# Count of anagrams of each string in an array present in another array

Given two arrays arr1[] and arr2[] consisting of strings, the task is to print the count of anagrams of every string in arr2[] that are present in in arr1[].

Examples:

Input: arr1[] = [“geeks”, “learn”, “for”, “egeks”, “ealrn”], arr2[] = [“kgees”, “rof”, “nrael”]
Output: 2 1 2
Explanation:
Anagrams of arr2 (“kgees”) in arr1 : “geeks” and “egeks”.
Anagrams of arr2 (“rof”) in arr1 : “for”.
Anagrams of arr2 (“nrael”) in arr1 : “learn” and “ealrn”.

Input: arr1[] = [“code”, “to”, “grow”, “odce”], arr2[] = [“edoc”, “wgor”, “ot”]
Output: 2 1 1
Explanation:
Anagrams of arr2 (“edoc”) in arr1 “code” and “odce”.
Anagrams of arr2 (“wgor”) in arr1 “grow”.
Anagrams of arr2 (“ot”) in arr1 “to”

## Recommended: Please try your approach on {IDE} first, before moving on to the solution.

Approach:
To solve the problem, the idea is to use frequency-counting with the help of HashMap. Store the frequencies of every string in arr1[] in hashmap in their sorted form. Traverse arr2[], sort strings in arr2[], and print their respective frequencies in HashMap.

Below is the implementation of the above approach:

## C++

 `// C++ Program to count the ` `// number of anagrams of ` `// each string in a given ` `// array present in ` `// another array ` ` `  `#include ` `using` `namespace` `std; ` ` `  `// Function to return the ` `// count of anagrams ` `void` `count(string arr1[], ` `           ``string arr2[], ` `           ``int` `n, ``int` `m) ` `{ ` `    ``// Store the frequencies ` `    ``// of strings in arr1[] ` `    ``map freq; ` ` `  `    ``for` `(``int` `i = 0; i < n; i++) { ` ` `  `        ``// Sort the string ` `        ``sort(arr1[i].begin(), ` `             ``arr1[i].end()); ` ` `  `        ``// Increase its frequency ` `        ``// in the map ` `        ``freq[arr1[i]]++; ` `    ``} ` ` `  `    ``for` `(``int` `i = 0; i < m; i++) { ` ` `  `        ``// Sort the string ` `        ``sort(arr2[i].begin(), ` `             ``arr2[i].end()); ` ` `  `        ``// Display its anagrams ` `        ``// in arr1[] ` `        ``cout << freq[arr2[i]] ` `             ``<< ``" "``; ` `    ``} ` `} ` ` `  `// Driver Code ` `int` `main() ` `{ ` ` `  `    ``string arr1[] = { ``"geeks"``, ``"learn"``, ` `                      ``"for"``, ``"egeks"``, ` `                      ``"ealrn"` `}; ` `    ``int` `n = ``sizeof``(arr1) ` `            ``/ ``sizeof``(string); ` ` `  `    ``string arr2[] = { ``"kgees"``, ``"rof"``, ` `                      ``"nrael"` `}; ` `    ``int` `m = ``sizeof``(arr2) ` `            ``/ ``sizeof``(string); ` ` `  `    ``count(arr1, arr2, n, m); ` `} `

## Python3

 `# Python3 program to count the number ` `# of anagrams of each string in a  ` `# given array present in another array  ` ` `  `# Function to return the count of anagrams ` `def` `count(arr1, arr2, n, m): ` `     `  `    ``# Store the frequencies of  ` `    ``# strings in arr1 ` `    ``freq ``=` `{} ` ` `  `    ``for` `word ``in` `arr1: ` `         `  `        ``# Sort the string ` `        ``word ``=` `' '``.join(``sorted``(word)) ` ` `  `        ``# Increase its frequency ` `        ``if` `word ``in` `freq.keys(): ` `            ``freq[word] ``=` `freq[word] ``+` `1` `        ``else``: ` `            ``freq[word] ``=` `1` ` `  `    ``for` `word ``in` `arr2: ` `         `  `        ``# Sort the string ` `        ``word ``=` `' '``.join(``sorted``(word)) ` ` `  `        ``# Display its anagrams ` `        ``# in arr1 ` `        ``if` `word ``in` `freq.keys(): ` `            ``print``(freq[word], end ``=` `" "``) ` `        ``else``: ` `            ``print``(``0``, end ``=` `" "``) ` `             `  `    ``print``()      ` ` `  `# Driver Code ` `if` `__name__ ``=``=` `'__main__'``: ` `      `  `    ``arr1 ``=` `[ ``"geeks"``, ``"learn"``, ``"for"``, ` `             ``"egeks"``, ``"ealrn"` `] ` `    ``n ``=` `len``(arr1) ` `     `  `    ``arr2 ``=` `[ ``"kgees"``, ``"rof"``, ``"nrael"` `] ` `    ``m ``=` `len``(arr2) ` ` `  `    ``count(arr1, arr2, n, m) ` ` `  `# This code is contributed by Pawan_29 `

Output:

```2 1 2
```

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Improved By : Pawan_29