# Convert numbers into binary representation and add them without carry

Given two numbers N and M. The task to convert both the numbers in the binary form then add respective bits of both the binary converted numbers but with a given condition that there is not any carry system in this addition.

```Input: N = 37, M = 12
Output: 41

Input: N = 456, M = 854
Output: 670
```

## Recommended: Please try your approach on {IDE} first, before moving on to the solution.

Approach:

• If we don’t consider carry then the binary addition of two bits will be:

```    1 + 0 = 1
0 + 1 = 1
0 + 0 = 0
1 + 1 = 0 (No carry)
```
• If you observe clearly you will notice that this is just bitwise XOR of two numbers.

Below is the implementation of the above approach

## C++

 `// C++ program to add two binary ` `// number without carry ` `#include ` `using` `namespace` `std; ` ` `  `// Function returns sum of both  ` `// the binary number without ` `// carry ` `int` `NoCarrySum(``int` `N, ``int` `M) ` `{ ` `    ``// XOR of N and M ` `    ``return` `N ^ M; ` `} ` `     `  `// Driver code ` `int` `main() ` `{ ` `    ``int` `N = 37; ` `    ``int` `M = 12; ` `     `  `    ``cout << NoCarrySum(N, M); ` `    ``return` `0; ` `} `

## Java

 `// Java program to add two binary ` `// number without carry ` `import` `java.util.*; ` ` `  `class` `GFG{ ` ` `  `// Function returns sum of both  ` `// the binary number without ` `// carry ` `static` `int` `NoCarrySum(``int` `N, ``int` `M) ` `{ ` `    ``// XOR of N and M ` `    ``return` `N ^ M; ` `} ` `     `  `// Driver code ` `public` `static` `void` `main(String[] args) ` `{ ` `    ``int` `N = ``37``; ` `    ``int` `M = ``12``; ` `    ``System.out.print(NoCarrySum(N, M)); ` `} ` `} ` ` `  `// This code is contributed by amal kumar choubey `

## Python3

 `# Python3 program to add two binary  ` `# number without carry  ` ` `  `# Function returns sum of both  ` `# the binary number without  ` `# carry  ` `def` `NoCarrySum(N, M):  ` ` `  `    ``# XOR of N and M  ` `    ``return` `N ^ M ` ` `  `# Driver code  ` `N ``=` `37` `M ``=` `12` `print``(NoCarrySum(N, M))  ` ` `  `# This code is contributed by sayesha  `

## C#

 `// C# program to add two binary ` `// number without carry ` `using` `System; ` ` `  `class` `GFG{ ` ` `  `// Function returns sum of both  ` `// the binary number without ` `// carry ` `static` `int` `NoCarrySum(``int` `N, ``int` `M) ` `{ ` `     `  `    ``// XOR of N and M ` `    ``return` `N ^ M; ` `} ` `     `  `// Driver code ` `static` `public` `void` `Main(String[] args) ` `{ ` `    ``int` `N = 37; ` `    ``int` `M = 12; ` `    ``Console.Write(NoCarrySum(N, M)); ` `} ` `} ` ` `  `// This code is contributed by Rajput-Ji `

Output:

```41
```

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