Given a string, the task is to count the number of words whose sum of Ascii values is less than and greater than or equal to given k.
Examples:
Input: str = "Learn how to code", k = 400
Output:
Number of words having sum of ascii less than k = 2
Number of words having sum of ascii greater than or equal to k = 2
Input: str = "Geeks for Geeks", k = 400
Output:
Number of words having sum of ascii less than k = 1
Number of words having sum of ascii greater than or equal to k = 2
Approach: Count the number of words having the sum of ASCII values less than k and subtract it from the total number of words to get the number of words having ASCII values to the sum greater than or equal to k. Start traversing the string letter by letter and add the ASCII value to sum. If there is a space then increment the count if the sum is less than k and will also set the sum to 0.
Below is the implementation of the above approach:
C++
#include <bits/stdc++.h>
using namespace std;
void CountWords(string str, int k)
{
int sum = 0;
int NumberOfWords = 0;
int counter = 0;
int len = str.length();
for ( int i = 0; i < len; ++i) {
if (str[i] == ' ' ) {
if (sum < k)
counter++;
sum = 0;
NumberOfWords++;
}
else
sum += str[i];
}
NumberOfWords++;
if (sum < k)
counter++;
cout << "Number of words having sum of ASCII"
" values less than k = "
<< counter << endl;
cout << "Number of words having sum of ASCII values"
" greater than or equal to k = "
<< NumberOfWords - counter;
}
int main()
{
string str = "Learn how to code" ;
int k = 400;
CountWords(str, k);
return 0;
}
|
Java
class GFG
{
static void CountWords(String str, int k)
{
int sum = 0 ;
int NumberOfWords = 0 ;
int counter = 0 ;
int len = str.length();
for ( int i = 0 ; i < len; ++i)
{
if (str.charAt(i) == ' ' )
{
if (sum < k)
{
counter++;
}
sum = 0 ;
NumberOfWords++;
}
else
{
sum += str.charAt(i);
}
}
NumberOfWords++;
if (sum < k)
{
counter++;
}
System.out.println( "Number of words having sum " +
"of ASCII values less than k = " +
counter);
System.out.println( "Number of words having sum of " +
"ASCII values greater than or equal to k = " +
(NumberOfWords - counter));
}
public static void main(String[] args)
{
String str = "Learn how to code" ;
int k = 400 ;
CountWords(str, k);
}
}
|
Python 3
def CountWords( str , k):
sum = 0
NumberOfWords = 0
counter = 0
l = len ( str )
for i in range (l):
if ( str [i] = = ' ' ) :
if ( sum < k):
counter + = 1
sum = 0
NumberOfWords + = 1
else :
sum + = ord ( str [i])
NumberOfWords + = 1
if ( sum < k):
counter + = 1
print ( "Number of words having sum of ASCII" ,
"values less than k =" , counter)
print ( "Number of words having sum of ASCII values" ,
"greater than or equal to k =" ,
NumberOfWords - counter)
if __name__ = = "__main__" :
str = "Learn how to code"
k = 400
CountWords( str , k)
|
C#
using System;
class GFG
{
static void CountWords(String str,
int k)
{
int sum = 0;
int NumberOfWords = 0;
int counter = 0;
int len = str.Length;
for ( int i = 0; i < len; ++i)
{
if (str[i]== ' ' )
{
if (sum < k)
{
counter++;
}
sum = 0;
NumberOfWords++;
}
else
{
sum += str[i];
}
}
NumberOfWords++;
if (sum < k)
{
counter++;
}
Console.WriteLine( "Number of words having sum " +
"of ASCII values less than k = " +
counter);
Console.WriteLine( "Number of words having sum of " +
"ASCII values greater than or equal to k = " +
(NumberOfWords - counter));
}
public static void Main(String[] args)
{
String str = "Learn how to code" ;
int k = 400;
CountWords(str, k);
}
}
|
PHP
<?php
function CountWords( $str , $k )
{
$sum = 0;
$NumberOfWords = 0;
$counter = 0;
$len = strlen ( $str );
for ( $i = 0; $i < $len ; ++ $i )
{
if ( $str [ $i ] == ' ' )
{
if ( $sum < $k )
$counter ++;
$sum = 0;
$NumberOfWords ++;
}
else
$sum += ord( $str [ $i ]);
}
$NumberOfWords ++;
if ( $sum < $k )
$counter ++;
echo "Number of words having sum of ASCII" .
" values less than k = " . $counter . "\n" ;
echo "Number of words having sum of ASCII " .
"values greater than or equal to k = " .
( $NumberOfWords - $counter );
}
$str = "Learn how to code" ;
$k = 400;
CountWords( $str , $k );
?>
|
Javascript
<script>
function CountWords(str, k)
{
let sum = 0;
let NumberOfWords = 0;
let counter = 0;
let len = str.length;
for (let i = 0; i < len; ++i) {
if (str[i] == " " ) {
if (sum < k) {
counter++;
}
sum = 0;
NumberOfWords++;
}
else {
sum += str.charCodeAt(i);
}
}
NumberOfWords++;
if (sum < k) {
counter++;
}
document.write( "Number of words having sum " +
"of ASCII values less than k = " +
counter + "<br>" );
document.write( "Number of words having sum of " +
"ASCII values greater than or equal to k = " +
(NumberOfWords - counter) + "<br>" );
}
let str = "Learn how to code" ;
let k = 400;
CountWords(str, k);
</script>
|
Output: Number of words having sum of ASCII values less than k = 2
Number of words having sum of ASCII values greater than or equal to k = 2
Time Complexity: O(N), as we are using a loop to traverse N times so it will cost us O(N) time
Auxiliary Space: O(1), as we are not using any extra space.