Given a tree, and the weights (in the form of strings) of all the nodes, the task is to count the nodes whose weights contain a vowel.
Only the strings of the nodes 1 and 5 contain vowels.
Approach: Perform dfs on the tree and for every node, check if it’s string contains vowels, If yes then increment the count.
Below is the implementation of the above approach:
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- Count the nodes of a tree whose weighted string is an anagram of the given string
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- Count the nodes of a tree whose weighted string does not contain any duplicate characters
- Count of leaf nodes of the tree whose weighted string is a palindrome
- Count pair of strings whose concatenation has every vowel
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- Count the nodes of the tree which make a pangram when concatenated with the sub-tree nodes
- Minimum Cost of Simple Path between two nodes in a Directed and Weighted Graph
- Count the nodes in the given tree whose weight is even parity
- Count the nodes of the given tree whose weight has X as a factor
- Count nodes in the given tree whose weight is a fibonacci number
- Count the nodes in the given tree whose weight is a powerful number
- Count the nodes in the given Tree whose weight is a Perfect Number
- Count of adjacent Vowel Consonant Pairs
- Count of N size strings consisting of at least one vowel and one consonant
- Alternate vowel and consonant string
- Print all Subsequences of String which Start with Vowel and End with Consonant.
- Lexicographically first alternate vowel and consonant string
- Python program to check if given string is vowel Palindrome
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