# Count of numbers from range [L, R] that end with any of the given digits

Given a range [L, R], the task is to find the count of numbers from the range whose last digit is either 2, 3 or 9.

Examples:

Input: L = 1, R = 3
Output: 2
2 and 3 are the only valid numbers.

Input: L = 11, R = 33
Output: 8

## Recommended: Please try your approach on {IDE} first, before moving on to the solution.

Approach: Initialize a counter count = 0 and run a loop for every element from the range, if the current element ends with any of the given digits then increment the count.

Below is the implementation of the above approach:

## C++

 `// C++ implementation of the approach ` `#include ` `using` `namespace` `std; ` ` `  `// Function to return the count ` `// of the required numbers ` `int` `countNums(``int` `l, ``int` `r) ` `{ ` `    ``int` `cnt = 0; ` ` `  `    ``for` `(``int` `i = l; i <= r; i++) ` `    ``{ ` ` `  `        ``// Last digit of the current number ` `        ``int` `lastDigit = (i % 10); ` ` `  `        ``// If the last digit is equal to ` `        ``// any of the given digits ` `        ``if` `((lastDigit % 10) == 2 || (lastDigit % 10) == 3 ` `            ``|| (lastDigit % 10) == 9)  ` `        ``{ ` `            ``cnt++; ` `        ``} ` `    ``} ` ` `  `    ``return` `cnt; ` `} ` ` `  `// Driver code ` `int` `main()  ` `{ ` `    ``int` `l = 11, r = 33; ` `    ``cout << countNums(l, r) ; ` `} ` `     `  `// This code is contributed by AnkitRai01 `

## Java

 `// Java implementation of the approach ` `class` `GFG { ` ` `  `    ``// Function to return the count ` `    ``// of the required numbers ` `    ``static` `int` `countNums(``int` `l, ``int` `r) ` `    ``{ ` `        ``int` `cnt = ``0``; ` ` `  `        ``for` `(``int` `i = l; i <= r; i++) { ` ` `  `            ``// Last digit of the current number ` `            ``int` `lastDigit = (i % ``10``); ` ` `  `            ``// If the last digit is equal to ` `            ``// any of the given digits ` `            ``if` `((lastDigit % ``10``) == ``2` `|| (lastDigit % ``10``) == ``3` `                ``|| (lastDigit % ``10``) == ``9``) { ` `                ``cnt++; ` `            ``} ` `        ``} ` ` `  `        ``return` `cnt; ` `    ``} ` ` `  `    ``// Driver code ` `    ``public` `static` `void` `main(String[] args) ` `    ``{ ` `        ``int` `l = ``11``, r = ``33``; ` `        ``System.out.print(countNums(l, r)); ` `    ``} ` `} `

## Python3

 `# Python3 implementation of the approach ` ` `  `# Function to return the count ` `# of the required numbers ` `def` `countNums(l, r) : ` `    ``cnt ``=` `0``; ` ` `  `    ``for` `i ``in` `range``(l, r ``+` `1``) : ` ` `  `        ``# Last digit of the current number ` `        ``lastDigit ``=` `(i ``%` `10``); ` ` `  `        ``# If the last digit is equal to ` `        ``# any of the given digits ` `        ``if` `((lastDigit ``%` `10``) ``=``=` `2` `or` `(lastDigit ``%` `10``) ``=``=` `3` `            ``or` `(lastDigit ``%` `10``) ``=``=` `9``) : ` `         `  `            ``cnt ``+``=` `1``; ` ` `  `    ``return` `cnt; ` ` `  `# Driver code ` `if` `__name__ ``=``=` `"__main__"` `:  ` `     `  `    ``l ``=` `11``; r ``=` `33``; ` `     `  `    ``print``(countNums(l, r)) ; ` ` `  `# This code is contributed by AnkitRai01 `

## C#

 `// C# implementation of the approach  ` `using` `System; ` ` `  `class` `GFG  ` `{  ` ` `  `    ``// Function to return the count  ` `    ``// of the required numbers  ` `    ``static` `int` `countNums(``int` `l, ``int` `r)  ` `    ``{  ` `        ``int` `cnt = 0;  ` ` `  `        ``for` `(``int` `i = l; i <= r; i++)  ` `        ``{  ` ` `  `            ``// Last digit of the current number  ` `            ``int` `lastDigit = (i % 10);  ` ` `  `            ``// If the last digit is equal to  ` `            ``// any of the given digits  ` `            ``if` `((lastDigit % 10) == 2 ||  ` `                ``(lastDigit % 10) == 3 ||  ` `                ``(lastDigit % 10) == 9) ` `            ``{  ` `                ``cnt++;  ` `            ``}  ` `        ``}  ` `        ``return` `cnt;  ` `    ``}  ` ` `  `    ``// Driver code  ` `    ``public` `static` `void` `Main()  ` `    ``{  ` `        ``int` `l = 11, r = 33;  ` `        ``Console.Write(countNums(l, r));  ` `    ``}  ` `} ` ` `  `// This code is contributed by AnkitRai01 `

Output:

```8
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Improved By : AnkitRai01