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# Count the number of occurrences of a particular digit in a number

• Difficulty Level : Basic
• Last Updated : 05 May, 2021

Given a number N and a digit D, the task is to count the occurrences of D in N.
Examples:

```Input: N = 25, D = 2
Output: 1

Input: N = 100, D = 0
Output: 2```

Approach: Take out the digits one by one in N and check if this digit is equal to D. If equal, then increment the count by 1. In the end, print the count.
Below is the implementation of the above approach:

## C++

 `// C++ program to count the number of occurrences``// of a particular digit in a number` `#include ``using` `namespace` `std;` `// Function to count the occurrences``// of the digit D in N``long` `long` `int` `countOccurrances(``long` `long` `int` `n,``                               ``int` `d)``{``    ``long` `long` `int` `count = 0;` `    ``// Loop to find the digits of N``    ``while` `(n > 0) {` `        ``// check if the digit is D``        ``count = (n % 10 == d)``                    ``? count + 1``                    ``: count;``        ``n = n / 10;``    ``}` `    ``// return the count of the``    ``// occurrences of D in N``    ``return` `count;``}` `// Driver code``int` `main()``{` `    ``int` `d = 2;``    ``long` `long` `int` `n = 214215421;` `    ``cout << countOccurrances(n, d)``         ``<< endl;` `    ``return` `0;``}`

## Java

 `// Java program to count the number of occurrences``// of a particular digit in a number``import` `java.util.*;` `class` `GFG``{` `// Function to count the occurrences``// of the digit D in N``static` `int` `countOccurrances(``int` `n,``                            ``int` `d)``{``    ``int` `count = ``0``;` `    ``// Loop to find the digits of N``    ``while` `(n > ``0``)``    ``{` `        ``// check if the digit is D``        ``count = (n % ``10` `== d) ?``                    ``count + ``1` `: count;``        ``n = n / ``10``;``    ``}` `    ``// return the count of the``    ``// occurrences of D in N``    ``return` `count;``}` `// Driver code``public` `static` `void` `main(String args[])``{``    ``int` `d = ``2``;``    ``int` `n = ``214215421``;` `    ``System.out.println(countOccurrances(n, d));``}``}` `// This code is contributed by Surendra_Gangwar`

## Python3

 `# Python3 program to count the``# number of occurrences of a``# particular digit in a number` `# Function to count the occurrences``# of the digit D in N``def` `countOccurrances(n, d):``    ``count ``=` `0` `    ``# Loop to find the digits of N``    ``while` `(n > ``0``):` `        ``# check if the digit is D``        ``if``(n ``%` `10` `=``=` `d):``            ``count ``=` `count ``+` `1`` ` `        ``n ``=` `n ``/``/` `10` `    ``# return the count of the``    ``# occurrences of D in N``    ``return` `count` `# Driver code``d ``=` `2``n ``=` `214215421``print``(countOccurrances(n, d))` `# This code is contributed by Mohit Kumar`

## C#

 `// C# program to count the number``// of occurrences of a particular``// digit in a number``using` `System;``class` `GFG``{` `// Function to count the occurrences``// of the digit D in N``static` `int` `countOccurrances(``int` `n,``                            ``int` `d)``{``    ``int` `count = 0;` `    ``// Loop to find the digits of N``    ``while` `(n > 0)``    ``{` `        ``// check if the digit is D``        ``count = (n % 10 == d) ?``                    ``count + 1 : count;``        ``n = n / 10;``    ``}` `    ``// return the count of the``    ``// occurrences of D in N``    ``return` `count;``}` `// Driver code``public` `static` `void` `Main()``{``    ``int` `d = 2;``    ``int` `n = 214215421;` `    ``Console.WriteLine(countOccurrances(n, d));``}``}` `// This code is contributed by Code_Mech.`

## Javascript

 ``
Output:
`3`

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