Given a range l – r (inclusive), count the numbers that are divisible by all of its non-zero digits.
Input : 1 9 Output : 9 Explanation: all the numbers are divisible by their digits in the range 1-9. Input : 10 20 Output : 5 Explanation: 10, 11, 12, 15, 20
1. Run a loop to generate every number from l and r.
2. Check if every non-zero digit of that number divides the number or not.
3. Keep a count of all numbers that are completely divisible by its digits.
4. Print the count of numbers.
Below is the implementation of the above approach:
- Count of numbers between range having only non-zero digits whose sum of digits is N and number is divisible by M
- Count of all even numbers in the range [L, R] whose sum of digits is divisible by 3
- Count numbers in given range such that sum of even digits is greater than sum of odd digits
- Count numbers in range 1 to N which are divisible by X but not by Y
- Count the numbers divisible by 'M' in a given range
- Count of numbers from range [L, R] that end with any of the given digits
- Count of numbers from range [L, R] whose sum of digits is Y
- Count of Numbers in Range where the number does not contain more than K non zero digits
- Count Numbers in Range with difference between Sum of digits at even and odd positions as Prime
- Sum of all numbers divisible by 6 in a given range
- Count integers in the range [A, B] that are not divisible by C and D
- N digit numbers divisible by 5 formed from the M digits
- Numbers that are not divisible by any number in the range [2, 10]
- Check if the number formed by the last digits of N numbers is divisible by 10 or not
- Count integers in a range which are divisible by their euler totient value
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Improved By : jit_t