# Count the minimum steps to reach 0 from the given integer N

Given two integers N and K where K represents the number of jumps that we are allowed to make directly from N reducing N to N – K, our task is to count minimum steps to reach 0 following the given operations:

• We can jump by a amount of K from N that is N = N – K
• Decrement N by 1 that is N = N -1.

Examples:

Input: N = 11, K = 4
Output: 5
Explanation:
For the given value N we can perform the operation in the given sequence: 11 -> 7 -> 3 -> 2 -> 1 -> 0

Input: N = 6, K = 3
Output: 2
Explanation:
For the given value N we can perform the operation in the given sequence: 6 -> 3 -> 0.

## Recommended: Please try your approach on {IDE} first, before moving on to the solution.

Approach:

To solve the problem mentioned above we know that it will take N / K steps to directly jump from value N to least divisible value with K and N % K steps to decrement it by 1 such as to reduce the count to 0. So the total number of steps required to reach 0 from N will be

(N / K) + (N % K)

Below is the implementation of the above approach:

## C++

 `// C++ program to Count the minimum steps ` `// to reach 0 from the given integer N ` ` `  `#include ` `using` `namespace` `std; ` ` `  `// Function retuns min step ` `// to reach 0 from N ` `int` `getMinSteps(``int` `n, ``int` `jump) ` `{ ` `    ``// Direct possible ` `    ``// reduction of value N ` `    ``int` `quotient = n / jump; ` ` `  `    ``// Remaining steps needs ` `    ``// to be reduced by 1 ` `    ``int` `remainder = n % jump; ` ` `  `    ``// Summation of both the values ` `    ``int` `steps = quotient + remainder; ` ` `  `    ``// Return the final answer ` `    ``return` `steps; ` `} ` ` `  `// Driver code ` `int` `main() ` `{ ` `    ``int` `N = 6, K = 3; ` ` `  `    ``cout << getMinSteps(N, K); ` ` `  `    ``return` `0; ` `} `

## Java

 `// Java program to count the minimum steps ` `// to reach 0 from the given integer N ` `class` `GFG{ ` ` `  `// Function retuns min step ` `// to reach 0 from N ` `static` `int` `getMinSteps(``int` `n, ``int` `jump) ` `{ ` `     `  `    ``// Direct possible ` `    ``// reduction of value N ` `    ``int` `quotient = n / jump; ` ` `  `    ``// Remaining steps needs ` `    ``// to be reduced by 1 ` `    ``int` `remainder = n % jump; ` ` `  `    ``// Summation of both the values ` `    ``int` `steps = quotient + remainder; ` ` `  `    ``// Return the final answer ` `    ``return` `steps; ` `} ` ` `  `// Driver code ` `public` `static` `void` `main(String[] args) ` `{ ` `    ``int` `N = ``6``, K = ``3``; ` ` `  `    ``System.out.print(getMinSteps(N, K)); ` `} ` `} ` ` `  `// This code is contributed by Rohit_ranjan `

## Python3

 `# Python3 program to Count the minimum steps  ` `# to reach 0 from the given integer N  ` ` `  `# Function retuns min step  ` `# to reach 0 from N  ` `def` `getMinSteps(n, jump): ` ` `  `    ``# Direct possible  ` `    ``# reduction of value N  ` `    ``quotient ``=` `int``(n ``/` `jump) ` ` `  `    ``# Remaining steps needs  ` `    ``# to be reduced by 1  ` `    ``remainder ``=` `n ``%` `jump ` ` `  `    ``# Summation of both the values  ` `    ``steps ``=` `quotient ``+` `remainder ` ` `  `    ``# Return the final answer  ` `    ``return` `steps ` ` `  `# Driver code  ` `N ``=` `6` `K ``=` `3` ` `  `print` `(getMinSteps(N, K)) ` ` `  `# This code is contributed by PratikBasu `

## C#

 `// C# program to count the minimum steps  ` `// to reach 0 from the given integer N  ` `using` `System; ` ` `  `class` `GFG{  ` ` `  `// Function retuns min step  ` `// to reach 0 from N  ` `static` `int` `getMinSteps(``int` `n, ``int` `jump)  ` `{  ` `     `  `    ``// Direct possible  ` `    ``// reduction of value N  ` `    ``int` `quotient = n / jump;  ` ` `  `    ``// Remaining steps needs  ` `    ``// to be reduced by 1  ` `    ``int` `remainder = n % jump;  ` ` `  `    ``// Summation of both the values  ` `    ``int` `steps = quotient + remainder;  ` ` `  `    ``// Return the final answer  ` `    ``return` `steps;  ` `}  ` ` `  `// Driver code  ` `public` `static` `void` `Main(``string``[] args)  ` `{  ` `    ``int` `N = 6, K = 3;  ` ` `  `    ``Console.Write(getMinSteps(N, K));  ` `}  ` `}  ` ` `  `// This code is contributed by rutvik_56 `

Output:

```2
```

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