Given two numbers x and y, and a range [l, r] where 1 <= l, r <= 32. The task is consider set bits of y in range [l, r] and set these bits in x also. Examples :

Input : x = 10, y = 13, l = 2, r = 3 Output : x = 14 Binary representation of 10 is 1010 and that of y is 1101. There is one set bit in y at 3’rd position (in given range). After we copy this bit to x, x becomes 1110 which is binary representation of 14. Input : x = 8, y = 7, l = 1, r = 2 Output : x = 11

Source : D E Shaw Interview

**Method 1 (One by one copy bits)**

We can one by one find set bits of y by traversing given range. For every set bit, we OR it to existing bit of x, so that the becomes set in x, if it was not set. Below is C++ implementation.

`// C++ program to rearrange array in alternating ` `// C++ program to copy set bits in a given ` `// range [l, r] from y to x. ` `#include <bits/stdc++.h> ` `using` `namespace` `std; ` ` ` `// Copy set bits in range [l, r] from y to x. ` `// Note that x is passed by reference and modified ` `// by this function. ` `void` `copySetBits(unsigned &x, unsigned y, ` ` ` `unsigned l, unsigned r) ` `{ ` ` ` `// l and r must be between 1 to 32 ` ` ` `// (assuming ints are stored using ` ` ` `// 32 bits) ` ` ` `if` `(l < 1 || r > 32) ` ` ` `return` `; ` ` ` ` ` `// Travers in given range ` ` ` `for` `(` `int` `i=l; i<=r; i++) ` ` ` `{ ` ` ` `// Find a mask (A number whose ` ` ` `// only set bit is at i'th position) ` ` ` `int` `mask = 1 << (i-1); ` ` ` ` ` `// If i'th bit is set in y, set i'th ` ` ` `// bit in x also. ` ` ` `if` `(y & mask) ` ` ` `x = x | mask; ` ` ` `} ` `} ` ` ` `// Driver code ` `int` `main() ` `{ ` ` ` `unsigned x = 10, y = 13, l = 2, r = 3; ` ` ` `copySetBits(x, y, l, r); ` ` ` `cout << ` `"Modified x is "` `<< x; ` ` ` `return` `0; ` `} ` |

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Output :

Modified x is 14

**Method 2 (Copy all bits using one bit mask)**

`// C++ program to copy set bits in a given ` `// range [l, r] from y to x. ` `#include <bits/stdc++.h> ` `using` `namespace` `std; ` ` ` `// Copy set bits in range [l, r] from y to x. ` `// Note that x is passed by reference and modified ` `// by this function. ` `void` `copySetBits(unsigned &x, unsigned y, ` ` ` `unsigned l, unsigned r) ` `{ ` ` ` `// l and r must be between 1 to 32 ` ` ` `if` `(l < 1 || r > 32) ` ` ` `return` `; ` ` ` ` ` `// get the length of the mask ` ` ` `int` `maskLength = (1<<(r-l+1)) - 1; ` ` ` ` ` `// Shift the mask to the required position ` ` ` `// "&" with y to get the set bits at between ` ` ` `// l ad r in y ` ` ` `int` `mask = ((maskLength)<<(l-1)) & y ; ` ` ` `x = x | mask; ` `} ` ` ` `// Driver code ` `int` `main() ` `{ ` ` ` `unsigned x = 10, y = 13, l = 2, r = 3; ` ` ` `copySetBits(x, y, l, r); ` ` ` `cout << ` `"Modified x is "` `<< x; ` ` ` `return` `0; ` `} ` |

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Output :

Modified x is 14

Thanks to Ashish Rathi for suggesting this solution in a comment.

This article is contributed by **Rishi**. Please write comments if you find anything incorrect, or you want to share more information about the topic discussed above

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