C++ Program to Print a given matrix in reverse spiral form
Last Updated :
17 Aug, 2023
Given a 2D array, print it in reverse spiral form. We have already discussed Print a given matrix in spiral form. This article discusses how to do the reverse printing. See the following examples.
Input:
1 2 3 4
5 6 7 8
9 10 11 12
13 14 15 16
Output:
10 11 7 6 5 9 13 14 15 16 12 8 4 3 2 1
Input:
1 2 3 4 5 6
7 8 9 10 11 12
13 14 15 16 17 18
Output:
11 10 9 8 7 13 14 15 16 17 18 12 6 5 4 3 2 1
C++
#include <iostream>
#define R 3
#define C 6
using namespace std;
void ReversespiralPrint( int m, int n, int a[R][C])
{
long int b[100];
int i, k = 0, l = 0;
int z = 0;
int size = m*n;
while (k < m && l < n)
{
int val;
for (i = l; i < n; ++i)
{
val = a[k][i];
b[z] = val;
++z;
}
k++;
for (i = k; i < m; ++i)
{
val = a[i][n-1];
b[z] = val;
++z;
}
n--;
if ( k < m)
{
for (i = n-1; i >= l; --i)
{
val = a[m-1][i];
b[z] = val;
++z;
}
m--;
}
if (l < n)
{
for (i = m-1; i >= k; --i)
{
val = a[i][l];
b[z] = val;
++z;
}
l++;
}
}
for ( int i=size-1 ; i>=0 ; --i)
{
cout<<b[i]<< " " ;
}
}
int main()
{
int a[R][C] = { {1, 2, 3, 4, 5, 6},
{7, 8, 9, 10, 11, 12},
{13, 14, 15, 16, 17, 18}};
ReversespiralPrint(R, C, a);
return 0;
}
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Output:
11 10 9 8 7 13 14 15 16 17 18 12 6 5 4 3 2 1
Time complexity: O(m*n) where m is number of rows and n is number of columns of a given matrix
Auxiliary Space: O(100)
Please refer complete article on Print a given matrix in reverse spiral form for more details!
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