# Count number of even and odd length elements in an Array

Given an array arr[] of integers of size N, the task is to find the number elements of the array having even and odd length.

Examples:

Input: arr[] = {14, 735, 3333, 223222}
Output: Number of even length elements = 3
Number of odd length elements = 1

Input: arr[] = {1121, 322, 32, 14783, 44}
Output: Number of even length elements = 3
Number of odd length elements = 2

## Recommended: Please try your approach on {IDE} first, before moving on to the solution.

Approach: To calculate the number of digits having even length or odd length, convert each number into a string. Then check if the length is odd or even. Finally, print the count of numbers having even length and odd length separately.

Below is the implementation of the above approach:

## CPP

 `// C++ program to find the count ` `// number of even and odd ` `// length elements in an Array ` ` `  `#include ` `using` `namespace` `std; ` ` `  `// Function to find the number elements of ` `// the array having even length and odd. ` `void` `EvenOddLength(``int` `arr[], ``int` `n) ` `{ ` `    ``// Store numbers with even length ` `    ``int` `even = 0; ` ` `  `    ``for` `(``int` `i = 0; i < n; i++) { ` ` `  `        ``// Conversion of integer to string ` `        ``string x = to_string(arr[i]); ` ` `  `        ``if` `(x.length() % 2 == 0) ` `            ``even++; ` `    ``} ` ` `  `    ``cout << ``"Number of even "` `         ``<< ``"length elements = "` `         ``<< even << endl; ` `    ``cout << ``"Number of odd "` `         ``<< ``"length elements = "` `         ``<< n - even << endl; ` `} ` ` `  `// Driver code ` `int` `main() ` `{ ` `    ``int` `arr[] = { 12, 44, 213, 232, 3433 }; ` `    ``int` `n = ``sizeof``(arr) / ``sizeof``(arr); ` ` `  `    ``// Function call ` `    ``EvenOddLength(arr, n); ` ` `  `    ``return` `0; ` `} `

## Java

 `// Java program to find the count ` `// number of even and odd ` `// length elements in an Array ` `import` `java.util.*; ` `class` `GFG{ ` ` `  `// Function to find the number elements of ` `// the array having even length and odd. ` `    ``static` `void` `EvenOddLength(``int` `arr[], ``int` `n) ` `    ``{ ` `        ``// Store numbers with even length ` `        ``int` `even = ``0``; ` `     `  `        ``for` `(``int` `i = ``0``; i < n; i++) { ` `     `  `            ``// Conversion of integer to string ` `            ``String x = Integer.toString(arr[i]); ` `     `  `            ``if` `(x.length() % ``2` `== ``0``) ` `                ``even++; ` `        ``} ` `     `  `        ``System.out.println(``"Number of even length elements = "``+even); ` `        ``System.out.println(``"Number of odd length elements = "``+(n - even)); ` `    ``} ` `     `  `    ``// Driver code ` `    ``public` `static` `void` `main(String args[]) ` `    ``{ ` `        ``int` `arr[] = { ``12``, ``44``, ``213``, ``232``, ``3433` `}; ` `        ``int` `n = arr.length; ` `     `  `        ``// Function call ` `        ``EvenOddLength(arr, n); ` `     `  `    ``} ` `} ` ` `  `// This code is contributed by AbhiThakur `

## Python3

 `# Python3 program to find the count ` `# number of even and odd ` `# length elements in an Array ` ` `  `# Function to find the number elements of ` `# the array having even length and odd. ` `def` `EvenOddLength(arr, n): ` `     `  `    ``# Store numbers with even length ` `    ``even ``=` `0` ` `  `    ``for` `i ``in` `range``(n): ` ` `  `        ``# Conversion of integer to string ` `        ``x ``=` `str``(arr[i]) ` ` `  `        ``if` `(``len``(x) ``%` `2` `=``=` `0``): ` `            ``even ``+``=` `1` ` `  `    ``print``( ``"Number of even length elements = "``, even) ` `    ``print``( ``"Number of odd length elements = "``, n ``-` `even) ` ` `  `# Driver code ` `if` `__name__ ``=``=` `'__main__'``: ` `    ``arr``=` `[``12``, ``44``, ``213``, ``232``, ``3433``] ` `    ``n ``=` `len``(arr) ` ` `  `    ``# Function call ` `    ``EvenOddLength(arr, n) ` ` `  `# This code is contributed by mohit kumar 29 `

## C#

 `// C# program to find the count ` `// number of even and odd ` `// length elements in an Array ` `using` `System; ` ` `  `class` `GFG{ ` `  `  `// Function to find the number elements of ` `// the array having even length and odd. ` `    ``static` `void` `EvenOddLength(``int` `[]arr, ``int` `n) ` `    ``{ ` `        ``// Store numbers with even length ` `        ``int` `even = 0; ` `      `  `        ``for` `(``int` `i = 0; i < n; i++) { ` `      `  `            ``// Conversion of integer to string ` `            ``String x = arr[i].ToString(); ` `      `  `            ``if` `(x.Length % 2 == 0) ` `                ``even++; ` `        ``} ` `      `  `        ``Console.WriteLine(``"Number of even length elements = "``+even); ` `        ``Console.WriteLine(``"Number of odd length elements = "``+(n - even)); ` `    ``} ` `      `  `    ``// Driver code ` `    ``public` `static` `void` `Main(String []args) ` `    ``{ ` `        ``int` `[]arr = { 12, 44, 213, 232, 3433 }; ` `        ``int` `n = arr.Length; ` `      `  `        ``// Function call ` `        ``EvenOddLength(arr, n); ` `      `  `    ``} ` `} ` ` `  `// This code is contributed by sapnasingh4991 `

Output:

```Number of even length elements = 3
Number of odd length elements = 2
```

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