Given an integer . The task is to find the number of bits changed after adding 1 to the given number.
Input : N = 5 Output : 2 After adding 1 to 5 it becomes 6. Binary representation of 5 is 101. Binary representation of 6 is 110. So, no. of bits changed is 2. Input : N = 1 Output : 2
There are three approaches to find the number of changed bits in the result obtained after adding 1 to the given value N:
- Approach 1: Add 1 to given integer and compare the bits of N and the result obtained after addition and count the number of unmatched bit.
- Approach 2: In case if 1 is added to N, then the total number of bits changed is defined by the position of 1st Zero from right i.e. LSB as zero. In the case, 1 is added to 1 then it got changed and pass a carry 1 to its next bit but if 1 is added to 0 only 0 changes to 1 and no further carry is passed.
- Approach 3: For finding number of changed bits when 1 is added to a given number take XOR of n and n+1 and calculate the number of set bits in the resultant XOR value.
Below is the implementation of the Approach 3:
# Python 3 program to find the number
# of changed bit
# Function to find number of changed bit
# Calculate xor of n and n+1
XOR = n ^ (n + 1)
# Count set bits in xor value
result = bin(XOR).count(“1”)
# Return the result
# Driver Code
if __name__ == ‘__main__’:
n = 6
n = 7
# This code is contributed by
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- Python | Count set bits in a range
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Improved By : SURENDRA_GANGWAR