;``        ``Console.WriteLine(``"Count of trailing 0s in "` `                ``+ n + ``"! is "` `+ findTrailingZeros(n));``    ``}``}`` ` `// This code is contributed by vt_m`
Output:
```Count of trailing 0s in 100! is 24
```

Please refer complete article on Count trailing zeroes in factorial of a number for more details!

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