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C++ Program to Check whether all the rotations of a given number is greater than or equal to the given number or not

  • Last Updated : 24 Jan, 2022

Given an integer x, the task is to find if every k-cycle shift on the element produces a number greater than or equal to the same element. 
A k-cyclic shift of an integer x is a function that removes the last k digits of x and inserts them in its beginning. 
For example, the k-cyclic shifts of 123 are 312 for k=1 and 231 for k=2. Print Yes if the given condition is satisfied else print No.
Examples: 
 

Input: x = 123 
Output : Yes 
The k-cyclic shifts of 123 are 312 for k=1 and 231 for k=2. 
Both 312 and 231 are greater than 123.
Input: 2214 
Output: No 
The k-cyclic shift of 2214 when k=2 is 1422 which is smaller than 2214 
 

 

Approach: Simply find all the possible k cyclic shifts of the number and check if all are greater than the given number or not.
Below is the implementation of the above approach: 
 

C++




// CPP implementation of the approach
#include<bits/stdc++.h>
using namespace std;
  
void CheckKCycles(int n, string s) 
{
    bool ff = true;
    int x = 0;
    for (int i = 1; i < n; i++) 
    {
  
        // Splitting the number at index i 
        // and adding to the front 
        x = (s.substr(i) + s.substr(0, i)).length();
  
        // Checking if the value is greater than 
        // or equal to the given value 
        if (x >= s.length()) 
        {
            continue;
        }
        ff = false;
        break;
    }
    if (ff) 
    {
        cout << ("Yes");
    }
    else
    {
        cout << ("No");
    }
}
  
// Driver code
int main() 
{
    int n = 3;
    string s = "123";
    CheckKCycles(n, s);
    return 0;
}
  
/* This code contributed by Rajput-Ji */
Output: 
Yes

 

Please refer complete article on Check whether all the rotations of a given number is greater than or equal to the given number or not for more details!


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