# Count number of even and odd elements in an array

For the given array of integers, count even and odd elements.

Examples:

```Input:
int arr = {2, 3, 4, 5, 6}
Output:
Number of even elements = 3
Number of odd elements = 2

Input:
int arr = {22, 32, 42, 52, 62}
Output:
Number of even elements = 5
Number of odd elements = 0
```

Solution:
We can also check if a number is odd or even

• By doing AND of 1 and that digit, if the result comes out to be 1 then the number is odd otherwise even.
• By its divisibility by 2. A number is said to be odd if it is not divisible by 2, otherwise its even.

Here, we will check if a number is odd, then we will increment the odd counter otherwise we will increment the even counter.

Below is the implementation of the above approach:

## C++

 `// CPP program to count number of even` `// and odd elements in an array` `#include ` `using` `namespace` `std;`   `void` `CountingEvenOdd(``int` `arr[], ``int` `arr_size)` `{` `    ``int` `even_count = 0;` `    ``int` `odd_count = 0;`   `    ``// loop to read all the values in the array` `    ``for` `(``int` `i = 0; i < arr_size; i++) {` `        `  `          ``// checking if a number is completely` `        ``// divisible by 2` `        ``if` `(arr[i] & 1 == 1)` `            ``odd_count++;` `        ``else` `            ``even_count++;` `    ``}`   `    ``cout << ``"Number of even elements = "` `<< even_count` `         ``<< ``"\nNumber of odd elements = "` `<< odd_count;` `}`   `// Driver Code` `int` `main()` `{` `    ``int` `arr[] = { 2, 3, 4, 5, 6 };` `    ``int` `n = ``sizeof``(arr) / ``sizeof``(arr);` `      `  `      ``// Function Call` `    ``CountingEvenOdd(arr, n);` `}`

## Java

 `// JAVA program to count number of even` `// and odd elements in an array` `import` `java.io.*;`   `class` `GFG {`   `    ``static` `void` `CountingEvenOdd(``int` `arr[], ``int` `arr_size)` `    ``{` `        ``int` `even_count = ``0``;` `        ``int` `odd_count = ``0``;`   `        ``// loop to read all the values in` `        ``// the array` `        ``for` `(``int` `i = ``0``; i < arr_size; i++) {` `            `  `              ``// checking if a number is` `            ``// completely divisible by 2` `            ``if` `((arr[i] & ``1``) == ``1``)` `                ``odd_count++;` `            ``else` `                ``even_count++;` `        ``}`   `        ``System.out.println(``"Number of even"` `                           ``+ ``" elements = "` `+ even_count` `                           ``+ ``" Number of odd elements = "` `                           ``+ odd_count);` `    ``}`   `    ``// Driver Code` `    ``public` `static` `void` `main(String[] args)` `    ``{` `        ``int` `arr[] = { ``2``, ``3``, ``4``, ``5``, ``6` `};` `        ``int` `n = arr.length;` `          `  `          ``// Function Call` `        ``CountingEvenOdd(arr, n);` `    ``}` `}`   `// This code is Contributed by anuj_67.`

## Python3

 `# Python3 program to count number of` `# even and odd elements in an array`     `def` `CountingEvenOdd(arr, arr_size):` `    ``even_count ``=` `0` `    ``odd_count ``=` `0`   `    ``# loop to read all the values` `    ``# in the array` `    ``for` `i ``in` `range``(arr_size):`   `        ``# checking if a number is` `        ``# completely divisible by 2` `        ``if` `(arr[i] & ``1` `=``=` `1``):` `            ``odd_count ``+``=` `1` `        ``else``:` `            ``even_count ``+``=` `1`   `    ``print``(``"Number of even elements = "``,` `          ``even_count)` `    ``print``(``"Number of odd elements = "``,` `          ``odd_count)`     `# Driver Code` `arr ``=` `[``2``, ``3``, ``4``, ``5``, ``6``]` `n ``=` `len``(arr)`   `# Function Call` `CountingEvenOdd(arr, n)`   `# This code is contributed by sahishelangia`

## C#

 `// C# program to count number of even` `// and odd elements in an array` `using` `System;`   `class` `GFG {`   `    ``static` `void` `CountingEvenOdd(``int``[] arr, ``int` `arr_size)` `    ``{` `        ``int` `even_count = 0;` `        ``int` `odd_count = 0;`   `        ``// loop to read all the values in` `        ``// the array` `        ``for` `(``int` `i = 0; i < arr_size; i++) {` `            `  `              ``// checking if a number is` `            ``// completely divisible by 2` `            ``if` `((arr[i] & 1) == 1)` `                ``odd_count++;` `            ``else` `                ``even_count++;` `        ``}`   `        ``Console.WriteLine(``"Number of even"` `                          ``+ ``" elements = "` `+ even_count` `                          ``+ ``" Number of odd elements = "` `                          ``+ odd_count);` `    ``}`   `    ``// Driver Code` `    ``public` `static` `void` `Main()` `    ``{` `        ``int``[] arr = { 2, 3, 4, 5, 6 };` `        ``int` `n = arr.Length;` `      `  `          ``// Function Call` `        ``CountingEvenOdd(arr, n);` `    ``}` `}`   `// This code is Contributed by anuj_67.`

## PHP

 ``

Output

```Number of even elements = 3
Number of odd elements = 2```

Time Complexity: O(n)

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