# Count number of substrings with numeric value greater than X

Given a string ‘S’ (composed of digits) and an integer ‘X”, the task is to count all the sub-strings of ‘S’ that satisfy the following conditions:

• The sub-string must not begin with the digit ‘0’.
• And the numeric number it represents must be greater than ‘X’.

Note: Two ways of selecting a sub-string are different if they begin or end at different indices.

Examples:

```Input: S = "471", X = 47
Output: 2
Only the sub-strings "471" and "71"
satisfy the given conditions.

Input: S = "2222", X = 97
Output: 3
Valid strings are "222", "222" and "2222".
```

## Recommended: Please try your approach on {IDE} first, before moving on to the solution.

Approach:

• Iterate over each digit of the string ‘S’ and choose the digits which are greater than ‘0’.
• Now, take all possible sub-strings starting from the character chosen in the previous step and convert each sub-string to integer.
• Compare the integer from previous step to ‘X’, if the number is greater than ‘X’ then increment the count variable.
• Finally, print the value of the count variable.

Below is the implementation of the above approach:

## C++

 `// C++ implementation of the approach ` `#include ` `using` `namespace` `std; ` ` `  `// Function that counts ` `// valid sub-strings ` `int` `count(string S, ``int` `X) ` `{ ` `    ``int` `count = 0; ` `    ``const` `int` `N = S.length(); ` `    ``for` `(``int` `i = 0; i < N; ++i) { ` ` `  `        ``// Only take those numbers ` `        ``// that do not start with '0'. ` `        ``if` `(S[i] != ``'0'``) { ` `            ``for` `(``int` `len = 1; (i + len) <= N; ++len) { ` ` `  `                ``// converting the sub-string ` `                ``// starting from index 'i' ` `                ``// and having length 'len' to int ` `                ``// and checking if it is greater ` `                ``// than X or not ` `                ``if` `(stoi(S.substr(i, len)) > X) ` `                    ``count++; ` `            ``} ` `        ``} ` `    ``} ` `    ``return` `count; ` `} ` ` `  `// Driver code ` `int` `main() ` `{ ` ` `  `    ``string S = ``"2222"``; ` `    ``int` `X = 97; ` `    ``cout << count(S, X); ` ` `  `    ``return` `0; ` `} `

## Java

 `// Java implementation of the approach ` `import` `java.util.*; ` ` `  `class` `GFG ` `{ ` `// Function that counts ` `// valid sub-strings ` `static` `int` `count(String S, ``int` `X) ` `{ ` `    ``int` `count = ``0``; ` `    ``int` `N = S.length(); ` `    ``for` `(``int` `i = ``0``; i < N; ++i) ` `    ``{ ` ` `  `        ``// Only take those numbers ` `        ``// that do not start with '0'. ` `        ``if` `(S.charAt(i) != ``'0'``) ` `        ``{ ` `            ``for` `(``int` `len = ``1``;  ` `                ``(i + len) <= N; ++len)  ` `            ``{ ` ` `  `                ``// converting the sub-string ` `                ``// starting from index 'i' ` `                ``// and having length 'len' to  ` `                ``// int and checking if it is  ` `                ``// greater than X or not ` `                ``int` `num = Integer.parseInt(S.substring(i, i + len)); ` `                ``if` `(num > X) ` `                    ``count++; ` `            ``} ` `        ``} ` `    ``} ` `    ``return` `count; ` `} ` ` `  `// Driver code ` `public` `static` `void` `main(String []args) ` `{ ` `    ``String S = ``"2222"``; ` `    ``int` `X = ``97``; ` `    ``System.out.println(count(S, X)); ` `} ` `} ` ` `  `// This code is contributed by ihritik `

## Python3

 `# Python3 implementation of ` `# the approach ` ` `  `# Function that counts ` `# valid sub-strings ` `def` `countSubStr(S, X): ` ` `  `    ``cnt ``=` `0` `    ``N ``=` `len``(S) ` `     `  `    ``for` `i ``in` `range``(``0``, N): ` ` `  `        ``# Only take those numbers ` `        ``# that do not start with '0'. ` `        ``if` `(S[i] !``=` `'0'``): ` `             `  `            ``j ``=` `1` `            ``while``((j ``+` `i) <``=` `N): ` ` `  `                ``# converting the sub-string ` `                ``# starting from index 'i' ` `                ``# and having length 'len' to  ` `                ``# int and checking if it is  ` `                ``# greater than X or not ` `                ``num ``=` `int``(S[i : i ``+` `j]) ` `             `  `                ``if` `(num > X): ` `                    ``cnt ``=` `cnt ``+` `1` `                 `  `                ``j ``=` `j ``+` `1` `         `  `    ``return` `cnt; ` ` `  `# Driver code ` `S ``=` `"2222"``; ` `X ``=` `97``; ` `print``(countSubStr(S, X)) ` ` `  `# This code is contributed by ihritik `

## C#

 `// C# implementation of the approach ` `using` `System; ` ` `  `class` `GFG ` `{ ` `// Function that counts ` `// valid sub-strings ` `static` `int` `count(``string` `S, ``int` `X) ` `{ ` `    ``int` `count = 0; ` `    ``int` `N = S.Length; ` `    ``for` `(``int` `i = 0; i < N; ++i)  ` `    ``{ ` ` `  `        ``// Only take those numbers ` `        ``// that do not start with '0'. ` `        ``if` `(S[i] != ``'0'``)  ` `        ``{ ` `            ``for` `(``int` `len = 1;  ` `                ``(i + len) <= N; ++len)  ` `            ``{ ` ` `  `                ``// converting the sub-string ` `                ``// starting from index 'i' ` `                ``// and having length 'len' to int ` `                ``// and checking if it is greater ` `                ``// than X or not ` `                ``int` `num = Int32.Parse(S.Substring(i, len)); ` `                ``if` `(num > X) ` `                    ``count++; ` `            ``} ` `        ``} ` `    ``} ` `    ``return` `count; ` `} ` ` `  `// Driver code ` `public` `static` `void` `Main(String []args) ` `{ ` `    ``string` `S = ``"2222"``; ` `    ``int` `X = 97; ` `    ``Console.WriteLine(count(S, X)); ` `} ` `} ` ` `  `// This code is contributed by ihritik `

## PHP

 ` ``\$X``) ` `                    ``\$cnt``++; ` `            ``} ` `        ``} ` `    ``} ` `    ``return` `\$cnt``; ` `} ` ` `  `// Driver code ` `\$S` `= ``"2222"``; ` `\$X` `= 97; ` `echo` `countSubStr(``\$S``, ``\$X``); ` ` `  `// This code is contributed by ihritik ` `?> `

Output:

```3
```

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Improved By : ihritik