Given two integers A and B, the task is to count the number of bits needed to be flipped to convert A to B.
Input: A = 10, B = 7
binary(10) = 1010
binary(7) = 0111
3 bits need to be flipped.
Input: A = 8, B = 7
Approach: An approach to solve this problem has already been discussed here. Here, the count of bits that need to be flipped can be found by matching all the bits in both the integers one by one. If the bit under consideration differs then increment the count.
Below is the implementation of the above approach:
- Count number of bits to be flipped to convert A to B
- Check if bits of a number has count of consecutive set bits in increasing order
- Count unset bits of a number
- Count Set-bits of number using Recursion
- Count pairs (A, B) such that A has X and B has Y number of set bits and A+B = C
- Count total bits in a number
- Count pairs of elements such that number of set bits in their AND is B[i]
- Count number of set bits in a range using bitset
- Program to count number of set bits in an (big) array
- Count number of bits changed after adding 1 to given N
- Find a number X such that (X XOR A) is minimum and the count of set bits in X and B are equal
- Check if the number is valid when flipped upside down
- Toggle bits of a number except first and last bits
- Count set bits in a range
- Count set bits in an integer
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