Given a linked list containing duplicate elements. The task is to find the count of all minimum occurring elements in the given linked list. That is the count of all such elements whose frequency is minimum in the matrix.
Input : 1-> 2-> 2-> 3 Output : 2 Explanation: 1 and 3 are elements occurs only one time. So, count is 2. Input : 10-> 20-> 20-> 10-> 30 Output : 1
- Traverse the linked list and use a hash table to store the frequency of elements of the linked list such that the key of map is the linked list element and value is its frequency in the linked list.
- Then traverse the hash table to find the minimum frequency.
- Finally, traverse the hash table to find the frequency of elements and check if it matches with the minimum frequency obtained in previous step, if yes, then add this frequency to count.
Below is the implementation of the above approach:
Time Complexity : O(n)
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- Sum of all minimum frequency elements in Matrix
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- Find unique elements in linked list
- Pairwise swap elements of a given linked list
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- Replace each node with its Surpasser Count in Linked List
- Minimum and Maximum Prime Numbers of a Singly Linked List
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Improved By : Vikash Kumar 37