Given a linked list containing duplicate elements. The task is to find the count of all minimum occurring elements in the given linked list. That is the count of all such elements whose frequency is minimum in the matrix.
Input : 1-> 2-> 2-> 3 Output : 2 Explanation: 1 and 3 are elements occurs only one time. So, count is 2. Input : 10-> 20-> 20-> 10-> 30 Output : 1
- Traverse the linked list and use a hash table to store the frequency of elements of the linked list such that the key of map is the linked list element and value is its frequency in the linked list.
- Then traverse the hash table to find the minimum frequency.
- Finally, traverse the hash table to find the frequency of elements and check if it matches with the minimum frequency obtained in previous step, if yes, then add this frequency to count.
Below is the implementation of the above approach:
Time Complexity : O(n)
- Find minimum and maximum elements in singly Circular Linked List
- Sum of all odd frequency nodes of the Linked List
- Sum of all minimum frequency elements in Matrix
- Partitioning a linked list around a given value and If we don't care about making the elements of the list "stable"
- Count duplicates in a given linked list
- Reverse first K elements of given linked list
- Count nodes in Circular linked list
- Sum of smaller elements of nodes in a linked list
- Find unique elements in linked list
- Pairwise swap elements of a given linked list
- Count rotations in sorted and rotated linked list
- Replace each node with its Surpasser Count in Linked List
- Count of Prime Nodes of a Singly Linked List
- Maximum and Minimum element of a linked list which is divisible by a given number k
- Minimum and Maximum Prime Numbers of a Singly Linked List
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Improved By : Vikash Kumar 37