# Count number of bits changed after adding 1 to given N

Given an integer . The task is to find the number of bits changed after adding 1 to the given number.

**Examples**:

Input: N = 5Output: 2 After adding 1 to 5 it becomes 6. Binary representation of 5 is 101. Binary representation of 6 is 110. So, no. of bits changed is 2.Input: N = 1Output: 2

There are three approaches to find the number of changed bits in the result obtained after adding 1 to the given value N:

**Approach 1:**Add 1 to given integer and compare the bits of N and the result obtained after addition and count the number of unmatched bit.**Approach 2:**In case if 1 is added to N, then the total number of bits changed is defined by the position of 1st Zero from right i.e. LSB as zero. In the case, 1 is added to 1 then it got changed and pass a carry 1 to its next bit but if 1 is added to 0 only 0 changes to 1 and no further carry is passed.**Approach 3:**For finding number of changed bits when 1 is added to a given number take XOR of n and n+1 and calculate the number of set bits in the resultant XOR value.

Below is the implementation of the **Approach 3**:

## C++

`// CPP program to find the number ` `// of changed bit ` `#include <bits/stdc++.h> ` `using` `namespace` `std; ` ` ` `// Function to find number of changed bit ` `int` `findChangedBit(` `int` `n) ` `{ ` ` ` `// Calculate xor of n and n+1 ` ` ` `int` `XOR = n ^ (n + 1); ` ` ` ` ` `// Count set bits in xor value ` ` ` `int` `result = __builtin_popcount(XOR); ` ` ` ` ` `// Return the result ` ` ` `return` `result; ` `} ` ` ` `// Driver function ` `int` `main() ` `{ ` ` ` `int` `n = 6; ` ` ` `cout << findChangedBit(n) << endl; ` ` ` ` ` `n = 7; ` ` ` `cout << findChangedBit(n); ` ` ` ` ` `return` `0; ` `} ` |

*chevron_right*

*filter_none*

## Python3

# Python 3 program to find the number

# of changed bit

# Function to find number of changed bit

def findChangedBit(n):

# Calculate xor of n and n+1

XOR = n ^ (n + 1)

# Count set bits in xor value

result = bin(XOR).count(“1”)

# Return the result

return result

# Driver Code

if __name__ == ‘__main__’:

n = 6

print(findChangedBit(n))

n = 7

print(findChangedBit(n))

# This code is contributed by

# Surendra_Gangwar

**Output:**

1 4

## Recommended Posts:

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- Check if bits of a number has count of consecutive set bits in increasing order
- Count pairs (A, B) such that A has X and B has Y number of set bits and A+B = C
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- Count total bits in a number
- Count number of bits to be flipped to convert A to B
- Program to count number of set bits in an (big) array
- Toggle bits of a number except first and last bits
- Count set bits in an integer
- Count set bits in a range
- Range query for count of set bits
- Count total set bits in all numbers from 1 to n
- Count unset bits in a range
- Python | Count set bits in a range
- Sort an array according to count of set bits | Set 2

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