# Count number of even and odd elements in an array

For the given array of integers, count even and odd elements.

Examples:

```Input : int arr = {2, 3, 4, 5, 6}
Output : Number of even elements = 3
Number of odd elements = 2

Input : int arr = {22, 32, 42, 52, 62}
Output : Number of even elements = 5
Number of odd elements = 0
```

## Recommended: Please try your approach on {IDE} first, before moving on to the solution.

Simple approach: A number is said to be Even if it is completely divisible by 2. A number is said to be Odd if it is leaves 1 as remainder on dividing by 2.

Other approach: We can also check if a number is odd by doing AND of 1 and that digit, if the result comes out to be 1 then the number is odd otherwise even.

Here, we will check if a number is odd , then we will increment the odd
counter otherwise we will increment the even counter.

## C++

 `// CPP program to count number of even ` `// and odd elements in an array ` `#include ` `using` `namespace` `std; ` ` `  `void` `CountingEvenOdd(``int` `arr[], ``int` `arr_size) ` `{ ` `    ``int` `even_count = 0;              ` `    ``int` `odd_count = 0;              ` `         `  `    ``// loop to read all the values in the array ` `    ``for``(``int` `i = 0 ; i < arr_size ; i++)  ` `    ``{ ` `        ``// checking if a number is completely ` `        ``// divisible by 2 ` `        ``if` `(arr[i] & 1 == 1) ` `            ``odd_count ++ ;          ` `        ``else`                      `            ``even_count ++ ;          ` `    ``} ` ` `  `    ``cout << ``"Number of even elements = "` `<< even_count  ` `         ``<< ``"\nNumber of odd elements = "` `<< odd_count ;          ` `} ` ` `  `// Driver Code ` `int` `main() ` `{ ` `    ``int` `arr[] = {2, 3, 4, 5, 6}; ` `    ``int` `n = ``sizeof``(arr) / ``sizeof``(arr); ` `    ``CouningEvenOdd(arr, n); ` `}  `

## Java

 `// java program to count number of even ` `// and odd elements in an array ` `import` `java.io.*; ` ` `  `class` `GFG { ` ` `  `    ``static` `void` `CountingEvenOdd(``int` `arr[], ` `                              ``int` `arr_size) ` `    ``{ ` `        ``int` `even_count = ``0``;          ` `        ``int` `odd_count = ``0``;          ` `             `  `        ``// loop to read all the values in ` `        ``// the array ` `        ``for``(``int` `i = ``0` `; i < arr_size ; i++)  ` `        ``{ ` `            ``// checking if a number is  ` `            ``// completely divisible by 2 ` `            ``if` `((arr[i] & ``1``) == ``1``) ` `                ``odd_count ++ ;      ` `            ``else`                 `                ``even_count ++ ;      ` `        ``} ` `     `  `        ``System.out.println( ``"Number of even"` `               ``+ ``" elements = "` `+ even_count  ` `               ``+ ``" Number of odd elements = "` `                              ``+ odd_count) ;      ` `    ``} ` `     `  `    ``// Driver Code ` `    ``public` `static` `void` `main (String[] args)  ` `    ``{ ` `        ``int` `arr[] = {``2``, ``3``, ``4``, ``5``, ``6``}; ` `        ``int` `n = arr.length; ` `        ``CountingEvenOdd(arr, n); ` `    ``} ` `} ` ` `  `// This code is Contributed by anuj_67. `

## Python3

 `# Python3 program to count number of  ` `# even and odd elements in an array  ` `def` `CountingEvenOdd(arr, arr_size):  ` `    ``even_count ``=` `0`             `    ``odd_count ``=` `0`             `         `  `    ``# loop to read all the values  ` `    ``# in the array  ` `    ``for` `i ``in` `range``(arr_size):  ` `         `  `        ``# checking if a number is  ` `        ``# completely divisible by 2  ` `        ``if` `(arr[i] & ``1` `=``=` `1``):  ` `            ``odd_count ``+``=` `1`         `        ``else``:                      ` `            ``even_count ``+``=` `1` ` `  `    ``print``(``"Number of even elements = "``, ` `                            ``even_count) ` `    ``print``(``"Number of odd elements = "` `,  ` `                             ``odd_count)  ` `                     `  `# Driver Code ` `arr ``=` `[``2``, ``3``, ``4``, ``5``, ``6``]  ` `n ``=` `len``(arr)  ` `CountingEvenOdd(arr, n) ` ` `  `# This code is contributed by sahishelangia `

## C#

 `// C# program to count number of even ` `// and odd elements in an array ` `using` `System; ` ` `  `class` `GFG { ` ` `  `    ``static` `void` `CountingEvenOdd(``int` `[]arr, ` `                            ``int` `arr_size) ` `    ``{ ` `        ``int` `even_count = 0;          ` `        ``int` `odd_count = 0;          ` `             `  `        ``// loop to read all the values in ` `        ``// the array ` `        ``for``(``int` `i = 0 ; i < arr_size ; i++)  ` `        ``{ ` `            ``// checking if a number is  ` `            ``// completely divisible by 2 ` `            ``if` `((arr[i] & 1) == 1) ` `                ``odd_count ++ ;      ` `            ``else`             `                ``even_count ++ ;      ` `        ``} ` `     `  `        ``Console.WriteLine( ``"Number of even"` `            ``+ ``" elements = "` `+ even_count  ` `            ``+ ``" Number of odd elements = "` `                            ``+ odd_count) ;      ` `    ``} ` `     `  `    ``// Driver Code ` `    ``public` `static` `void` `Main ()  ` `    ``{ ` `        ``int` `[]arr = {2, 3, 4, 5, 6}; ` `        ``int` `n = arr.Length; ` `        ``CountingEvenOdd(arr, n); ` `    ``} ` `} ` ` `  `// This code is Contributed by anuj_67. `

## PHP

 ` `

Output:

```Number of even elements = 3   Number of odd elements = 2
```

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