Count number of even and odd length elements in an Array

Given an array arr[] of integers of size N, the task is to find the number elements of the array having even and odd length.

Examples:

Input: arr[] = {14, 735, 3333, 223222}
Output: Number of even length elements = 3
Number of odd length elements = 1

Input: arr[] = {1121, 322, 32, 14783, 44}
Output: Number of even length elements = 3
Number of odd length elements = 2

Approach: To calculate the number of digits having even length or odd length, convert each number into a string. Then check if the length is odd or even. Finally, print the count of numbers having even length and odd length separately.



Below is the implementation of the above approach:

CPP

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// C++ program to find the count
// number of even and odd
// length elements in an Array
  
#include <bits/stdc++.h>
using namespace std;
  
// Function to find the number elements of
// the array having even length and odd.
void EvenOddLength(int arr[], int n)
{
    // Store numbers with even length
    int even = 0;
  
    for (int i = 0; i < n; i++) {
  
        // Conversion of integer to string
        string x = to_string(arr[i]);
  
        if (x.length() % 2 == 0)
            even++;
    }
  
    cout << "Number of even "
         << "length elements = "
         << even << endl;
    cout << "Number of odd "
         << "length elements = "
         << n - even << endl;
}
  
// Driver code
int main()
{
    int arr[] = { 12, 44, 213, 232, 3433 };
    int n = sizeof(arr) / sizeof(arr[0]);
  
    // Function call
    EvenOddLength(arr, n);
  
    return 0;
}

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Java

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// Java program to find the count
// number of even and odd
// length elements in an Array
import java.util.*;
class GFG{
  
// Function to find the number elements of
// the array having even length and odd.
    static void EvenOddLength(int arr[], int n)
    {
        // Store numbers with even length
        int even = 0;
      
        for (int i = 0; i < n; i++) {
      
            // Conversion of integer to string
            String x = Integer.toString(arr[i]);
      
            if (x.length() % 2 == 0)
                even++;
        }
      
        System.out.println("Number of even length elements = "+even);
        System.out.println("Number of odd length elements = "+(n - even));
    }
      
    // Driver code
    public static void main(String args[])
    {
        int arr[] = { 12, 44, 213, 232, 3433 };
        int n = arr.length;
      
        // Function call
        EvenOddLength(arr, n);
      
    }
}
  
// This code is contributed by AbhiThakur

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Python3

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# Python3 program to find the count
# number of even and odd
# length elements in an Array
  
# Function to find the number elements of
# the array having even length and odd.
def EvenOddLength(arr, n):
      
    # Store numbers with even length
    even = 0
  
    for i in range(n):
  
        # Conversion of integer to string
        x = str(arr[i])
  
        if (len(x) % 2 == 0):
            even += 1
  
    print( "Number of even length elements = ", even)
    print( "Number of odd length elements = ", n - even)
  
# Driver code
if __name__ == '__main__':
    arr= [12, 44, 213, 232, 3433]
    n = len(arr)
  
    # Function call
    EvenOddLength(arr, n)
  
# This code is contributed by mohit kumar 29

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C#

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// C# program to find the count
// number of even and odd
// length elements in an Array
using System;
  
class GFG{
   
// Function to find the number elements of
// the array having even length and odd.
    static void EvenOddLength(int []arr, int n)
    {
        // Store numbers with even length
        int even = 0;
       
        for (int i = 0; i < n; i++) {
       
            // Conversion of integer to string
            String x = arr[i].ToString();
       
            if (x.Length % 2 == 0)
                even++;
        }
       
        Console.WriteLine("Number of even length elements = "+even);
        Console.WriteLine("Number of odd length elements = "+(n - even));
    }
       
    // Driver code
    public static void Main(String []args)
    {
        int []arr = { 12, 44, 213, 232, 3433 };
        int n = arr.Length;
       
        // Function call
        EvenOddLength(arr, n);
       
    }
}
  
// This code is contributed by sapnasingh4991

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Output:

Number of even length elements = 3
Number of odd length elements = 2

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