Related Articles

# Count and Print the alphabets having ASCII value not in the range [l, r]

• Last Updated : 26 May, 2021

Given a string str, the task is to count the number of alphabets having ASCII values, not in the range [l, r].
Examples:

```Input: str = "geeksforgeeks", l = 102, r = 111
Output: Count = 7
Characters - e, s, r have ascii values not in the range [102, 111].

Input: str = "GeEkS", l = 80, r = 111
Output: Count = 2```

Attention reader! Don’t stop learning now. Get hold of all the important DSA concepts with the DSA Self Paced Course at a student-friendly price and become industry ready.  To complete your preparation from learning a language to DS Algo and many more,  please refer Complete Interview Preparation Course.

In case you wish to attend live classes with experts, please refer DSA Live Classes for Working Professionals and Competitive Programming Live for Students.

Approach: Start traversing the string and check if the current character has ASCII value less than equal to r and greater than equal to l. If no then increment the count and print that element.
Below is the implementation of above approach:

## C++

 `// C++ implementation of the above approach``#include ``using` `namespace` `std;` `// Function to count the number of characters``// whose ascii value not in range [l, r]``int` `CountCharacters(string str, ``int` `l, ``int` `r)``{``    ``// Initializing the count to 0``    ``int` `cnt = 0;` `    ``// using map to print a character only once``    ``unordered_map<``char``, ``int``> m;``    ``int` `len = str.length();``    ``for` `(``int` `i = 0; i < len; i++) {` `        ``// Increment the count``        ``// if the value is less``        ``if` `(!(l <= str[i] and str[i] <= r)) {``            ``cnt++;``            ``if` `(m[str[i]] != 1) {``                ``cout << str[i] << ``" "``;``            ``m[str[i]]++;``            ``}``        ``}``    ``}``    ``// return the count``    ``return` `cnt;``}` `// Driver code``int` `main()``{``    ``string str = ``"geeksforgeeks"``;``    ``int` `l = 102, r = 111;` `    ``cout << ``"Characters with ASCII values"``            ``" not in the range [l, r] \nin the given string are: "``;``    ``cout << ``"\nand their count is "` `<< CountCharacters(str, l, r);` `    ``return` `0;``}`

## Java

 `// Java implementation of the above approach``import` `java.util.*;``class` `Solution``{``  ` `// Function to count the number of characters``// whose ascii value not in range [l, r]``static` `int` `CountCharacters(String str, ``int` `l, ``int` `r)``{``    ``// Initializing the count to 0``    ``int` `cnt = ``0``;``  ` `    ``// using map to print a character only once``    ``Map m= ``new` `HashMap();``    ``int` `len = str.length();``    ``for` `(``int` `i = ``0``; i < len; i++) {``  ` `        ``// Increment the count``        ``// if the value is less``        ``if` `(!(l <= str.charAt(i) && str.charAt(i) <= r)) {``            ``cnt++;``            ``if``(m.get(str.charAt(i))!=``null``)``            ``if` `(m.get(str.charAt(i)) != ``1``) {``                ``System.out.print(str.charAt(i) + ``" "``);``            ``m.put(str.charAt(i),m.get(str.charAt(i))==``null``?``0``:m.get(str.charAt(i))+``1``);``            ``}``        ``}``    ``}``    ``// return the count``    ``return` `cnt;``}``  ` `// Driver code``public` `static` `void` `main(String args[])``{``    ``String str = ``"geeksforgeeks"``;``    ``int` `l = ``102``, r = ``111``;``  ` `    ``System.out.println( ``"Characters with ASCII values not in the range [l, r] \nin the given string are: "``);``     ``System.out.println(  ``"\nand their count is "` `+ CountCharacters(str, l, r));``  ` `}``}``//contributed by Arnab Kundu`

## Python3

 `# Python3 implementation of the``# above approach` `# Function to count the number of``# characters whose ascii value not``# in range [l, r]``def` `CountCharacters(``str``, l, r):` `    ``# Initializing the count to 0``    ``cnt ``=` `0` `    ``# using map to pra character``    ``# only once``    ``m ``=` `{}``    ``length ``=` `len``(``str``)``    ``for` `i ``in` `range``(``0``, length):``        ` `        ``# Increment the count if the``        ``# value is less``        ``if` `(``not``(l <``=` `ord``(``str``[i]) ``and``                     ``ord``(``str``[i]) <``=` `r)):``            ``cnt ``+``=` `1``            ``if` `ord``(``str``[i]) ``not` `in` `m:``                ``m[``ord``(``str``[i])] ``=` `0``                ``print``(``str``[i], end ``=` `" "``)``            ``m[``ord``(``str``[i])] ``+``=` `1``            ` `    ``# return the count``    ``return` `cnt` `# Driver Code``if` `__name__ ``=``=` `'__main__'``:` `    ``str` `=` `"geeksforgeeks"``    ``str` `=` `str``.strip()``    ``l ``=` `102``    ``r ``=` `111``    ``print``(``"Characters with ASCII values"``, end ``=` `"")``    ``print``(``" not in the range [l, r]\n"``,``          ``"in the given string are: "``, end ``=` `"")``    ``print``(``"\nand their count is "``,``            ``CountCharacters(``str``, l, r))` `# This code is contributed by``# Shubham Singh(SHUBHAMSINGH10)`

## C#

 `// C# implementation of the above approach``using` `System;``using` `System.Collections;``using` `System.Collections.Generic;` `class` `GFG``{``   ` `// Function to count the number of characters``// whose ascii value not in range [l, r]``static` `int` `CountCharacters(``string` `str, ``int` `l, ``int` `r)``{``  ` `    ``// Initializing the count to 0``    ``int` `cnt = 0;``   ` `    ``// using map to print a character only once``    ``Dictionary<``char``, ``int``> m = ``new` `Dictionary<``char``, ``int``>();``    ``int` `len = str.Length;``    ``for` `(``int` `i = 0; i < len; i++)``    ``{``   ` `        ``// Increment the count``        ``// if the value is less``        ``if` `(!(l <= str[i] && str[i] <= r))``        ``{``            ``cnt++;``            ``if``(!m.ContainsKey(str[i]))``            ``{``                ``m[str[i]] = 0;``                ``Console.Write(str[i] + ``" "``);``            ``}``            ``m[str[i]]++;``        ``}``    ``}``  ` `    ``// return the count``    ``return` `cnt;``}``   ` `// Driver code``public` `static` `void` `Main(``string` `[]args)``{``    ``string` `str = ``"geeksforgeeks"``;``    ``int` `l = 102, r = 111;   ``    ``Console.Write( ``"Characters with ASCII values"` `+``                  ``"not in the range [l, r] \nin"` `+``                  ``"the given string are: "``);``     ``Console.WriteLine( ``"\nand their count is "` `+``                       ``CountCharacters(str, l, r));``}``}` `// This code is contributed by rutvik_56`

## PHP

 ``

## Javascript

 ``
Output:
```Characters with ASCII values not in the range [l, r]
in the given string are: e s r
and their count is 7```

Time Complexity: O(n) where n is the length of string.

My Personal Notes arrow_drop_up