Given a number . The task is to count pairs (x, y) such that x*y is divisible by (x+y) and the condition 1 <= x < y < N holds true.
Input : N = 6 Output : 1 Explanation: The only pair is (3, 6) which satisfies all of the given condition, 3<6 and 18%9=0. Input : N = 15 Output : 4
The basic approach is to iterate using two loops carefully maintaining the given condition 1 <= x < y < N and generate all possible valid pairs and count such pairs for which the product of their values is divisible by sum.
Below is the implementation of the above approach:
Time Complexity : O(N2)
- Count the number of pairs (i, j) such that either arr[i] is divisible by arr[j] or arr[j] is divisible by arr[i]
- Count pairs from 1 to N such that their Sum is divisible by their XOR
- Count of pairs from 1 to a and 1 to b whose sum is divisible by N
- Count pairs (i,j) such that (i+j) is divisible by A and B both
- Count sub-arrays whose product is divisible by k
- Count pairs in array whose sum is divisible by K
- Print k numbers where all pairs are divisible by m
- Count ordered pairs with product less than N
- Count number of pairs in array having sum divisible by K | SET 2
- Check if product of first N natural numbers is divisible by their sum
- Sum and Product of all Composite numbers which are divisible by k in an array
- Number of pairs from the first N natural numbers whose sum is divisible by K
- Count unordered pairs (i,j) such that product of a[i] and a[j] is power of two
- Count number of ordered pairs with Even and Odd Product
- Count all distinct pairs with product equal to K
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