Open In App

# Count the number of words having sum of ASCII values less than and greater than k

Given a string, the task is to count the number of words whose sum of Ascii values is less than and greater than or equal to given k.

Examples:

```Input: str = "Learn how to code", k = 400
Output:
Number of words having sum of ascii less than k = 2
Number of words having sum of ascii greater than or equal to k = 2

Input: str = "Geeks for Geeks", k = 400
Output:
Number of words having sum of ascii less than k = 1
Number of words having sum of ascii greater than or equal to k = 2```

Brute Force Approach:

The approach is to solve this problem is to first split the given string into individual words and calculate the sum of ASCII values of each word. Then, we can iterate through each word and check whether its sum of ASCII values is less than or greater than or equal to the given value k. Finally, we can count the number of words that satisfy each condition and print the results.

Below is the implementation of the above approach:

## C++

 `#include ``using` `namespace` `std;` `// Function to split the given string into individual words``vector splitWords(string str)``{``    ``vector words;``    ``stringstream ss(str);``    ``string word;``    ``while` `(ss >> word)``        ``words.push_back(word);``    ``return` `words;``}` `// Function to count the words``void` `CountWords(string str, ``int` `k)``{``    ``vector words = splitWords(str);``    ``int` `lessThanK = 0;``    ``int` `greaterThanOrEqualK = 0;``    ``for` `(string word : words)``    ``{``        ``int` `sum = 0;``        ``for` `(``char` `c : word)``            ``sum += c;``        ``if` `(sum < k)``            ``lessThanK++;``        ``else``            ``greaterThanOrEqualK++;``    ``}``    ``cout << ``"Number of words having sum of ascii less than k = "` `<< lessThanK << endl;``    ``cout << ``"Number of words having sum of ascii greater than or equal to k = "` `<< greaterThanOrEqualK << endl;``}` `// Driver code``int` `main()``{``    ``string str = ``"Learn how to code"``;``    ``int` `k = 400;``    ``CountWords(str, k);``    ``return` `0;``}`

## Java

 `import` `java.util.*;` `public` `class` `Main {``    ``// Function to split the given string into individual words``    ``static` `List splitWords(String str) {``        ``List words = ``new` `ArrayList<>();``        ``Scanner sc = ``new` `Scanner(str);``        ``while` `(sc.hasNext()) {``            ``words.add(sc.next());``        ``}``        ``return` `words;``    ``}` `  ``// Function to count the words``    ``static` `void` `countWords(String str, ``int` `k) {``        ``List words = splitWords(str);``        ``int` `lessThanK = ``0``;``        ``int` `greaterThanOrEqualK = ``0``;``        ``for` `(String word : words) {``            ``int` `sum = ``0``;``            ``for` `(``char` `c : word.toCharArray()) {``                ``sum += (``int``) c;``            ``}``            ``if` `(sum < k) {``                ``lessThanK++;``            ``} ``else` `{``                ``greaterThanOrEqualK++;``            ``}``        ``}``        ``System.out.println(``"Number of words having sum of ascii less than k = "` `+ lessThanK);``        ``System.out.println(``"Number of words having sum of ascii greater than or equal to k = "` `+ greaterThanOrEqualK);``    ``}` `    ``// Driver code``    ``public` `static` `void` `main(String[] args) {``        ``String str = ``"Learn how to code"``;``        ``int` `k = ``400``;``        ``countWords(str, k);``    ``}``}`

## Python3

 `# Importing the regular expression module``import` `re` `# Function to split the given string into individual words`  `def` `splitWords(s):``    ``return` `re.findall(r``'\w+'``, s)` `# Function to count the words`  `def` `countWords(s, k):``    ``words ``=` `splitWords(s)``    ``lessThanK ``=` `0``    ``greaterThanOrEqualK ``=` `0``    ``for` `word ``in` `words:``        ``sum` `=` `0``        ``for` `c ``in` `word:``            ``sum` `+``=` `ord``(c)``        ``if` `sum` `< k:``            ``lessThanK ``+``=` `1``        ``else``:``            ``greaterThanOrEqualK ``+``=` `1``    ``print``(``"Number of words having sum of ascii less than k ="``, lessThanK)``    ``print``(``"Number of words having sum of ascii greater than or equal to k ="``,``          ``greaterThanOrEqualK)`  `# Driver code``str` `=` `"Learn how to code"``k ``=` `400``countWords(``str``, k)`

## C#

 `using` `System;``using` `System.Collections.Generic;``using` `System.Linq;``using` `System.Text.RegularExpressions;` `class` `Program {``    ``// Function to split the given string into individual``    ``// words``    ``static` `List<``string``> SplitWords(``string` `str)``    ``{``        ``List<``string``> words = ``new` `List<``string``>();``        ``Regex regex = ``new` `Regex(``@"\w+"``);``        ``MatchCollection matches = regex.Matches(str);``        ``foreach``(Match match ``in` `matches)``        ``{``            ``words.Add(match.Value);``        ``}``        ``return` `words;``    ``}` `    ``// Function to count the words``    ``static` `void` `CountWords(``string` `str, ``int` `k)``    ``{``        ``List<``string``> words = SplitWords(str);``        ``int` `lessThanK = 0;``        ``int` `greaterThanOrEqualK = 0;``        ``foreach``(``string` `word ``in` `words)``        ``{``            ``int` `sum = 0;``            ``foreach``(``char` `c ``in` `word) { sum += c; }``            ``if` `(sum < k) {``                ``lessThanK++;``            ``}``            ``else` `{``                ``greaterThanOrEqualK++;``            ``}``        ``}``        ``Console.WriteLine(``            ``"Number of words having sum of ascii less than k = "``            ``+ lessThanK);``        ``Console.WriteLine(``            ``"Number of words having sum of ascii greater than or equal to k = "``            ``+ greaterThanOrEqualK);``    ``}` `    ``// Driver code``    ``static` `void` `Main(``string``[] args)``    ``{``        ``string` `str = ``"Learn how to code"``;``        ``int` `k = 400;``        ``CountWords(str, k);``    ``}``}`

## Javascript

 `// Function to split the given string into individual words``function` `splitWords(str) {``    ``let words = [];``    ``let sc = str.split(``" "``);``    ``for` `(let i = 0; i < sc.length; i++) {``        ``words.push(sc[i]);``    ``}``    ``return` `words;``}` `// Function to count the words``function` `countWords(str, k) {``    ``let words = splitWords(str);``    ``let lessThanK = 0;``    ``let greaterThanOrEqualK = 0;``    ``for` `(let word of words) {``        ``let sum = 0;``        ``for` `(let c of word.split(``''``)) {``            ``sum += c.charCodeAt(0);``        ``}``        ``if` `(sum < k) {``            ``lessThanK++;``        ``} ``else` `{``            ``greaterThanOrEqualK++;``        ``}``    ``}``    ``console.log(``"Number of words having sum of ascii less than k = "` `+ lessThanK);``    ``console.log(``"Number of words having sum of ascii greater than or equal to k = "` `+ greaterThanOrEqualK);``}` `// Driver code``let str = ``"Learn how to code"``;``let k = 400;``countWords(str, k);`

Output

```Number of words having sum of ascii less than k = 2
Number of words having sum of ascii greater than or equal to k = 2```

Time Complexity: O(n*m), where n is the length of the string and m is the average length of each word in the string.
Space Complexity: O(m), as we are using a vector to store each word in the string.

Approach: Count the number of words having the sum of ASCII values less than k and subtract it from the total number of words to get the number of words having ASCII values to the sum greater than or equal to k. Start traversing the string letter by letter and add the ASCII value to sum. If there is a space then increment the count if the sum is less than k and will also set the sum to 0.

Below is the implementation of the above approach:

## C++

 `// C++ implementation of the above approach``#include ``using` `namespace` `std;` `// Function to count the words``void` `CountWords(string str, ``int` `k)``{``    ``// Sum of ascii values``    ``int` `sum = 0;` `    ``int` `NumberOfWords = 0;` `    ``// Number of words having``    ``// sum of ascii less than k``    ``int` `counter = 0;` `    ``int` `len = str.length();` `    ``for` `(``int` `i = 0; i < len; ++i) {``        ``// If character is a space``        ``if` `(str[i] == ``' '``) {``            ``if` `(sum < k)``                ``counter++;` `            ``sum = 0;``            ``NumberOfWords++;``        ``}``        ``else``            ``// Add the ascii value to sum``            ``sum += str[i];``    ``}` `    ``// Handling the Last word separately``    ``NumberOfWords++;``    ``if` `(sum < k)``        ``counter++;` `    ``cout << ``"Number of words having sum of ASCII"``            ``" values less than k = "``         ``<< counter << endl;``    ``cout << ``"Number of words having sum of ASCII values"``            ``" greater than or equal to k = "``         ``<< NumberOfWords - counter;``}` `// Driver code``int` `main()``{``    ``string str = ``"Learn how to code"``;``    ``int` `k = 400;``    ``CountWords(str, k);` `    ``return` `0;``}`

## Java

 `// Java implementation of the``// above approach``class` `GFG``{``    ` `// Function to count the words``static` `void` `CountWords(String str, ``int` `k)``{``    ``// Sum of ascii values``    ``int` `sum = ``0``;` `    ``int` `NumberOfWords = ``0``;` `    ``// Number of words having``    ``// sum of ascii less than k``    ``int` `counter = ``0``;` `    ``int` `len = str.length();` `    ``for` `(``int` `i = ``0``; i < len; ++i)``    ``{``        ``// If character is a space``        ``if` `(str.charAt(i) == ``' '``)``        ``{``            ``if` `(sum < k)``            ``{``                ``counter++;``            ``}` `            ``sum = ``0``;``            ``NumberOfWords++;``        ``}``        ` `        ``else` `// Add the ascii value to sum``        ``{``            ``sum += str.charAt(i);``        ``}``    ``}` `    ``// Handling the Last word separately``    ``NumberOfWords++;``    ``if` `(sum < k)``    ``{``        ``counter++;``    ``}` `    ``System.out.println(``"Number of words having sum "` `+``                    ``"of ASCII values less than k = "` `+``                                             ``counter);``    ``System.out.println(``"Number of words having sum of "` `+``           ``"ASCII values greater than or equal to k = "` `+``                              ``(NumberOfWords - counter));``}` `// Driver code``public` `static` `void` `main(String[] args)``{``    ``String str = ``"Learn how to code"``;``    ``int` `k = ``400``;``    ``CountWords(str, k);``}``}` `// This code is contributed by RAJPUT-JI`

## Python 3

 `# Python 3 implementation of the``# above approach` `# Function to count the words``def` `CountWords(``str``, k):` `    ``# Sum of ascii values``    ``sum` `=` `0` `    ``NumberOfWords ``=` `0` `    ``# Number of words having``    ``# sum of ascii less than k``    ``counter ``=` `0` `    ``l ``=` `len``(``str``)` `    ``for` `i ``in` `range``(l):``        ` `        ``# If character is a space``        ``if` `(``str``[i] ``=``=` `' '``) :``            ``if` `(``sum` `< k):``                ``counter ``+``=` `1` `            ``sum` `=` `0``            ``NumberOfWords ``+``=` `1``        ` `        ``else``:``            ` `            ``# Add the ascii value to sum``            ``sum` `+``=` `ord``(``str``[i])` `    ``# Handling the Last word separately``    ``NumberOfWords ``+``=` `1``    ``if` `(``sum` `< k):``        ``counter ``+``=` `1` `    ``print``(``"Number of words having sum of ASCII"``,``          ``"values less than k ="``, counter)``    ``print``(``"Number of words having sum of ASCII values"``,``                        ``"greater than or equal to k ="``,``                               ``NumberOfWords ``-` `counter)` `# Driver code``if` `__name__ ``=``=` `"__main__"``:``    ` `    ``str` `=` `"Learn how to code"``    ``k ``=` `400``    ``CountWords(``str``, k)` `# This code is contributed``# by ChitraNayal`

## C#

 `// C# implementation of the``// above approach``using` `System;` `class` `GFG``{` `// Function to count the words``static` `void` `CountWords(String str,``                       ``int` `k)``{``    ``// Sum of ascii values``    ``int` `sum = 0;` `    ``int` `NumberOfWords = 0;` `    ``// Number of words having``    ``// sum of ascii less than k``    ``int` `counter = 0;` `    ``int` `len = str.Length;` `    ``for` `(``int` `i = 0; i < len; ++i)``    ``{``        ``// If character is a space``        ``if` `(str[i]==``' '``)``        ``{``            ``if` `(sum < k)``            ``{``                ``counter++;``            ``}` `            ``sum = 0;``            ``NumberOfWords++;``        ``}``        ``else` `// Add the ascii value to sum``        ``{``            ``sum += str[i];``        ``}``    ``}` `    ``// Handling the Last word``    ``// separately``    ``NumberOfWords++;``    ``if` `(sum < k)``    ``{``        ``counter++;``    ``}` `    ``Console.WriteLine(``"Number of words having sum "` `+``                      ``"of ASCII values less than k = "` `+``                                               ``counter);``    ``Console.WriteLine(``"Number of words having sum of "` `+``          ``"ASCII values greater than or equal to k = "` `+``                             ``(NumberOfWords - counter));``}` `// Driver code``public` `static` `void` `Main(String[] args)``{``    ``String str = ``"Learn how to code"``;``    ``int` `k = 400;``    ``CountWords(str, k);``}``}` `// This code is contributed by RAJPUT-JI`

## PHP

 ``

## Javascript

 ``

Output

```Number of words having sum of ASCII values less than k = 2
Number of words having sum of ASCII values greater than or equal to k = 2```

Complexity Analysis:

• Time Complexity: O(N), as we are using a loop to traverse N times so it will cost us O(N) time
• Auxiliary Space: O(1), as we are not using any extra space.