C++ Program to Store Information of a Student in a Structure
Arrays are used to store sets of data of similar data types at contiguous memory locations. Unlike Arrays, Structures are user-defined data types that are used to store groups of items of non-similar data types. Here, we are going to compile a C++ program that will store the information of the students in a Structure.
Following is the information we will store in the structure:
- Student Name (String)
- Student Roll Number (String)
- Subjects Enrolled (Array of Strings)
- Marks in each subject (Array of Int)
- CGPA(Float)
Examples:
Yash Gupta S20200010234 [DSA, OOPS ,DBMS, CCN] [89,78,86,90] 8.918
For a Student
C++
// C++ program to demonstrate // a structure for student details #include <bits/stdc++.h> using namespace std; // Structure Of students struct student { string name; // Student Name string rollno; // Student Roll Number vector<string> subjects; // Subjects Enrolled(Array) vector< int > marks; // Marks in each subject(Array) float cgpa; // Student's CGPA }; // Function to print a vector(for more "Different ways to // print elements of vector" at GFG) template < typename S> void printv( const vector<S>& v) { cout << "[ " ; // Iterating over all elements of vector for ( auto elem : v) { cout << elem << " " ; } cout << "]" ; cout << endl; } // Function to print a Student void printStudent(student* s) { cout << "Student Details:" << endl; cout << endl; cout << "Name: " << s->name << endl; cout << "Roll Number: " << s->rollno << endl; cout << "Subjects: " ; printv(s->subjects); cout << "Marks: " ; printv(s->marks); cout << "CGPA " << s->cgpa << endl; } // Driver Code int main() { // New Student student s; // Declaring all the information of a student s.name = "GeeksforGeeks" ; s.rollno = "S20200010234" ; s.subjects = { "DSA" , "OOPS" , "DBMS" , "CCN" }; s.marks = { 89, 78, 86, 90 }; s.cgpa = 8.918; // Function call to print a Student printStudent(&s); return 0; } |
Output
Student Details: Name: GeeksforGeeks Roll Number: S20200010234 Subjects: [ DSA OOPS DBMS CCN ] Marks: [ 89 78 86 90 ] CGPA 8.918
For a Student (Array)
These two details will also be added with the old detail to showcase the use of structure with multiple parameters.
GFG S20200010164 [DSA, OOPS ,DBMS, CCN] [89,80,89,80] 8.45
gfg Roll Number: S20200010169 Subjects: [ DSA OOPS DBMS CCN ] Marks: [ 99 0 99 90 ] CGPA 9.47
C++
// C++ program to demonstrate a // structure for multiple student details #include <bits/stdc++.h> using namespace std; // Structure Of students struct student { string name; string rollno; // Subjects Enrolled(Array) vector<string> subjects; // Marks in each subject(Array) vector< int > marks; // Student's CGPA float cgpa; }; // Function to print a vector // (for more "Different ways to // print elements of vector" at GFG) template < typename S> void printv( const vector<S>& v) { cout << "[ " ; // Iterating over all elements of vector for ( auto elem : v) { cout << elem << " " ; } cout << "]" ; cout << endl; } // Function to print a Student void printStudent(student* s) { cout << "Student Details:" << endl; cout << endl; cout << "Name: " << s->name << endl; cout << "Roll Number: " << s->rollno << endl; cout << "Subjects: " ; printv(s->subjects); cout << "Marks: " ; printv(s->marks); cout << "CGPA " << s->cgpa << endl; } // Driver Code int main() { // Array of Students student arrayofstudents[10]; // Student 1 arrayofstudents[0].name = "GeeksforGeeks" ; arrayofstudents[0].rollno = "S20200010234" ; arrayofstudents[0].subjects = { "DSA" , "OOPS" , "DBMS" , "CCN" }; arrayofstudnets[0].marks = { 89, 78, 86, 90 }; arrayofstudnets[0].cgpa = 8.918; // Student 2 arrayofstudnets[1].name = "GFG" ; arrayofstudnets[1].rollno = "S20200010164" ; arrayofstudnets[1].subjects = { "DSA" , "OOPS" , "DBMS" , "CCN" }; arrayofstudnets[1].marks = { 89, 80, 89, 80 }; arrayofstudnets[1].cgpa = 8.45; // Student 3 arrayofstudnets[2].name = "gfg" ; arrayofstudnets[2].rollno = "S20200010169" ; arrayofstudnets[2].subjects = { "DSA" , "OOPS" , "DBMS" , "CCN" }; arrayofstudnets[2].marks = { 99, 00, 99, 90 }; arrayofstudnets[2].cgpa = 9.47; // Loop to print all students for ( int i = 0; i < 3; i++) { // Function call printStudent(&arrayofstudnets[i]); } return 0; } |
Output
Student Details: Name: GeeksforGeeks Roll Number: S20200010234 Subjects: [ DSA OOPS DBMS CCN ] Marks: [ 89 78 86 90 ] CGPA 8.918 Student Details: Name: GFG Roll Number: S20200010164 Subjects: [ DSA OOPS DBMS CCN ] Marks: [ 89 80 89 80 ] CGPA 8.45 Student Details: Name: gfg Roll Number: S20200010169 Subjects: [ DSA OOPS DBMS CCN ] Marks: [ 99 0 99 90 ] CGPA 9.47
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