Given two integers A and B, the task is to count the number of bits needed to be flipped to convert A to B.
Input: A = 10, B = 7
binary(10) = 1010
binary(7) = 0111
3 bits need to be flipped.
Input: A = 8, B = 7
Approach: An approach to solve this problem has already been discussed here. Here, the count of bits that need to be flipped can be found by matching all the bits in both the integers one by one. If the bit under consideration differs then increment the count.
Below is the implementation of the above approach:
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- Count number of bits to be flipped to convert A to B
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- Minimize bits to be flipped in X and Y such that their Bitwise OR is equal to Z
- Count of 0s to be flipped to make any two adjacent 1s at least K 0s apart
- Check if the number is valid when flipped upside down
- Maximum number of 0s that can be flipped such that Array has no adjacent 1s
- Check if bits of a number has count of consecutive set bits in increasing order
- Toggle bits of a number except first and last bits
- Print numbers having first and last bits as the only set bits
- Check if all bits can be made same by flipping two consecutive bits
- Program to count number of set bits in an (big) array
- Count total bits in a number
- Count unset bits of a number
- Count number of bits changed after adding 1 to given N
- Count pairs (A, B) such that A has X and B has Y number of set bits and A+B = C
- Count number of set bits in a range using bitset
- Count pairs of elements such that number of set bits in their AND is B[i]
- Count Set-bits of number using Recursion
- Find a number X such that (X XOR A) is minimum and the count of set bits in X and B are equal
- Count of pairs in an Array with same number of set bits
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