# C++ Program For Moving All Occurrences Of An Element To End In A Linked List

• Last Updated : 10 Jan, 2022

Given a linked list and a key in it, the task is to move all occurrences of the given key to the end of the linked list, keeping the order of all other elements the same.

Examples:

```Input  : 1 -> 2 -> 2 -> 4 -> 3
key = 2
Output : 1 -> 4 -> 3 -> 2 -> 2

Input  : 6 -> 6 -> 7 -> 6 -> 3 -> 10
key = 6
Output : 7 -> 3 -> 10 -> 6 -> 6 -> 6```

A simple solution is to one by one find all occurrences of a given key in the linked list. For every found occurrence, insert it at the end. We do it till all occurrences of the given key are moved to the end.

Time Complexity: O(n2)

Efficient Solution 1: is to keep two pointers:
pCrawl => Pointer to traverse the whole list one by one.
pKey => Pointer to an occurrence of the key if a key is found. Else same as pCrawl.
We start both of the above pointers from the head of the linked list. We move pKey only when pKey is not pointing to a key. We always move pCrawl. So, when pCrawl and pKey are not the same, we must have found a key that lies before pCrawl, so we swap between pCrawl and pKey, and move pKey to the next location. The loop invariant is, after swapping of data, all elements from pKey to pCrawl are keys.

Below is the implementation of this approach.

## C++

 `// C++ program to move all occurrences of a``// given key to end.``#include `` ` `// A Linked list Node``struct` `Node {``    ``int` `data;``    ``struct` `Node* next;``};`` ` `// A utility function to create a new node.``struct` `Node* newNode(``int` `x)``{``    ``Node* temp = ``new` `Node;``    ``temp->data = x;``    ``temp->next = NULL;``}`` ` `// Utility function to print the elements``// in Linked list``void` `printList(Node* head)``{``    ``struct` `Node* temp = head;``    ``while` `(temp != NULL) {``        ``printf``(``"%d "``, temp->data);``        ``temp = temp->next;``    ``}``    ``printf``("``");``}`` ` `// Moves all occurrences of given key to``// end of linked list.``void` `moveToEnd(Node* head, ``int` `key)``{``    ``// Keeps track of locations where key``    ``// is present.``    ``struct` `Node* pKey = head;`` ` `    ``// Traverse list``    ``struct` `Node* pCrawl = head;``    ``while` `(pCrawl != NULL) {``        ``// If current pointer is not same as pointer``        ``// to a key location, then we must have found``        ``// a key in linked list. We swap data of pCrawl``        ``// and pKey and move pKey to next position.``        ``if` `(pCrawl != pKey && pCrawl->data != key) {``            ``pKey->data = pCrawl->data;``            ``pCrawl->data = key;``            ``pKey = pKey->next;``        ``}`` ` `        ``// Find next position where key is present``        ``if` `(pKey->data != key)``            ``pKey = pKey->next;`` ` `        ``// Moving to next Node``        ``pCrawl = pCrawl->next;``    ``}``}`` ` `// Driver code``int` `main()``{``    ``Node* head = newNode(10);``    ``head->next = newNode(20);``    ``head->next->next = newNode(10);``    ``head->next->next->next = newNode(30);``    ``head->next->next->next->next = newNode(40);``    ``head->next->next->next->next->next = newNode(10);``    ``head->next->next->next->next->next->next = newNode(60);`` ` `    ``printf``("Before moveToEnd(), the Linked list is``");``    ``printList(head);`` ` `    ``int` `key = 10;``    ``moveToEnd(head, key);`` ` `    ``printf``("``After moveToEnd(), the Linked list is``");``    ``printList(head);`` ` `    ``return` `0;``}`

Output:

```Before moveToEnd(), the Linked list is
10 20 10 30 40 10 60

After moveToEnd(), the Linked list is
20 30 40 60 10 10 10```

Time Complexity: O(n) requires only one traversal of the list.

Efficient Solution 2 :
1. Traverse the linked list and take a pointer at the tail.
2. Now, check for the key and node->data. If they are equal, move the node to last-next, else move ahead.

## C++

 `// C++ code to remove key element to end of linked list``#include``using` `namespace` `std;`` ` `// A Linked list Node``struct` `Node ``{``    ``int` `data;``    ``struct` `Node* next;``};`` ` `// A utility function to create a new node.``struct` `Node* newNode(``int` `x)``{``    ``Node* temp = ``new` `Node;``    ``temp->data = x;``    ``temp->next = NULL;``}`` ` `// Function to remove key to end``Node *keyToEnd(Node* head, ``int` `key)``{`` ` `    ``// Node to keep pointing to tail``    ``Node* tail = head;``    ``if` `(head == NULL) ``    ``{``        ``return` `NULL;``    ``}``    ``while` `(tail->next != NULL) ``    ``{``        ``tail = tail->next;``    ``}``     ` `    ``// Node to point to last of linked list``    ``Node* last = tail;``    ``Node* current = head;``    ``Node* prev = NULL;``     ` `    ``// Node prev2 to point to previous when head.data!=key``    ``Node* prev2 = NULL;``     ` `    ``// loop to perform operations to remove key to end``    ``while` `(current != tail) ``    ``{``        ``if` `(current->data == key && prev2 == NULL) ``        ``{``            ``prev = current;``            ``current = current->next;``            ``head = current;``            ``last->next = prev;``            ``last = last->next;``            ``last->next = NULL;``            ``prev = NULL;``        ``}``        ``else``        ``{``            ``if` `(current->data == key && prev2 != NULL)``            ``{``                ``prev = current;``                ``current = current->next;``                ``prev2->next = current;``                ``last->next = prev;``                ``last = last->next;``                ``last->next = NULL;``            ``}``            ``else` `if` `(current != tail) ``            ``{``                ``prev2 = current;``                ``current = current->next;``            ``}``        ``}``    ``}``    ``return` `head;``}`` ` `// Function to display linked list``void` `printList(Node* head) ``{``    ``struct` `Node* temp = head;``    ``while` `(temp != NULL) ``    ``{``        ``printf``(``"%d "``, temp->data);``        ``temp = temp->next;``    ``}``    ``printf``(``"\n"``);``}`` ` ` ` `// Driver Code``int` `main()``{``    ``Node* root = newNode(5);``    ``root->next = newNode(2);``    ``root->next->next = newNode(2);``    ``root->next->next->next = newNode(7);``    ``root->next->next->next->next = newNode(2);``    ``root->next->next->next->next->next = newNode(2);``    ``root->next->next->next->next->next->next = newNode(2);`` ` `    ``int` `key = 2;``    ``cout << ``"Linked List before operations :"``;``    ``printList(root);``    ``cout << ``"\nLinked List after operations :"``;``    ``root = keyToEnd(root, key);``    ``printList(root);``    ``return` `0;``}`` ` `// This code is contributed by Rajout-Ji`

Output:

```Linked List before operations :
5 2 2 7 2 2 2