Given two linked list of equal sizes, the task is to create new linked list using those linked lists where at every step, the maximum of the two elements from both the linked lists is chosen and the other is skipped.
list1 = 5 -> 2 -> 3 -> 8 -> NULL
list2 = 1 -> 7 -> 4 -> 5 -> NULL
Output: 5 -> 7 -> 4 -> 8 -> NULL
list1 = 2 -> 8 -> 9 -> 3 -> NULL
list2 = 5 -> 3 -> 6 -> 4 -> NULL
Output: 5 -> 8 -> 9 -> 4 -> NULL
Approach: We traverse both the linked list at the same time and compare node from both the lists. The node which is greater among them, will be added to the new linked list. We do this for each node and then print the nodes of the generated linked list.
Below is the implementation of the above approach:
5 -> 7 -> 4 -> 8 -> NULL
- Create new linked list from two given linked list with greater element at each node
- Construct a Maximum Sum Linked List out of two Sorted Linked Lists having some Common nodes
- Insert a whole linked list into other at k-th position
- Rotate the sub-list of a linked list from position M to N to the right by K places
- First common element in two linked lists
- Make a loop at k-th position in a linked list
- Delete a Linked List node at a given position
- Create linked list from a given array
- Insert a node at a specific position in a linked list
- Insert N elements in a Linked List one after other at middle position
- Delete a Doubly Linked List node at a given position
- Insertion at Specific Position in a Circular Doubly Linked List
- Create a sorted linked list from the given Binary Tree
- Create a Doubly Linked List from a Ternary Tree
- Divide the given linked list in two lists of size ratio p:q
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